此脚本应该检测完整路径中的最后一部分,如果是stackoverflow输出ok
$current_url = $_SERVER['REQUEST_URI'];
$current_url_arr = explode('/',$current_url);
$count = count($current_url_arr);
if($current_url_arr[$count-2] == 'stackoverflow'){
echo 'ok';
}
else {
echo 'not ok';
}示例1:www.myserver.ext/something/else/stackoverflow/输出:ok
示例2:www.myserver.ext/something/else/stackoverflow输出:not ok
示例3:www.myserver.ext/something/else/stackoverflow/foo输出:not ok
我希望你能理解这个想法。这个脚本运行良好,但我想知道是否有更好、更优雅的方式来读取URL的最后部分?
发布于 2012-04-14 22:40:33
是!有$_SERVER['PATH_INFO']
if(isset($_SERVER['PATH_INFO'])) {
$info = explode('/', trim($_SERVER['PATH_INFO'], '/'));
if($info[count($info) - 1] === 'stackoverflow') {
echo 'ok';
} else {
echo 'not ok';
}
}发布于 2012-04-14 22:44:39
if (preg_match("#stackoverflow/$#", $_SERVER['REQUEST_URI'])) {
echo 'ok';
}发布于 2012-04-14 23:13:58
我认为这是最好的方法:
<?php
$url = "www.myserver.ext/something/else/stackoverflow/";
$fullpath = parse_url($url, PHP_URL_PATH);
$paths = explode("/", $fullpath);
$path = $paths[sizeof($paths)-1];
if ($path === "stackoverflow") {
# Condition satisfied
}
?>https://stackoverflow.com/questions/10157927
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