我有一个GameLoop类,其中定义了一个ParticleSystem对象。
ParticleSystem包含一个粒子对象数组--我不想为每个单独的粒子加载一个图像,我只想从GameLoop类中的源图像中提取--我怎样才能高效地这样做呢?
解决方案:
以下是丹·S帮我想出的:
public class ResourceManager {
Context mContext;
public final HashMap<String, Bitmap> Texture = new HashMap<String, Bitmap>();
//Constructor
public ResourceManager(Context context)
{
mContext = context;
Texture.put("particle1", loadBitmap(R.drawable.particle1));
}
public Bitmap getBitmap(String key)
{
return Texture.get(key);
}
/** Load an image */
protected Bitmap loadBitmap(int id) { return BitmapFactory.decodeResource(mContext.getResources(), id); }
} //End ResourceManager然后在一个类中定义它:
rm = new ResourceManager(mContext);然后将rm变量向下传递:
ParticleSystem.Draw(rm, canvas);
{
Particle.Draw(rm, canvas);
}在粒子类中,我在构造函数中设置了一个字符串assetKey,因此我可以通过名称引用位图:
public void doDraw(ResourceManager rm, Canvas canvas) {
canvas.drawBitmap(rm.getBitmap(AssetKey), xpos, ypos, null);
}我希望这对其他人也有帮助。
发布于 2011-09-02 22:21:02
在GameLoop的构造函数中,创建位图并在那里保存对它们的引用,将它们设置为最终变量,以防止意外分配。每当您创建一个新的粒子系统时,将它们传递给构造函数或在适当的setter方法中设置它们。
示例:
// in GameLoop definition
private Bitmap particleA;
private Bitmap particleB;
// somewhere in GameLoop constructor
particleA = BitmapFactor.decodeResource (activity.getResources(), R.drawable.particle_a);
particleB = BitmapFactor.decodeResource (activity.getResources(), R.drawable.particle_b);
// where you build your particle
Particle (GameLoop gl, ...) {
oneLevelDown = new OneLevelDown(GameLoop gl, ...);
}
OneLevelDown (GameLoop gl, ...) {
twoLevelDown = new TwoLevelDown(GameLoop gl, ...);
}
TwoLevelDown (GameLoop gl, ...) {
particleABitmap = gl.getParticleA(); // simple getter
particleBBitmap = gl.getParticleB(); // simple getter
}一直把GameLoop传下去直到你说完为止。这可能不太有效,但一旦您掌握了喜欢的窍门,也请参阅本文中有关依赖注入的内容。
Java内存使用示例:
class Car{
public int year;
public int name;
}
// Object variables are references to an object's data.
Car a = new Car(); // first car object and variable.
a.year = 1990;
a.name = "Sam";
Car b = new Car();// second car object and variable
b.year = 2000;
b.name = "Bob";
Car c = a; // third car **variable** but same car object as **a**
// primitives are different
int a = 23; // first variable, 4 bytes used
int b = 45; // second variable, 4 bytes used (and a total of 8)
int c = a; // third variable, 4 bytes used (and a total of 12). c took on the value of a, but does not point to the same memory as ahttps://stackoverflow.com/questions/7289721
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