PHP句子案例函数

Question

我有一个功能，从谷歌，以清理我的段落在句子的情况。

1. 我想要修改这个函数，使它将超过2个新的行字符转换为换行符。否则，它将转换空间中的所有新行字符。所以我想要段落格式的。在这里，它将所有新行字符转换为空间。
2. 在正确的句子里转换。但是，如果我发现一个单词有首字母作为大写，那么我需要函数来忽略这一点。有时，如果有任何名词，它需要的是大写。我们不能改变这个小案子。否则，如果名词和它有两个以上的大写字符，而不是第一个字符转换成小写。

像-> Noun => Noun但是NoUn => noun。意思是我想，如果不是第一个字符是大写，而是它转换它两个小写，否则它保持相同的格式。

function sentence_case($string) {
$sentences = preg_split('/([.?!]+)/', $string, -1, PREG_SPLIT_NO_EMPTY|PREG_SPLIT_DELIM_CAPTURE);
$new_string = '';
foreach ($sentences as $key => $sentence) {
    $new_string .= ($key & 1) == 0?
        ucfirst(strtolower(trim($sentence))) :
        $sentence.' ';
}
$new_string = preg_replace("/\bi\b/", "I", $new_string);
//$new_string = preg_replace("/\bi\'\b/", "I'", $new_string);
$new_string = clean_spaces($new_string);
$new_string = m_r_e_s($new_string);
return trim($new_string);
}

Answer 1

function sentence_case($str) {
   $cap = true;
   $ret='';
   for($x = 0; $x < strlen($str); $x++){
       $letter = substr($str, $x, 1);
       if($letter == "." || $letter == "!" || $letter == "?"){
           $cap = true;
       }elseif($letter != " " && $cap == true){
           $letter = strtoupper($letter);
           $cap = false;
       } 
       $ret .= $letter;
   }
   return $ret;
}

这将保留现有的专有名词大写、缩略语和缩写。

Answer 2

这应该可以做到：

function sentence_case($string) {
// Protect the paragraphs and the caps
$parDelim = "/(\n+\r?)/";
$string = preg_replace($parDelim, "#PAR#", $string);
$string = preg_replace("/\b([A-Z])/", "#$1#", $string);

$sentences = preg_split('/([.?!]+)/', $string, -1, PREG_SPLIT_NO_EMPTY|PREG_SPLIT_DELIM_CAPTURE);
$new_string = '';
foreach ($sentences as $key => $sentence) {
    $new_string .= ($key & 1) == 0?
        ucfirst(strtolower(trim($sentence))) :
        $sentence.' ';
}
$new_string = preg_replace("/\bi\b/", "I", $new_string);
//$new_string = preg_replace("/\bi\'\b/", "I'", $new_string);
$new_string = clean_spaces($new_string);
$new_string = m_r_e_s($new_string);

// Restore the paragraphs and the caps
$new_string = preg_replace("#PAR#", PHP_EOL, $new_string);
$new_string = preg_replace("/#([A-Z])#/", "$1", $new_string);
return trim($new_string);
}

它的工作方式是识别你想要保护的物品(第一段和第一帽)，然后用一个字符串标记它，当你完成任务时，你可以把它替换回来。假设字符串中还没有#PAR#和#A#。之后，如果要强制使用某一类型的行结束或中间的几行，则可以在段落分隔符中使用任何您想要使用的内容。

Answer 3

稍微修改了Sylverdrag的函数，我得到了一些对我很有用的东西。这个版本适用于我到目前为止抛出的每一句糟糕的句子:)

​

function sentence_case($string) {

$string = strtolower($string); // ADDED THIS LINE
    
// Protect the paragraphs and the caps
$parDelim = "/(\n+\r?)/";
$string = preg_replace($parDelim, "#PAR#", $string);
$string = preg_replace("/\b([A-Z])/", "#$1#", $string);

$sentences = preg_split('/([.?!]+)/', $string, -1, PREG_SPLIT_NO_EMPTY|PREG_SPLIT_DELIM_CAPTURE);
$new_string = '';
foreach ($sentences as $key => $sentence) {
    $new_string .= ($key & 1) == 0?
        ucfirst(strtolower(trim($sentence))) :
        $sentence.' ';
}
$new_string = preg_replace("/\bi\b/", "I", $new_string);
// GOT RID OF THESE LINES
// $new_string = preg_replace("/\bi\'\b/", "I'", $new_string);
// $new_string = clean_spaces($new_string);
// $new_string = m_r_e_s($new_string);

// Restore the paragraphs and the caps
$new_string = preg_replace("#PAR#", PHP_EOL, $new_string);
$new_string = preg_replace("/#([A-Z])#/", "$1", $new_string);
$new_string = preg_replace("/#([A-Z])#/", "$1", $new_string);
preg_match('/#(.*?)#/', $new_string, $match); // MODIFIED THIS LINE TO USE (.*?)

return trim($new_string);
}
           
           
$string = "that IS it!! YOU and i are Totally DONE hanging out toGether... like FOREveR DUDE! i AM serious. a good FRIEND would NOT treAT me LIKE you dO. it Seems, howEVER, THAT you ARE not ONE of tHe GOOD ONEs.";
           
echo "<b>String 1:</b> " . $string . "<br><b>String 2:</b> " . sentence_case($string);

​

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