现在我试着用下面的代码编程发送SMS,但是我不理解SMS发送接收器的行为。
1)例如,如果我发送一条短信,那么
Activity.RESULT_OK内部的registerReceiver就会被调用3次。如果我发送3条短信通过调用sendSMS进行循环,那么Activity.RESULT_OK将被调用9次。现在我真的不知道一个短信发送为什么这个registerReceiver被调用了这么多次? 2)此外,当我在模拟器上运行此代码时,我通过模拟器端口将SMS发送到其他仿真程序,这是很自然的,但当我试图将SMS发送到实数时,我不会收到SMS发送失败通知,因为它只通知Activity.RESULT_OK。
发送短消息的代码
private void sendSMS(String phoneNumber, String message)
{
String SENT = "SMS_SENT";
String DELIVERED = "SMS_DELIVERED";
PendingIntent sentPI = PendingIntent.getBroadcast(this, 0,
new Intent(SENT), 0);
PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0,
new Intent(DELIVERED), 0);
Log.d("SMS Service", "SMS SEND CALLED");
//---when the SMS has been sent---
registerReceiver(new BroadcastReceiver(){
@Override
public void onReceive(Context arg0, Intent arg1) {
Log.d("SMS Service", "RECEIVE CALLED");
switch (getResultCode())
{
case Activity.RESULT_OK:
Toast.makeText(SMSService.this, "SMS sent",
Toast.LENGTH_SHORT).show();
System.out.println("SMSService " + "SMS SENT");
break;
case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
Toast.makeText(SMSService.this, "Generic failure",
Toast.LENGTH_SHORT).show();
System.out.println("SMSService " + "GENERIC FAILURE");
break;
case SmsManager.RESULT_ERROR_NO_SERVICE:
Toast.makeText(SMSService.this, "No service",
Toast.LENGTH_SHORT).show();
System.out.println("SMSService " + "NO SERVICE");
break;
case SmsManager.RESULT_ERROR_NULL_PDU:
Toast.makeText(SMSService.this, "Null PDU",
Toast.LENGTH_SHORT).show();
System.out.println("SMSService " + "Null PDU");
break;
case SmsManager.RESULT_ERROR_RADIO_OFF:
Toast.makeText(SMSService.this, "Radio off",
Toast.LENGTH_SHORT).show();
System.out.println("SMSService " + "Radio Off");
break;
}
}
}, new IntentFilter(SENT));
//---when the SMS has been delivered---
registerReceiver(new BroadcastReceiver(){
@Override
public void onReceive(Context arg0, Intent arg1) {
switch (getResultCode())
{
case Activity.RESULT_OK:
Toast.makeText(getBaseContext(), "SMS delivered",
Toast.LENGTH_SHORT).show();
System.out.println("SMSService " + "SMS Delivered");
break;
case Activity.RESULT_CANCELED:
Toast.makeText(getBaseContext(), "SMS not delivered",
Toast.LENGTH_SHORT).show();
System.out.println("SMSService " + "SMS not delivered");
break;
}
}
}, new IntentFilter(DELIVERED));
SmsManager sms = SmsManager.getDefault();
sms.sendTextMessage(phoneNumber, null, message, sentPI, deliveredPI);
} 发布于 2012-03-13 08:04:31
一般来说,这取决于您要发送的消息的大小--如果消息超过了单个消息的限制(在您的例子中,它听起来大约是单个消息限制的3倍),那么您将得到消息的每个部分的发送和传递报告。因为您没有手动拆分消息,所以不能为每个部分指定不同的意图。
值得一看的是SmsManager.divideMessage()自己拆分消息,然后在SmsManager.sendMultiPartTextMessage()进行实际发送。这允许您为消息的不同部分指定不同的挂起意图,这样您就可以确定消息何时最后发送了。
我认为仿真器将所有消息目的地视为准确,而且由于没有网络返回,否则您很可能不会从模拟器发送失败(除非您做了类似于将模拟器置于飞机模式)。根据经验,您确实可以在真正的设备上获得这些错误代码。
编辑:考虑到这一点,每次发送消息时,都会注册接收方,我使用的代码有一个清单注册接收方。有一种可能是,您已经多次注册它(它存在于您正在注册的上下文中),这将多次提供给您--这也会使它在3条消息中重复大约9次(假设第一条消息在发送完成之前注册了第三次)--但我不知道有多大的可能性。通过在注册的接收器中记录对象,您可以进行相对较好的测试。
这是我用来发送sms消息的代码的精简版本,它不会得到消息的重复响应:
ArrayList<String> split = SmsManager.getDefault().divideMessage(message);
ArrayList<PendingIntent> success = new ArrayList<PendingIntent>(partInfo.length);
Intent sendInt = null;
for (int i = 0; i < partInfo.length; i++)
{
sendInt = new Intent(context.getPackageName() + RELAY_INTERNAL_RESPONSE);
sendInt.putExtra(KEY_MESSAGEID, messageID);
sendInt.putExtra(KEY_PART_NUMBER, i);
sendInt.putExtra(KEY_REPLY_SEND_INTENT, sendIntAction);
sendInt.putExtra(KEY_NUMBER, number);
PendingIntent sendResult = PendingIntent.getBroadcast(context, i, sendInt, PendingIntent.FLAG_ONE_SHOT); //You have to use an incrementing request code to ensure you don't just get the same pending intent.
success.add(sendResult);
}
ArrayList<PendingIntent> receipt = new ArrayList<PendingIntent>(partInfo.length);
sendInt = new Intent(context.getPackageName() + RELAY_INTERNAL_RECEIPT);
sendInt.putExtra(KEY_MESSAGEID, messageID);
sendInt.putExtra(KEY_REPLY_RECEIPT_INTENT, receiptIntAction);
sendInt.putExtra(KEY_NUMBER, number);
PendingIntent sendResult = PendingIntent.getBroadcast(context, nextReceiptCounter(context), sendInt, PendingIntent.FLAG_ONE_SHOT);
for (int i = 0; i < partInfo.length; i++)
{
receipt.add(sendResult);
}
SmsManager sm = SmsManager.getDefault();
sm.sendMultipartTextMessage(target, null, split, success, receipt);我的受话人定义:
<receiver android:name="<package>.SMSBroadcastModule"
android:enabled="true"
android:exported="false">
<intent-filter>
<action android:name="<package>.RELAY_INTERNAL_RESPONSE" />
<action android:name="<package>.RELAY_INTERNAL_RESPONSE_RECEIPT" />
</intent-filter>
</receiver>发布于 2012-07-25 23:02:17
或者您可以为注册表做一个单例类:
public class RegisterReceiverSingleton {
private static RegisterReceiverSingleton rrS;
public static final String SENT = "SMS_SENT";
public static final String DELIVERED = "SMS_DELIVERED";
private RegisterReceiverSingleton(final Context ctx){
//when the SMS has been sent
ctx.registerReceiver(new BroadcastReceiver(){
@Override
public void onReceive(Context arg0, Intent arg1) {
switch (getResultCode())
{
case Activity.RESULT_OK:
Toast.makeText(ctx, "SMS Enviado",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
Toast.makeText(ctx, "Generic failure",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_NO_SERVICE:
Toast.makeText(ctx, "No service",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_NULL_PDU:
Toast.makeText(ctx, "Null PDU",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_RADIO_OFF:
Toast.makeText(ctx, "Radio off",
Toast.LENGTH_SHORT).show();
break;
}
}
}, new IntentFilter(SENT));
//when the SMS has been delivered
ctx.registerReceiver(new BroadcastReceiver(){
@Override
public void onReceive(Context arg0, Intent arg1) {
switch (getResultCode())
{
case Activity.RESULT_OK:
Toast.makeText(ctx, "SMS Entregado",
Toast.LENGTH_SHORT).show();
break;
case Activity.RESULT_CANCELED:
Toast.makeText(ctx, "SMS No Entregado",
Toast.LENGTH_SHORT).show();
break;
}
}
}, new IntentFilter(DELIVERED));
}
public static RegisterReceiverSingleton getInstance(final Context ctx){
if(rrS==null){
rrS = new RegisterReceiverSingleton(ctx);
}
return rrS;
}}
https://stackoverflow.com/questions/9680004
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