在我的第一个Clojure程序中,我正在与NPE做斗争,并希望得到一些帮助。
call-elem是一个包含以下内容的结构:
:id,字符串类似于some.packagename.SomeClass.someMethod:calls (子),它是其他call-elem结构的一个向量。
定义如下:
(defstruct call-struct :id :calls)
(defn- class-name [call]
(let [id (call :id)]
(.substring id 0 (.lastIndexOf id "."))))
(defn- method-name [call]
(let [id (call :id)]
(.substring id (inc (.lastIndexOf id ".")))))我还有一个方法foo,它以一个class-map和一个call-elem作为参数。class-map是class-name到method-map的地图。method-map是method-name到variations列表的映射,每个variation都是带有:class-name、:method-name和:calls键的地图。:calls是其他变体的列表。foo函数应该返回一个包含两个元素的向量:-
第一个元素是一个类映射,它的新条目对应于call-elem及其子元素
以下是代码:
(declare foo' add-new-variation)
(defn foo [class-map call-elem]
(let [children (call-elem :calls)
class-name (class-name call-elem)
method-name (method-name call-elem)]
(if (empty? children)
(let [new-variation {:class-name class-name
:method-name method-name
:calls []}
new-class-map (add-new-variation class-map
class-name method-name
new-variation)]
[new-class-map new-variation])
(let [[new-class-map child-variations-list]
(reduce #(foo' %1 %2) (class-map '()) children)
new-variation {:class-name class-name
:method-name method-name
:calls child-variations-list}
new-class-map' (add-new-variation new-class-map
class-name method-name
new-variation)]
[new-class-map' new-variation]))))
(defn foo' [[class-map variations-list] call-elem]
(let [[new-class-map new-variation] (foo class-map call-elem)]
[new-class-map (cons new-variation variations-list)]))
(defn add-new-variation [class-map class-name method-name variation]
(let [method-map (if (contains? class-map class-name)
(class-map class-name) {})
variations-list (if (contains? method-map method-name)
(method-map method-name) [])
new-variations-list (conj variations-list variation)
new-method-map (assoc method-map method-name new-variations-list)]
(assoc class-map class-name new-method-map)))当我尝试运行以下代码时:
(try
(let [call-elem
(struct call-struct "Class1.method1"
[(struct call-struct "Class2.method1" [])])]
(second (foo {} call-elem)))
(catch Exception ex
(.printStackTrace ex)))我得到以下结果:
{:class-name "Class1",
:method-name "method1",
:calls ({:class-name "Class2", :method-name "method1", :calls []})}但是,当我试图运行下面的代码时,将调用增加一个更深的级别,就会得到一个NullPointerException
(try
(let [call-elem
(struct call-struct "Class1.method1"
[(struct call-struct "Class2.method1"
[(struct call-struct "Class3.method1" [])])])]
(second (foo {} call-elem)))
(catch Exception ex
(.printStackTrace ex)))下面是堆栈跟踪:
java.lang.NullPointerException
at first.simple$foo.invoke(NO_SOURCE_FILE:46)
at first.simple$foo_SINGLEQUOTE_.invoke(NO_SOURCE_FILE:55)
at first.simple$foo$fn__1986.invoke(NO_SOURCE_FILE:46)
at clojure.lang.ArrayChunk.reduce(ArrayChunk.java:58)
at clojure.core.protocols$fn__5565.invoke(protocols.clj:30)
at clojure.core.protocols$fn__5543$G__5538__5552.invoke(protocols.clj:11)
at clojure.core$reduce.invoke(core.clj:5995)
at first.simple$foo.invoke(NO_SOURCE_FILE:46)
at first.simple$eval2010.invoke(NO_SOURCE_FILE:6)
at clojure.lang.Compiler.eval(Compiler.java:6465)
at clojure.lang.Compiler.eval(Compiler.java:6431)
at clojure.core$eval.invoke(core.clj:2795)
at clooj.repl$create_clojure_repl$repl_thread_fn__578$fn__589.invoke(repl.clj:147)
at clojure.main$repl$read_eval_print__5967.invoke(main.clj:244)
at clojure.main$repl$fn__5972.invoke(main.clj:265)
at clojure.main$repl.doInvoke(main.clj:265)
at clojure.lang.RestFn.invoke(RestFn.java:1523)
at clooj.repl$create_clojure_repl$repl_thread_fn__578.invoke(repl.clj:145)
at clojure.lang.AFn.run(AFn.java:24)
at java.lang.Thread.run(Thread.java:680)发布于 2011-12-27 12:05:23
让我们仔细看看reduce in foo。我怀疑您试图将一个双元素集合作为reduce累加器的初始值传递,但是使用未引号的括号会使(class-map '())被视为要计算的表达式。更糟糕的是,它是有效的,因为class-map是一个clojure.lang.PersistentArrayMap,它实现了IFn。
因此,您没有创建两个元素列表,而是调用(class-map '()),它很可能返回nil,因为class-map中没有'()键。之后,在foo'中,您将尝试将nil绑定到[class-map variations-list]。轰隆隆。空指针异常
将reduce的第二个参数定义为向量应该可以解决这个问题。
--- before 2011-12-27 12:52:43.052218334 +0100
+++ after 2011-12-27 12:52:56.785477270 +0100
@@ -13,7 +13,7 @@
new-variation)]
[new-class-map new-variation])
(let [[new-class-map child-variations-list]
- (reduce #(foo' %1 %2) (class-map '()) children)
+ (reduce #(foo' %1 %2) [class-map '()] children)
new-variation {:class-name class-name
:method-name method-name
:calls child-variations-list}https://stackoverflow.com/questions/8643159
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