首页
学习
活动
专区
圈层
工具
发布
社区首页 >问答首页 >AudioTrack:从线程开始调用

AudioTrack:从线程开始调用
EN

Stack Overflow用户
提问于 2012-01-23 18:14:13
回答 1查看 4.2K关注 0票数 1

我在静态模式下使用AudioTrack一次又一次地再现相同的信号。

我在这里学习了这个例子,有时它运行得很好,但有时它会抛出这个错误,而它不会产生任何声音:

代码语言:javascript
复制
AudioTrack: start called from a thread
01-23 15:26:16.902: W/libutils.threads(1133): Thread (this=0x3973b8): don't call waitForExit() from this Thread object's thread. It's a guaranteed deadlock!

这是源代码。我试图确保我调用停止并为下一个“播放”执行重新加载数据。

代码语言:javascript
复制
     public class SoundPlayer {
     // originally from http://marblemice.blogspot.com/2010/04/generate-and-play-tone-in-android.html
        private int numSamples;
        private double sample[];
        private byte generatedSnd[];
        private AudioTrack audioTrack;

        public SoundPlayer(float duration, int sampleRate, double freqOfTone) {
            super();
            this.numSamples = (int) (duration * sampleRate);
            this.sample = new double[numSamples];
            this.generatedSnd = new byte[2 * numSamples];
            // fill out the array
            for (int i = 0; i < numSamples; ++i) {
                sample[i] = Math.sin(2 * Math.PI * i / (sampleRate / freqOfTone));
            }
            // convert to 16 bit pcm sound array
            // assumes the sample buffer is normalised.
            int idx = 0;
            for (final double dVal : sample) {
                // scale to maximum amplitude
                final short val = (short) ((dVal * 32767));
                // in 16 bit wav PCM, first byte is the low order byte
                generatedSnd[idx++] = (byte) (val & 0x00ff);
                generatedSnd[idx++] = (byte) ((val & 0xff00) >>> 8);

            }
            audioTrack = new AudioTrack(AudioManager.STREAM_MUSIC,
                    sampleRate, AudioFormat.CHANNEL_CONFIGURATION_MONO,
                    AudioFormat.ENCODING_PCM_16BIT, numSamples,
                    AudioTrack.MODE_STATIC);
            audioTrack.write(generatedSnd, 0, generatedSnd.length);
        }

        public void playSound() {
            if ( audioTrack.getPlayState() ==  (AudioTrack.PLAYSTATE_PLAYING | AudioTrack.PLAYSTATE_PAUSED )) {
                audioTrack.stop();
                audioTrack.reloadStaticData();
            }
            Log.i("Audio", "playState: " + audioTrack.getPlayState());
            audioTrack.play();
            audioTrack.stop();
            audioTrack.reloadStaticData();
        }

}

如果我们打开android源代码,它不会解释很多:

代码语言:javascript
复制
void AudioTrack::start()
{
sp<AudioTrackThread> t = mAudioTrackThread;

LOGV("start");
if (t != 0) {
    if (t->exitPending()) {
        if (t->requestExitAndWait() == WOULD_BLOCK) {
            LOGE("AudioTrack::start called from thread");
            return;
        }
    }
    t->mLock.lock();
 } 

有人知道怎么处理这件事吗?

EN

回答 1

Stack Overflow用户

发布于 2012-09-18 17:03:42

我也有过类似的问题。

简单地说,如果您碰巧在多个线程中运行了一些东西,则必须确保创建AudioTrack并在其上调用play()stop() --必须在同一个线程中执行

但是,这并不意味着您也必须在该线程中创建音频示例。如果您使用静态音频数据(AudioTrack.MODE_STATIC),您可以在其他地方预加载或生成它们,然后在应用程序的整个生命周期中使用它甚至多次。

票数 5
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/8976491

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档