没有需要编译的体系结构(ONLY_ACTIVE_ARCH=YES、active arch=x86_64、VALID_ARCHS=armv6 armv7)

Question

我有一个带有两个目标的Xcode 3.2.5项目。第一个是普通的iOS目标。第二个是针对Mac的。以下是项目说明：

    92936A04148FEE15001C4EC6 /* Debug */ = {
        isa = XCBuildConfiguration;
        buildSettings = {
            ADDITIONAL_SDKS = "";
            ALWAYS_SEARCH_USER_PATHS = NO;
            ARCHS = "$(NATIVE_ARCH_ACTUAL)";
            COPY_PHASE_STRIP = NO;
            GCC_DYNAMIC_NO_PIC = NO;
            GCC_ENABLE_FIX_AND_CONTINUE = YES;
            GCC_OPTIMIZATION_LEVEL = 0;
            GCC_PRECOMPILE_PREFIX_HEADER = NO;
            GCC_PREFIX_HEADER = SleepSoundCommand_Prefix.pch;
            GENERATE_PKGINFO_FILE = NO;
            INFOPLIST_FILE = "SleepSoundCommand-Info.plist";
            INSTALL_PATH = "$(HOME)/Applications";
            ONLY_ACTIVE_ARCH = YES;
            OTHER_LDFLAGS = "";
            PREBINDING = NO;
            PRIVATE_HEADERS_FOLDER_PATH = "";
            PRODUCT_NAME = SleepSoundCommand;
            PUBLIC_HEADERS_FOLDER_PATH = "";
            SDKROOT = "";
            VALID_ARCHS = "i386 ppc ppc64 ppc7400 ppc970 x86_64";
        };
        name = Debug;
    };

问题是，当我试图构建的时候

No architectures to compile for (ONLY_ACTIVE_ARCH=YES, active arch=x86_64, VALID_ARCHS=armv6 armv7).

为什么要坚持"VALID_ARCHS=armv6 armv7"？

Answer 1

为什么要坚持"VALID_ARCHS=armv6 armv7"？

在Xcode项目中混合Mac和iOS目标总是很棘手的。

我怀疑您的问题与SDK的使用有关。如果您使用的是iOS SDK，并且目标是某个iOS设备，则需要arm*。确保SDK设置没有泄漏到Mac目标。

而且--如果可能的话，您应该升级到最新的Xcode。自从相对古老的3.2.