我怎样才能throw any object(Stone) continuously到moving Horizontally object?我使用了一个线程,它可以连续使用翻译动画来扔石头,但是内存使用量很大,我的设备在3-4 min.How之后就会慢下来来解决dis问题?
发布于 2011-12-19 12:38:48
我认为您最好实现自己的SurfaceView。在它中,您可以更巧妙地绘制动画对象(使用专用线程),而不是使用视图动画。(当然,您必须为此重写部分代码,但从长远来看,这可能是最好的)。
如果您想尝试SurfaceView,我建议您查看一下来自安卓的月球着陆器示例。
示例:
public class ThrowView extends SurfaceView implements SurfaceHolder.Callback, OnGestureListener{
//The OnGestureListener can detect a fling motion.
private class DrawingThread extends Thread{
private final float timefactor = 0.0001f; //This is used to make the animation a bit slower. Play with this value if the animation seems too be to slow or too fast.
private final float damp = 0.9; //This is used to slow down the object. If it stops too fast or slow, this is the value to change.
private float stoneX = 0; //The x-coordinate of our stone object. Use this when drawing.
private float stoneY = 0; //The y-coordinate of our stone object. Use this when drawing.
@Override
public void run(){
while(running){
Canvas c = null;
try{
c = surfaceHolder.lockCanvas(null);
synchronized (surfaceHolder) {
updatePhysics();
doDraw(c); //doDraw is not in this example, but it should essentially just draw our object at stoneX, stoneY.
}
}finally{
if(c!=null) surfaceHolder.unlockCanvasAndPost(c);
}
SystemClock.sleep(40);
}
private void updatePhysics(long time){
//Calculate how much time has passed since last step:
time1 = System.currentTimeMillis();
dT = (time1 - time2)*timefactor;
time2 = time1;
//Move the stone in x depending on the time and velocity:
stoneX += vX*dT;
//Decrease the velocity:
vX -= dT*damp:
}
}
protected volatile float vX = 0; //This is the x-speed. To be able to throw in y too, just make another variable for that.
@Override
public boolean onFling(MotionEvent e1, MotionEvent e2, float velocityX, float velocityY) {
//This is our onFling, here we take the velocity of the users fling and set our variable to that.
//Note that this value is based on pixels.
vX = velocityX;
return true;
}
@Override
public boolean onDown(MotionEvent e) {
//The onDown should return true so onFling can be activated:
return true;
}
}为便于使用,根据月球着陆器样本制作了此示例。这里省略了许多方法(对于这个例子来说不是必需的),但是可以根据月球着陆器来实现。
https://stackoverflow.com/questions/8561400
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