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社区首页 >问答首页 >Win CE:创建命名共享内存

Win CE:创建命名共享内存
EN

Stack Overflow用户
提问于 2012-04-14 18:35:39
回答 1查看 1.8K关注 0票数 0

我尝试在win CE6.0上创建命名共享内存,但是可能该进程没有保存数据。我写了两个过程。第一个将文本写入共享内存,第二个读取。第二个显示空消息窗口。

第一进程:

代码语言:javascript
复制
#include "stdafx.h"
#include <stdlib.h>

#define BUFFSIZE 256
TCHAR szName[]=TEXT("MyFileMappingObject");
TCHAR szText[]=TEXT("Process write");

int _tmain(int argc, TCHAR *argv[], TCHAR *envp[])
{
HANDLE hMutex;  
HANDLE hMapFile;
LPCTSTR pBuff;
BOOL fFirstApp = TRUE;
int rc;

// Create mutex used to share memory-mapped structure.
hMutex = CreateMutex (NULL, TRUE, TEXT ("MyFileMOWRT"));
rc = GetLastError();
if (rc == ERROR_ALREADY_EXISTS)
    fFirstApp = FALSE;
else if (rc)
{
    _tprintf(TEXT("rc1 (%d).\n"), GetLastError());
    return 0;
}

// Wait here for ownership to ensure that the initialization is done.
// This is necessary since CreateMutex doesn’t wait.
rc = WaitForSingleObject(hMutex, 2000);
if (rc != WAIT_OBJECT_0)
{
    _tprintf(TEXT("rc2 wait (%d).\n"), GetLastError());
    return 0;
}

// Create a file-mapping object.
hMapFile = CreateFileMapping(INVALID_HANDLE_VALUE, NULL, PAGE_READWRITE, 0, 
                             BUFFSIZE, szName);
if (hMapFile == NULL)
{
    _tprintf(TEXT("Could not create file mapping object (%d).\n"), GetLastError());
    return 1;
}
else
    printf("File mapping object was created\n");

// Map into memory the file-mapping object.
pBuff = (LPTSTR)MapViewOfFile(hMapFile, FILE_MAP_WRITE, 0, 0, BUFFSIZE);
if (pBuff == NULL)
{
    _tprintf(TEXT("Could not map view of file (%d).\n"), GetLastError());
    CloseHandle(hMapFile);

    return 1;
}
else
    printf("Map view of file\n");

CopyMemory((PVOID)pBuff, szText, (_tcslen(szText) * sizeof(TCHAR)));

UnmapViewOfFile(pBuff);

// Release the mutex. We need to release the mutex twice 
// if we owned it when we entered the wait above.   ReleaseMutex(hMutex);
ReleaseMutex(hMutex);
if (fFirstApp)
    ReleaseMutex(hMutex);

CloseHandle(hMapFile);
CloseHandle(hMutex);

return 0;
}

第二阶段:

代码语言:javascript
复制
#include "stdafx.h"
#include <stdlib.h>

#define BUFFSIZE 256
TCHAR szName[]=TEXT("MyFileMappingObject");

int _tmain(int argc, TCHAR *argv[], TCHAR *envp[])
{
    HANDLE hMutex;  
HANDLE hMapFile;
LPCTSTR pBuf;
BOOL fFirstApp = TRUE;
int rc;

// Create mutex used to share memory-mapped structure.
hMutex = CreateMutex (NULL, TRUE, TEXT ("MyFileMOWRT"));
rc = GetLastError();
if (rc == ERROR_ALREADY_EXISTS)
    fFirstApp = FALSE;
else if (rc)
{
    _tprintf(TEXT("rc1 (%d).\n"), GetLastError());
    return 0;
}

// Wait here for ownership to ensure that the initialization is done.
// This is necessary since CreateMutex doesn’t wait.
rc = WaitForSingleObject(hMutex, 2000);
if (rc != WAIT_OBJECT_0)
{
    _tprintf(TEXT("rc2 wait (%d).\n"), GetLastError());
    return 0;
}

// Create a file-mapping object.
hMapFile = CreateFileMapping(INVALID_HANDLE_VALUE, NULL, PAGE_READWRITE, 0, 
                             BUFFSIZE, szName);
if (hMapFile == NULL)
{
    _tprintf(TEXT("Could not create file mapping object (%d).\n"), GetLastError());
    return 1;
}
else
    printf("File mapping object was created\n");

pBuf = (LPTSTR) MapViewOfFile(hMapFile, FILE_MAP_READ, 0, 0, 0);    
if (pBuf)
{
    MessageBox(NULL, pBuf, TEXT("Process2"), MB_OK);
}
else
{
    _tprintf(TEXT("Could not map view of file (%d).\n"), GetLastError());
    CloseHandle(hMapFile);

    return 1;
}

UnmapViewOfFile(pBuf);

// Release the mutex. We need to release the mutex twice 
// if we owned it when we entered the wait above.   ReleaseMutex(hMutex);
ReleaseMutex(hMutex);
if (fFirstApp)
    ReleaseMutex(hMutex);

CloseHandle(hMapFile);
CloseHandle(hMutex);

return 0;
}

运行进程的程序:

代码语言:javascript
复制
#include "stdafx.h"
#include <stdlib.h>

int _tmain(int argc, TCHAR *argv[], TCHAR *envp[])
{
    CreateProcess(TEXT("\\Windows\\Mutex_proces.exe"), NULL, 0,0,0,0,0,0,0,0);
    CreateProcess(TEXT("\\Windows\\Mutex_proces_rd.exe"), NULL, 0,0,0,0,0,0,0,0);

    return 0;
}
EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2012-04-19 14:16:39

在从MapViewOfFile获得指向共享内存的指针之后,两个进程中的代码都应该设置同步模式,以便从/写入该内存:

过程1- P1

  1. 创建命名文件映射
  2. 获取指向内存的指针
  3. 写到内存
  4. 创建命名互斥,
  5. 向已写入内存的P2 (使用互斥)发出信号,P2可以读取它。
  6. P1应该等到P2读取共享内存时,它可以简单地等待互斥对象从第4点开始。

过程2- P2

mutex.

  • Create

  • 创建命名互斥锁,但如果它不存在,则返回错误,或者等待P1创建这个名为文件的

  • ,并获得指向其内存

  • 句柄的互斥对象的指针(从1开始)。如果需要,P2现在等待P1信号(使用P1信号到达,然后在读取释放互斥体之后读取内存,以便P1可以从第6点开始处理。
票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/10156231

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