我有两张桌子。其中一个表有7个值,另一个表有5个值。这些表有其共同的主键。我想用这种方式连接两个表:如果我有一个表
English French
-------------------- --------------------
one Un
two Deux
three Trois
four Quatre
four Quattro
five Cinq
five Cinco另外一个是:
English French
-------------------- --------------------
one aaaaa
two bbbbb
three ccccc
four
five我想要一张这样的桌子
English French
-------------------- --------------------
one Un
one aaaaa
two Deux
two bbbb
three Trois
three ccccc
four Quatre
four Quattro
four --------
five Cinq
five Cinco
five ----------我试过使用join,但它可以将值four和five进行线性组合。我该怎么做呢?谢谢。
编辑:SQL查询:
SELECT l.date_location, l.duree, r.km_restitution, r.km_parcouru
FROM locations l, restitutions r
UNION
SELECT l.num_client, l.date_location, l.duree, r.km_restitution, r.km_parcouru
FROM locations l, restitutions r
id_agence num_immatriculation num_client km_restitution km_parcouru state date_restitution
1 406BON69 1002 30000 1000 BON 29-MAY-10
3 785CIM13 1001 56580 80 BON 09-AUG-08
5 800BBB75 1000 2020 20 BON 24-APR-11
4 307VXN78 1000 20040 40 BON 28-JAN-11
2 290UTT92 1004 30030 30 BON 01-AUG-10
5 777SET13 1005 4030 30 BON 26-APR-11
2 179CLV92 1004 15015 15 BON 03-FEB-11
5 400AAA75 1003 1020 20 BON 18-SEP-11
5 666NEF69 1004 3040 40 BON 15-APR-11
2 111AAA75 1001 20020 20 BON 21-DEC-09
1 333CCC78 1001 43250 40 BON 27-DEC-09
2 260CDE95 1003 79000 430 BON 10-SEP-09
4 307VXN78 1003 20090 90 BON 11-FEB-11
1 123ABC78 1003 10010 10 BON 04-OCT-10
1 222BBB77 1001 9050 50 BON 23-DEC-09
Locations
id_agence num_immatricul num_client duree date_location
2 406BON69 1002 20 10-MAY-10
3 785CIM13 1001 3 07-AUG-08
5 800BBB75 1000 7 18-APR-11
4 307VXN78 1000 5 24-JAN-11
1 290UTT92 1004 1 31-JUL-10
5 777SET13 1005 4 23-APR-11
1 179CLV92 1004 5 30-JAN-11
5 400AAA75 1003 2 17-SEP-11
2 123ABC78 1003 4 01-OCT-10
5 666NEF69 1004 5 11-APR-11
1 111AAA75 1001 2 20-DEC-09
1 222BBB77 1001 2 22-DEC-09
1 333CCC78 1001 3 25-DEC-09
1 260CDE95 1003 10 01-SEP-09
4 307VXN78 1003 13 30-JAN-11
2 123ABC78 1003 8 20-NOV-11
2 406BON69 1002 10 20-NOV-11期望结果
id_agence num_immatricul num_client duree date_location date_restitution
2 406BON69 1002 20 10-MAY-10 date_restitution
3 785CIM13 1001 3 07-AUG-08 date_restitution
5 800BBB75 1000 7 18-APR-11 date_restitution
4 307VXN78 1000 5 24-JAN-11 date_restitution
1 290UTT92 1004 1 31-JUL-10 date_restitution
5 777SET13 1005 4 23-APR-11 date_restitution
1 179CLV92 1004 5 30-JAN-11 date_restitution
5 400AAA75 1003 2 17-SEP-11 date_restitution
2 123ABC78 1003 4 01-OCT-10 date_restitution
5 666NEF69 1004 5 11-APR-11 date_restitution
1 111AAA75 1001 2 20-DEC-09 date_restitution
1 222BBB77 1001 2 22-DEC-09 date_restitution
1 333CCC78 1001 3 25-DEC-09 date_restitution
1 260CDE95 1003 10 01-SEP-09 date_restitution
4 307VXN78 1003 13 30-JAN-11 date_restitution
2 123ABC78 1003 8 20-NOV-11 ----------------
2 406BON69 1002 10 20-NOV-11 ---------------除了列名之外,我把date_restitution放在这里还包含了真正的日期。
发布于 2011-11-28 16:03:30
你需要一个工会:
select English, French from Table1
UNION ALL
select English, French from Table2或者一个完全的外部连接
select distinct coalesce(T1.English, T2.English), coalesce(T1.French, T2.French)
from Table1 T1
full outer join Table2 T2 on T1.English = T2.English编辑:
假设你想让restitutions.date_restitution代替date_location来记录归还-
SELECT l.num_client, l.date_location, l.duree, to_number(null) km_restitution, to_number(null) km_parcouru
FROM locations l
UNION ALL
SELECT r.num_client, r.date_restitution date_location, 0 duree, r.km_restitution, r.km_parcouru
FROM restitutions r进一步编辑(根据提供的结果):
select l.id_agence,
l.num_immatricul,
l.num_client,
l.duree,
l.date_location,
decode(r.date_restitution, NULL,'----------------', 'date_restitution')
as date_restitution -- or just r.date_restitution
from location l
left outer join restitution r
on l.id_agence = r.id_agence and
l.num_immatricul = r.num_immatricul and
l.num_client = r.num_client and
l.date_location <= r.date_restitution发布于 2011-11-28 16:02:51
你真的需要一个工会:
SELECT English, French FROM T1
UNION
SELECT English, French FROM T2如果您不关心副本,则可以使用UNION
在OP的评论之后编辑:
SELECT l.num_client, l.id_agence, l.num_immatricul
FROM locations l
UNION
SELECT r.num_client, r.id_agence, r.num_immatriculation
FROM restitutions r发布于 2011-11-28 16:04:53
以下几点应该可以做到。
SELECT tab1.English, tab1.French
UNION
SELECT tab2.English, tab2.Frenchhttps://stackoverflow.com/questions/8298529
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