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社区首页 >问答首页 >如何在Android中对中国人进行排序?

如何在Android中对中国人进行排序?
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Stack Overflow用户
提问于 2012-04-15 04:52:03
回答 4查看 2.7K关注 0票数 2

我有一个字符串列表,每个字符串都可能由汉字、数字或英文字符组成。(例如:“z莉z莉”,“露西”,“蒋豪”、"qwer“、"zout1iao”、"hah")。我想做的是按照英文字母顺序排序,就像安卓的联系人应用程序。(即"hah“、”蒋豪“,”露西“、"qwer”、"z莉z莉“、"zout1iao"),所以我的策略是把所有汉字转换成拼音,然后像往常一样比较它们。我尝试过库yinpin4j,它在J2SE平台上运行良好,但是当我在Android上运行相同的代码时,它会引发一个错误。java代码是:

代码语言:javascript
复制
@Override
public int compareTo(People another) {
    String onePinyin = HanziHelper.words2Pinyin(name);
String theOtherPinyin = HanziHelper.words2Pinyin(another.getName());
return onePinyin.compareTo(theOtherPinyin);
}

private static String char2String(char c) {
    StringBuilder sb = new StringBuilder();
    return sb.append(c).toString(); 
}

public static String char2Pinyin(char c) {
    String[] pinyin = null;
    try {
        pinyin = PinyinHelper.toHanyuPinyinStringArray(c, format);
    } catch(BadHanyuPinyinOutputFormatCombination e) {
        e.printStackTrace();
    }
    if(pinyin == null) {
        return char2String(c);
    } else {
        return pinyin[0];
    }
}

public static String words2Pinyin(String words) {
    StringBuilder sb = new StringBuilder();
    char[] chars = words.toCharArray();
    for(int i = 0, length = chars.length; i < length; i++) {
        sb.append(char2Pinyin(chars[i]));
    }
    return sb.toString();
}

错误是:

代码语言:javascript
复制
04-15 12:37:15.750: W/System.err(6898): java.io.IOException: BufferedInputStream is closed
04-15 12:37:15.791: W/System.err(6898):     at     java.io.BufferedInputStream.streamClosed(BufferedInputStream.java:116)
04-15 12:37:15.791: W/System.err(6898):     at java.io.BufferedInputStream.read(BufferedInputStream.java:294)
04-15 12:37:15.791: W/System.err(6898):     at java.io.InputStreamReader.read(InputStreamReader.java:255)
04-15 12:37:15.791: W/System.err(6898):     at java.io.BufferedReader.fillBuf(BufferedReader.java:128)
04-15 12:37:15.791: W/System.err(6898):     at java.io.BufferedReader.read(BufferedReader.java:236)
04-15 12:37:15.791: W/System.err(6898):     at java.util.Properties.load(Properties.java:307)
04-15 12:37:15.791: W/System.err(6898):     at java.util.Properties.load(Properties.java:266)
04-15 12:37:15.791: W/System.err(6898):     at net.sourceforge.pinyin4j.ChineseToPinyinResource.initializeResource(Unknown Source)
04-15 12:37:15.791: W/System.err(6898):     at net.sourceforge.pinyin4j.ChineseToPinyinResource.<init>(Unknown Source)
04-15 12:37:15.791: W/System.err(6898):     at net.sourceforge.pinyin4j.ChineseToPinyinResource.<init>(Unknown Source)
04-15 12:37:15.791: W/System.err(6898):     at net.sourceforge.pinyin4j.ChineseToPinyinResource$ChineseToPinyinResourceHolder.<clinit>(Unknown Source)
04-15 12:37:15.791: W/System.err(6898):     at net.sourceforge.pinyin4j.ChineseToPinyinResource.getInstance(Unknown Source)
04-15 12:37:15.796: W/System.err(6898):     at net.sourceforge.pinyin4j.PinyinHelper.getUnformattedHanyuPinyinStringArray(Unknown Source)
04-15 12:37:15.796: W/System.err(6898):     at net.sourceforge.pinyin4j.PinyinHelper.getFormattedHanyuPinyinStringArray(Unknown Source)
04-15 12:37:15.796: W/System.err(6898):     at net.sourceforge.pinyin4j.PinyinHelper.toHanyuPinyinStringArray(Unknown Source)
04-15 12:37:15.796: W/System.err(6898):     at com.sf.tools.HanziHelper.char2Pinyin(HanziHelper.java:29)
04-15 12:37:15.796: W/System.err(6898):     at com.sf.tools.HanziHelper.words2Pinyin(HanziHelper.java:44)
04-15 12:37:15.796: W/System.err(6898):     at com.sf.parse.PeopleListParser$Result$People.compareTo(PeopleListParser.java:156)
04-15 12:37:15.796: W/System.err(6898):     at com.sf.parse.PeopleListParser$Result$People.compareTo(PeopleListParser.java:1)
04-15 12:37:15.796: W/System.err(6898):     at java.util.ComparableTimSort.countRunAndMakeAscending(ComparableTimSort.java:286)
04-15 12:37:15.796: W/System.err(6898):     at java.util.ComparableTimSort.sort(ComparableTimSort.java:153)
04-15 12:37:15.796: W/System.err(6898):     at java.util.ComparableTimSort.sort(ComparableTimSort.java:142)
04-15 12:37:15.796: W/System.err(6898):     at java.util.Arrays.sort(Arrays.java:1974)
04-15 12:37:15.796: W/System.err(6898):     at java.util.Collections.sort(Collections.java:1941)
04-15 12:37:15.796: W/System.err(6898):     at com.sf.activity.PeopleListActivity.initPageView(PeopleListActivity.java:73)
04-15 12:37:15.796: W/System.err(6898):     at com.sf.activity.ReceiverListActivity.initPageView(ReceiverListActivity.java:23)
04-15 12:37:15.796: W/System.err(6898):     at com.yek.android.base.BaseActivity.onCreate(BaseActivity.java:158)

然后我改用Collator usCollator = Collator.getInstance(Locale.SIMPLIFIED_CHINESE); usCollator.setStrength(Collator.PRIMARY);,只要有汉字就行了。在上面的例子中,这个方法将中文和英文分开排序。

那么,你有什么想法吗?

EN

回答 4

Stack Overflow用户

发布于 2012-04-15 06:09:20

联系人应用程序使用“整理本地化ASC”。你可以尝试同样的方法

What does COLLATE LOCALIZED ASC stand for?

票数 0
EN

Stack Overflow用户

发布于 2012-05-21 12:54:46

我的建议是,逐个解析"word“代码点,并构建一个新的字符串。如果下一个代码点的拉丁/公共,不要调用words2Pinyin(),只需将聊天添加到新构建的字符串。它是中文,调用words2Pinyin()并将拼音添加到新字符串中。循环播放。在最后,你有一个干净的拉丁字符串。

票数 0
EN

Stack Overflow用户

发布于 2012-06-06 08:20:51

你可以搜索一个看起来像pinyin.jar的jar,它可以帮助你

票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/10159640

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