嘿,我有一组从数据库中返回的结果,它们是代表1-18的数字,这是drivers_id,它可以返回任意数量的取决于有多少车手从一场比赛中退休。然后,我将它们与用户驱动程序进行匹配,如果它们匹配,则从用户点到-10分。
如果他们不匹配,那么到+5分。如果查询根本不返回set,那么我知道用户--四个驱动程序--每个可以是+5个点,但是如果它返回5行,那么我如何循环遍历这些驱动程序并匹配它们呢?如果没有匹配,则向该驱动程序变量添加+5分,但必须在所有结果集进行比较之后,因为该驱动程序可能与$row中的下一行匹配。非常感谢你提供的帮助!
p.s结果集中的每个driver_id都是唯一的,因此一旦比较为真,那么driver_id就不会再次出现。
$results = mysql_query("SELECT drivers_id FROM results_retired WHERE drivers_id IN ('$driver1', '$driver2', '$driver3', '$driver4') AND track_id = '$track'") or die ("Failed to update" . mysql_error());
$retireddrivers = mysql_fetch_array($results)
if(in_array($driver1, $retireddrivers)){
$driveronepoints -= $driver_points_system["retired"];
}
else {
$driveronepoints += $driver_points_system["completion"];
}
if(in_array($driver2, $retireddrivers)) {
$drivertwopoints -= $driver_points_system["retired"];
}
else {
$drivertwopoints += $driver_points_system["completion"];
}
if(in_array($driver3, $retireddrivers)) {
$driverthreepoints -= $driver_points_system["retired"];
}
else {
$driverthreepoints += $driver_points_system["completion"];
}
if(in_array($driver4, $retireddrivers)) {
$driverfourpoints -= $driver_points_system["retired"];
}
else {
$driverfourpoints += $driver_points_system["completion"];
}我现在对代码做了一些修改,in_array函数可以在这个实例中使用吗??
谢谢
发布于 2011-09-23 00:03:02
看起来,您缺少了行与列的概念。
mysql_fetch_*将返回一行--也就是退休司机的ID之一--每一次调用。在使用in_array之前,您需要将它们收集到一个数组中。
while ($retired_driver = mysql_fetch_array($results))
{
$retireddrivers[] = $retired_driver['driver_id'];
}此外,如果您能够管理它,我也会考虑将驱动程序1-4放入数组中。然后你就可以像
// Ideally, $driver[1-4]* won't exist at all -- you'd pull the info from the DB,
// or from the form, and stuff it directly into the array.
// This code right here is just to make existing code work
$drivers = array(
array('id' => $driver1, 'points' => &$driver1points),
array('id' => $driver2, 'points' => &$driver2points),
array('id' => $driver3, 'points' => &$driver3points),
array('id' => $driver4, 'points' => &$driver4points),
);
foreach ($drivers as $driver)
{
if (in_array($driver['id'], $retireddrivers))
{
$driver['points'] -= $driver_points_system['retired'];
}
else
{
$driver['points'] += $driver_points_system['completion'];
}
}大大减少代码的重复。
https://stackoverflow.com/questions/7514469
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