上的简单Servlet部署
上的简单Servlet部署
提问于 2012-01-01 22:01:33
我先跟着头爪哇。
我按照他们的指示创建了一个简单的servlet，但是他们没有编写如何部署它。
我正在尝试将它部署到Tomcat 7上，并通过eclipse设置了它。
然而，我得到一个404页错误。
我创建了一个web.xml，我还将类文件放在WEB/ class中。
这是密码。
package org.code;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class KathyServlet extends HttpServlet {
public void doGet (HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
PrintWriter out;
String title = "PhraseOMatic has generated the following phrase.";
response.setContentType("text/html");
out = response.getWriter();
out.println("<HTML><HEAD><TITLE>");
out.println("PhraseOmatic");
out.println("</TITLE></HEAD><BODY>");
out.println("<H1>" + title + "</H1>");
out.println("<P>" + PhraseOMatic2.makePhrase());
out.println("<P><a href=\"KathyServlet\">make another phrase</a></p>");
out.println("</BODY></HTML>");
out.close();
}
}其他java代码文件：
package org.code;
public class PhraseOMatic2 {
public static String makePhrase() {
// make three sets of words to choose from
String[] wordListOne = {"24/7","multi-Tier","30,000 foot","B-to-B","win-win","front- end", "web-based","pervasive", "smart", "six-sigma","critical-path", "dynamic"};
String[] wordListTwo = {"empowered", "sticky", "valued-added", "oriented", "centric", "distributed", "clustered", "branded","outside-the-box", "positioned", "networked", "focused", "leveraged", "aligned", "targeted", "shared", "cooperative", "accelerated"};
String[] wordListThree = {"process", "tipping point", "solution", "architecture", "core competency", "strategy", "mindshare", "portal", "space", "vision", "paradigm", "mission"};
// find out how many words are in each list
int oneLength = wordListOne.length;
int twoLength = wordListTwo.length;
int threeLength = wordListThree.length;
// generate three random numbers, to pull random words from each list
int rand1 = (int) (Math.random() * oneLength);
int rand2 = (int) (Math.random() * twoLength);
int rand3 = (int) (Math.random() * threeLength);
// now build a phrase
String phrase = wordListOne[rand1] + " " + wordListTwo[rand2] + " " + wordListThree[rand3];
// now return it
return ("What we need is a " + phrase);
}
} web.xml：
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<display-name>HFJse</display-name>
<servlet>
<servlet-name>kathyServlet</servlet-name>
<servlet-class>org.yasin.KathyServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>KathyServlet</servlet-name>
<url-pattern>/snoop/*</url-pattern>
</servlet-mapping>
</web-app>回答 2
Stack Overflow用户
回答已采纳
发布于 2012-01-01 22:08:55
我们的servlet位于包org.code中，但是您在web.xml中设置的类名是org.yasin.KathyServlet。
此外，您在kathyServlet中将名称web.xml给servlet，但是您的映射使用了名称KathyServlet。Servlet名称区分大小写。
Stack Overflow用户
发布于 2012-01-01 22:37:10
如果该代码是正确的，那么web.xml是坏的。您正在使用以下方法定义servlet类：
org.yasin.KathyServlet
您的Servlet是：
org.code.KathyServlet
在web.xml中使用的Servlet需要指向正确的包和Sevlet名称。
您应该会在tomcat日志中看到与404错误相关联的ClassNotFound。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/8695849
复制相关文章
相似问题
腾讯云开发者
Copyright © 2013 - 2026 Tencent Cloud. All Rights Reserved. 腾讯云 版权所有
深圳市腾讯计算机系统有限公司 ICP备案/许可证号：粤B2-20090059 
粤公网安备44030502008569号
腾讯云计算（北京）有限责任公司 京ICP证150476号 | 京ICP备11018762号