在我的Django项目中,我有两个应用程序:一个面向公众的应用程序和一个管理应用程序(不是django的内置管理站点)。我希望一个域名指向公共网站,另一个指向管理网站。(例如,根据域名的不同,/index.html路由将指向不同应用程序中的视图。)每个应用程序都有自己的URLconf,它们都包含在主URLconf中。做这件事最好的方法是什么?
发布于 2012-02-28 01:04:26
有很多种方法,这里有一些可以根据您的特定约束为您工作的方法。
- Make one urls script per site,
- Make one settings per site as such
- Run one Django instance per domain
示例设置文件:
management_settings.py
from settings import *
ROOT_URLCONF='management_urls.py'public_settings.py
from settings import *
ROOT_URLCONF='public_urls.py'并在每个服务器上运行一个Django服务器。不要忘记使用-管理命令的设置开关,如下所示:
# run public
./manage.py runserver --settings public_settings
# run management
./manage.py runserver --settings management_settings发布于 2012-02-28 17:35:16
您可以使用自己的主机中间件。
示例:https://code.djangoproject.com/wiki/MultiHostMiddleware
settings.py
HOST_MIDDLEWARE_URLCONF_MAP = {
# Control Panel
"www.example.com": "webapp.sites.example.urls",
}multihost.py
from django.conf import settings
from django.utils.cache import patch_vary_headers
class MultiHostMiddleware:
def process_request(self, request):
try:
request.META["LoadingStart"] = time.time()
host = request.META["HTTP_HOST"]
if host[-3:] == ":80":
host = host[:-3] # ignore default port number, if present
if settings.HOST_MIDDLEWARE_URLCONF_MAP.has_key(host):
request.urlconf = settings.HOST_MIDDLEWARE_URLCONF_MAP[host]
request.META["MultiHost"] = str(request.urlconf)
else:
request.META["MultiHost"] = str(settings.ROOT_URLCONF)
except KeyError:
pass # use default urlconf (settings.ROOT_URLCONF)
def process_response(self, request, response):
if request.META.has_key('MultiHost'):
response['MultiHost'] = request.META.get("MultiHost")
if request.META.has_key('LoadingStart'):
_loading_time = time.time() - int(request.META["LoadingStart"])
response['LoadingTime'] = "%.2fs" % ( _loading_time, )
if getattr(request, "urlconf", None):
patch_vary_headers(response, ('Host',))
return responsehttps://stackoverflow.com/questions/9474619
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