多态类的boost序列化似乎不起作用( 1.40+ boost),例如使用以下代码,我相信我遵循了这样的规则:导出类时,我尝试了gcc4.4 (ubuntu)和windows VS2010(使用Boost 1.48):在下面的程序中,我希望打印10和100,但它只打印10,这意味着它只序列化了基类;
我主要是从boost的文档中复制这个例子,但是它仍然不起作用,谁知道呢?非常感谢
#include <iostream>
#include <sstream>
#include <boost/serialization/base_object.hpp>
#include <boost/serialization/serialization.hpp>
#include <boost/archive/text_oarchive.hpp>
#include <boost/archive/text_iarchive.hpp>
#include <boost/serialization/export.hpp>
#define NVP(X) X
class base {
public:
friend class boost::serialization::access;
base (){ v1 = 10;}
int v1;
template<class Archive>
void serialize(Archive & ar, const unsigned int file_version)
{
ar & NVP(v1);
}
};
class derived : public base {
public:
friend class boost::serialization::access;
int v2 ;
derived() { v2 = 100;}
template<class Archive>
void serialize(Archive & ar, const unsigned int file_version){
boost::serialization::base_object<base>(* this);
ar & NVP(v2);
}
};
BOOST_CLASS_EXPORT(base);
BOOST_CLASS_EXPORT_GUID(derived, "derived");
int main ( )
{
std::stringstream ss;
boost::archive::text_oarchive ar(ss);
base *b = new derived();
ar << NVP(b);
std::cout << ss.str();
}发布于 2012-04-30 21:00:05
你忘了
virtual ~base() {}这不仅是多态序列化工作所必需的(没有它,您的类是而不是多态),而且我认为在48个州中忽略它是一种轻罪。所以YMMV。
哦,应该是ar & boost::serialization::base_object<...>。
https://stackoverflow.com/questions/10378733
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