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Spring静态资源servlet请求
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Stack Overflow用户
提问于 2012-05-02 00:19:17
回答 2查看 6.1K关注 0票数 0

我英语不好。请理解它。

我负责维护一个由Spring、tiles和ib提斯框架构建的网站。

所有的问题都是gif,js等等.通过DispatcherServlet,因为大多数静态资源的地址都与/home/images/hbg_01.gif.类似资源路径由homeServlet映射。

但是,我希望用Web.xml编写的任何Dispatcher servlet忽略我的静态资源。

我是J2EE的新手。所以如果缺乏信息的话。请留下评论。如果需要的话我会给你任何东西

这是我的web.xml

代码语言:javascript
复制
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
                      http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
    version="3.0" metadata-complete="true">

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>
            /WEB-INF/xml/root-context.xml
            /WEB-INF/xml/security.xml
        </param-value>
    </context-param>


    <!-- Processes application requests -->
    <servlet>
        <servlet-name>appServlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/xml/appServlet/servlet-context.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>appServlet</servlet-name>
        <url-pattern>/app/*</url-pattern>
    </servlet-mapping>

    <servlet>
        <servlet-name>adminServlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/xml/adminServlet/servlet-context.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>adminServlet</servlet-name>
        <url-pattern>/admin/*</url-pattern>
    </servlet-mapping>

    <servlet>
        <servlet-name>homeServlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/xml/homeServlet/servlet-context.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>homeServlet</servlet-name>
        <url-pattern>/home/*</url-pattern>
    </servlet-mapping>


    <servlet>
        <servlet-name>monitorServlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/xml/monitorServlet/servlet-context.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>monitorServlet</servlet-name>
        <url-pattern>/monitor/*</url-pattern>
    </servlet-mapping>


    <servlet>
        <servlet-name>monitorDemoServlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/xml/monitorDemoServlet/servlet-context.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>monitorDemoServlet</servlet-name>
        <url-pattern>/monitor_demo/*</url-pattern>
    </servlet-mapping>


    <servlet>
        <servlet-name>projectServlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/xml/projectServlet/servlet-context.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>projectServlet</servlet-name>
        <url-pattern>/project/*</url-pattern>
    </servlet-mapping>


    <context-param>
        <param-name>log4jConfigLocation</param-name>
        <param-value>/WEB-INF/log4j.properties</param-value>
    </context-param>

    <listener>
        <listener-class>org.springframework.web.util.Log4jConfigListener</listener-class>
    </listener>
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>


    <filter>
        <description></description>
        <display-name>encodingFilter</display-name>
        <filter-name>encodingFilter</filter-name>
        <filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
        <init-param>
            <param-name>encoding</param-name>
            <param-value>EUC-KR</param-value>
        </init-param>
       <init-param>
            <param-name>forceEncoding</param-name>
            <param-value>true</param-value>
       </init-param>
    </filter>

    <filter-mapping>
        <filter-name>encodingFilter</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>



    <filter>
        <filter-name>springSecurityFilterChain</filter-name>
        <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
    </filter>

    <filter-mapping>
        <filter-name>springSecurityFilterChain</filter-name>
        <url-pattern>/home/*</url-pattern>
        <url-pattern>/project/*</url-pattern>
        <url-pattern>/admin/*</url-pattern>
        <url-pattern>/monitor/*</url-pattern>
        <url-pattern>/monitor_demo/*</url-pattern>
    </filter-mapping>

    <session-config>
        <session-timeout>180</session-timeout>
    </session-config>

</web-app>
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回答 2

Stack Overflow用户

回答已采纳

发布于 2012-05-02 06:15:08

mvc静态资源可能会有所帮助。Pl。请参阅:

http://static.springsource.org/spring/docs/3.0.5.RELEASE/spring-framework-reference/html/mvc.html#mvc-static-resources

票数 1
EN

Stack Overflow用户

发布于 2012-09-11 12:54:55

就像你告诉/home/images/hbg_01.gif的那样。资源路径由homeServlet映射。

更改url模式/home/*以避免映射到homeServlet,如:

代码语言:javascript
复制
<servlet-mapping>
    <servlet-name>homeServlet</servlet-name>
    <url-pattern>/home/anything/*</url-pattern>
</servlet-mapping>
票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/10406146

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