如何使用BeginInvoke

Question

我有个问题：

第20行(LOOT_FromContainer(容器))我需要使用它作为Invoke，因为我想执行的过程需要一些时间，所以ServerMessageHandler不会处理它.

如果我只是简单地将这一行重写为LOOT_FromContainer.BeginInvoke(container);，那么我就会出现以下错误：

error CS0119：'LOOT.LOOT_FromContainer(Phoenix.Serial)‘是一个’方法‘，它在给定的上下文中无效

我是C#新手，来自PHP，对于Invoke，我不太了解。几天来我一直在努力解决这个问题，连谷歌都没帮上忙.

  [ServerMessageHandler(0x3C)]
  public CallbackResult ContainerContains(byte[] data, CallbackResult prevResult)
  {
     PacketReader reader = new PacketReader(data);
     reader.Skip(3);

     ushort len = reader.ReadUInt16();
     for (int i = 0; i < len; i++)
     {
        Serial serial = (Serial)(reader.ReadUInt32());
        ushort graphic = (ushort)(reader.ReadUInt16());

        reader.Skip(7);

        Serial container = (Serial)(reader.ReadUInt32());
        ushort color = (ushort)(reader.ReadUInt16());

        if (((int)graphic == 0x0E76) && ((int)color == 0x049A))
        {
           LOOT_FromContainer.BeginInvoke(container);
        }
     }
     return CallbackResult.Normal;
  }

  [Command]
  public static void LOOT_FromContainer(Serial target)
  {
        UOItem lootCorpse = new UOItem(target);
        if (lootCorpse.Graphic == 0x2006)
        {
            if (((draw == 1) && (World.Player.Backpack.AllItems.Count(draw_knife[0], draw_knife[1]) > 0)) || (World.Player.Layers[Layer.RightHand].Exist))
            {
                if ((lootCorpse.Amount != 400) && (lootCorpse.Amount != 401))
                {
                    if (draw == 0)
                    {
                        UO.WaitTargetObject(lootCorpse);
                        UO.UseObject(World.Player.Layers[Layer.RightHand].Serial);
                    }
                    else
                    {
                        UO.WaitTargetObject(lootCorpse);
                        UO.UseType(draw_knife[0], draw_knife[1]);
                    }
                    UO.Wait(500);
                }
            }
            else
        {
               UO.Print("Neni cim rezat, pouze lootim");
        }

            for (int i = 0; i < loot.Length; i++)
            {
           if (lootCorpse.Items.Count(loot[i][0], loot[i][1]) > 0)
                {
              if (loot[i][2] == 1)
              {
                 if (loot[i][4] == 1)
                 {
                    UO.MoveItem(lootCorpse.Items.FindType(loot[i][0], loot[i][1]), 0, Aliases.GetObject("loot_bag"), loot[i][5], loot[i][6]);
                      UO.Wait(200);
                 }
                 else
                 {
                    UO.MoveItem(lootCorpse.Items.FindType(loot[i][0], loot[i][1]), 0, World.Player.Backpack);
                        UO.Wait(200);
                 }
              }
                }
            }
        }
  }

Answer 1

我想这就是你需要的。您需要声明一个与您的方法具有相同的返回类型和输入参数的委托，实例化该委托将其指向您的方法，然后调用BeginInvoke传递您的串行变量，然后是null，null：

public delegate void LFC(Serial target);

[ServerMessageHandler(0x3C)]
  public CallbackResult ContainerContains(byte[] data, CallbackResult prevResult)
  {
   PacketReader reader = new PacketReader(data);
   reader.Skip(3);

   ushort len = reader.ReadUInt16();
   for (int i = 0; i < len; i++)
   {
      Serial serial = (Serial)(reader.ReadUInt32());
      ushort graphic = (ushort)(reader.ReadUInt16());

      reader.Skip(7);

      Serial container = (Serial)(reader.ReadUInt32());
      ushort color = (ushort)(reader.ReadUInt16());

    LFC = lootfromcontainer = new LFC(LOOT_FromContainer);

      if (((int)graphic == 0x0E76) && ((int)color == 0x049A))
      {
        lootfromcontainer.BeginInvoke(container, null, null);
         //LOOT_FromContainer.BeginInvoke(container);
      }
   }
   return CallbackResult.Normal;
  }


[Command]
public static void LOOT_FromContainer(Serial target)
{
   UOItem lootCorpse = new UOItem(target);
      if (lootCorpse.Graphic == 0x2006)
      {
          if (((draw == 1) && (World.Player.Backpack.AllItems.Count(draw_knife[0], draw_knife[1]) > 0)) || (World.Player.Layers[Layer.RightHand].Exist))
          {
              if ((lootCorpse.Amount != 400) && (lootCorpse.Amount != 401))
              {
                  if (draw == 0)
                  {
                      UO.WaitTargetObject(lootCorpse);
                      UO.UseObject(World.Player.Layers[Layer.RightHand].Serial);
                  }
                  else
                  {
                      UO.WaitTargetObject(lootCorpse);
                      UO.UseType(draw_knife[0], draw_knife[1]);
                  }
                  UO.Wait(500);
              }
          }
          else
      {
             UO.Print("Neni cim rezat, pouze lootim");
      }

          for (int i = 0; i < loot.Length; i++)
          {
         if (lootCorpse.Items.Count(loot[i][0], loot[i][1]) > 0)
              {
            if (loot[i][2] == 1)
            {
               if (loot[i][4] == 1)
               {
                  UO.MoveItem(lootCorpse.Items.FindType(loot[i][0], loot[i][1]), 0, Aliases.GetObject("loot_bag"), loot[i][5], loot[i][6]);
                    UO.Wait(200);
               }
               else
               {
                  UO.MoveItem(lootCorpse.Items.FindType(loot[i][0], loot[i][1]), 0, World.Player.Backpack);
                      UO.Wait(200);
               }
            }
              }
          }
      }
}

Answer 2

如果您只需要在另一个线程中运行该线程，则可以使用ThreadPool。

为此，你需要一些简单的东西。

而不是：

LOOT_FromContainer.BeginInvoke(container);

你可以使用：

ThreadPool.QueueUserWorkItem(LOOT_FromContainer, container);

并稍微修改LOOT_FromContainer方法以：

public static void LOOT_FromContainer(object prm)
{
   var target = (Serial)prm;
   // ...

Answer 3

我假设LOOT_FromCotainer是一个控件，考虑到编译器返回的错误，人们可以粗略地猜出问题在于您使用非委托调用BeginInvoke。BeginInvoke的名称如下：

LOOT_FromContainer.BeginInvoke(container); //where container is a delegate that maybe declared as follows

private delegate void container; //may also contain parameters eg container(string s);

因此，只需以这种方式重新编写代码即可。例如，关于如何使用本文件，请参见BeginInvoke。