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背景工作人员不工作
EN

Stack Overflow用户
提问于 2011-10-18 20:22:19
回答 1查看 348关注 0票数 3

我有一个表单调用另一个表单中的方法。但另一种形式的方法不能正常工作。

Form2调用main:

代码语言:javascript
复制
private void button1_Click(object sender, EventArgs e)
{
    main ma = new main();
    ma.AddType(txtName.Text,txtURL.Text,12);
    this.Close();
}

main:(向xml添加一行并从xml重新加载数据)

代码语言:javascript
复制
public void AddType(string name, string url, int interval)
{

    string path = Application.StartupPath + @"\sites.xml";
    //create new instance of XmlDocument
    XmlDocument doc = new XmlDocument();
    //load from file
    doc.Load(path);
    //create node and add value
    XmlNode node = doc.CreateNode(XmlNodeType.Element, "site", null);
    node.InnerXml = "<Name>"+name+"</Name><URL>"+url+"</URL><Status></Status><Response-Time></Response-Time><Last-Checked></Last-Checked>";
    //add to elements collection
    doc.DocumentElement.AppendChild(node);
    //save back
    doc.Save(path);
    bwLoadXML.RunWorkerAsync();
}

bwLoadXML.RunWorkerAsync();由于某种原因,bwLoadXML.RunWorkerAsync()没有在datagrid中显示新的

编辑,这里是backgroundWorker:

代码语言:javascript
复制
/////////////////////////////////
        ////Populate Grid from XML
        /////////////////////////////////
        private void bwLoadXML_DoWork(object sender, DoWorkEventArgs e)
        {
            gridPopulate();
        }
        private void gridPopulate()
        {

            DataSet data = new DataSet(); string p = System.IO.Path.Combine(Application.StartupPath, "sites.xml");
            data.ReadXml(p);
            if (this.dataGrid.InvokeRequired)
            {
                this.dataGrid.Invoke(new MethodInvoker(delegate
                {
                    this.dataGrid.DataSource = data;
                    this.dataGrid.DataMember = "site";
                }));
            }
            else
            {
                this.dataGrid.DataSource = data;
                this.dataGrid.DataMember = "site";
            }
            int i = 0;
            foreach (DataGridViewColumn column in this.dataGrid.Columns)
            {
                if (i != 0)
                {
                    if (column.Name == "Name" || column.Name == "Status" || column.Name == "URL" || column.Name == "Response-Time" || column.Name == "Last-Checked")
                    {
                        //column.AutoSizeMode
                        column.Visible = true;
                        //column.Width = (int)(dataGrid.Width * .2) + (column.Name.Length / 2)-9;
                        /*if (column.Name == "URL")
                        {
                            ColumnHeader ch = new ColumnHeader();
                            //ch.
                        }*/
                    }
                    else
                    {
                        column.Visible = false;
                        //dataGrid.Columns[i+1].CellType = new DataGridViewButtonColumn();
                        //dataGrid.Columns[i+1].HeaderCell.
                    }
                }
                i++;
            }
            if (this.dataGrid.InvokeRequired)
            {
                this.dataGrid.Invoke(new MethodInvoker(delegate
                {
                    // If column 3 is the checkbox column, we sit it's resize mode to none:
                    dataGrid.Columns[0].AutoSizeMode = DataGridViewAutoSizeColumnMode.None;
                    // Then we set the width:
                    dataGrid.Columns[0].Width = 25;
                    dataGrid.Columns[0].DefaultCellStyle.Padding = System.Windows.Forms.Padding.Empty;
                    // If column 3 is the checkbox column, we sit it's resize mode to none:
                    dataGrid.Columns[2].AutoSizeMode = DataGridViewAutoSizeColumnMode.DisplayedCells;
                    // Finally we set the rest of the grid to fill or what ever resizing you need:
                    dataGrid.AutoSizeColumnsMode = DataGridViewAutoSizeColumnsMode.Fill;
                }));
            }
            else
            {
                // If column 3 is the checkbox column, we sit it's resize mode to none:
                dataGrid.Columns[0].AutoSizeMode = DataGridViewAutoSizeColumnMode.None;
                // Then we set the width:
                dataGrid.Columns[0].Width = 25;
                dataGrid.Columns[0].DefaultCellStyle.Padding = System.Windows.Forms.Padding.Empty;
                // If column 3 is the checkbox column, we sit it's resize mode to none:
                dataGrid.Columns[2].AutoSizeMode = DataGridViewAutoSizeColumnMode.DisplayedCells;
                // Finally we set the rest of the grid to fill or what ever resizing you need:
                dataGrid.AutoSizeColumnsMode = DataGridViewAutoSizeColumnsMode.Fill;
            }
        }
EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2011-10-18 20:26:33

您的问题源于以下事实:您的按钮单击方法创建了一个,独立的主表单,并且不与您期望的进行交互。由于您的新表单在按钮单击完成后不再被引用,后台工作人员可能永远没有机会启动。您需要设置并保存对主表单的引用才能使用它。

代码语言:javascript
复制
public class Form2 : ... {
  main ma;

  public Form2(main ma) {
    this.ma = ma;
  }

  private void Button1_Click(object sender, EventArgs e) {
    this.ma.AddType(txtName.Text, txtUrl.Text, 12);
    this.Close();
  }
}

在主表单中,当您创建第二个表单并显示它时,您需要传递它所期望的表单:

代码语言:javascript
复制
void DoingSomething() {
  Form2 form = new Form2(this); // <-- this is where you pass in main
  form.ShowDialog();
}
票数 2
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/7813212

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