返回StringBuffer阵列

Question

我使用StringBuffer从web服务发送和接收变量。

我的代码是：

// connection = new (urlSCS+ "/login")；connection = (HttpURLConnection) url.openConnection()；connection.setRequestMethod("POST")；

            connection.setRequestProperty("Content-Type",
                    "application/x-www-form-urlencoded");

            connection.setRequestProperty("Content-Length",
                    "" + Integer.toString(urlParameters.getBytes().length));
            connection.setRequestProperty("Content-Language", "pl-PL");

            connection.setUseCaches(false);
            connection.setDoInput(true);
            connection.setDoOutput(true);

            // Send request
            DataOutputStream wr = new DataOutputStream(
                    connection.getOutputStream());
            wr.writeBytes(urlParameters);
            wr.flush();
            wr.close();

            // Get Response
            InputStream is = connection.getInputStream();
            BufferedReader rd = new BufferedReader(new InputStreamReader(is));
            String line;
            StringBuffer response = new StringBuffer();
            while ((line = rd.readLine()) != null) {
                response.append(line);
                response.append('\r');
            }
            rd.close();

如何将此代码更改为能够接收数组而不是字符串？

我从web服务获得的请求如下：{"var", "var"}。

Answer 1

这可能对http://www.coderanch.com/t/393008/java/java/explode-Java有帮助

记住使用response.substring()从{}中删除响应！

看：

    String partsColl = "A,B,C";  
    String[] partsCollArr;  
    String delimiter = ",";  
    partsCollArr = partsColl.split(delimiter);

您将有您的响应在“所以子字符串他们”。祝好运!