我正在尝试序列化和反序列化XPathDocument之间的协议缓冲区消息,但是它失败了,只有一个例外:ProtoBuf.ProtoException: message中检测到的不匹配的组标记--如何使它工作?
我正在使用protobuf-net,我用于复制它的源代码如下所示:
TestMsg.proto
option optimize_for = SPEED;
//*************************
message Test {
repeated A a = 1;
}
message A {
required string str = 1;
}Progam.cs
using System;
using System.Collections.Generic;
using System.IO;
using System.Xml;
using System.Xml.Serialization;
using System.Xml.XPath;
using ProtoBuf;
using TestMsg;
namespace protocolbufferserialize
{
class Program
{
static void Main(string[] args)
{
Test t = new Test();
XPathDocument xmldoc = Serialize(t);
Test t1 = Serialize(xmldoc);
}
public static XPathDocument Serialize(Test wro)
{
XPathDocument xmlDoc = null;
Serializer.PrepareSerializer<Test>();
XmlSerializer x = new XmlSerializer(wro.GetType());
using (MemoryStream memoryStream = new MemoryStream())
{
using (TextWriter w = new StreamWriter(memoryStream))
{
x.Serialize(w, wro);
memoryStream.Position = 0;
xmlDoc = new XPathDocument(memoryStream);
}
}
return xmlDoc;
}
public static Test Serialize(XPathDocument xmlDoc)
{
Test t = null;
Serializer.PrepareSerializer<Test>();
XmlSerializer x = new XmlSerializer(xmlDoc.GetType());
using (MemoryStream memoryStream = new MemoryStream())
{
using (TextWriter w = new StreamWriter(memoryStream))
{
x.Serialize(w, xmlDoc);
memoryStream.Position = 0;
t = Serializer.Deserialize<Test>(memoryStream);
}
}
return t;
}
}
}我试图扩展use,但是当测试对象从Serializer.Merge返回时它是空的。
using System;
using System.Collections.Generic;
using System.IO;
using System.Xml;
using System.Xml.Serialization;
using System.Xml.XPath;
using ProtoBuf;
using TestMsg;
namespace TestXMLSerilizationLars
{
class Program
{
static void Main(string[] args)
{
Test t = new Test();
A a = new A();
string str = "test";
a.str = str;
t.a.Add(a);
XPathDocument xmldoc = Serialize(t);
WriteXpathDocument(xmldoc, "c:\\testmsg.xml");
Test t1 = Serialize(xmldoc);
}
public static XPathDocument Serialize(Test t)
{
XPathDocument xmlDoc = null;
Serializer.PrepareSerializer<Test>();
XmlSerializer x = new XmlSerializer(t.GetType());
using (MemoryStream memoryStream = new MemoryStream())
{
using (TextWriter w = new StreamWriter(memoryStream))
{
x.Serialize(w, t);
memoryStream.Position = 0;
xmlDoc = new XPathDocument(memoryStream);
}
}
return xmlDoc;
}
public static Test Serialize(XPathDocument xmlDoc)
{
Test t = null;
Type type = xmlDoc.GetType();
XmlSerializer serializer = new XmlSerializer(type);
using (MemoryStream memoryStream = new MemoryStream())
{
serializer.Serialize(memoryStream, xmlDoc);
// memoryStream.Close();
Test newt = Deserialize(memoryStream.ToArray());
return newt;
}
return t;
}
static public Test Deserialize(byte[] Bytes)
{
MemoryStream SerializeStream = new MemoryStream(Bytes);
Test NewObject = Serializer.Deserialize<Test>(SerializeStream);
Test ObjectExist = new Test();
if (ObjectExist == null)
{
return NewObject;
}
else
{
SerializeStream.Seek(0, SeekOrigin.Begin);
Serializer.Merge<Test>(SerializeStream, ObjectExist);
return ObjectExist;
}
}
public static void WriteXpathDocument(XPathDocument xpathDoc, string filename)
{
// Create XpathNaviagtor instances from XpathDoc instance.
XPathNavigator objXPathNav = xpathDoc.CreateNavigator();
// Create XmlWriter settings instance.
XmlWriterSettings objXmlWriterSettings = new XmlWriterSettings();
objXmlWriterSettings.Indent = true;
// Create disposable XmlWriter and write XML to file.
using (XmlWriter objXmlWriter = XmlWriter.Create(filename, objXmlWriterSettings))
{
objXPathNav.WriteSubtree(objXmlWriter);
objXmlWriter.Close();
}
}
}
}我抛出的xml文件如下所示
<?xml version="1.0" encoding="utf-8"?>
<Test xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<a>
<A>
<str>test</str>
</A>
</a>
</Test>发布于 2011-06-24 22:45:39
您在这里使用protobuf的唯一方法是:
x.Serialize(w, xmlDoc);
memoryStream.Position = 0;
t = Serializer.Deserialize<Test>(memoryStream);您已经编写了xml (x是一个XmlSerializer),然后尝试通过protobuf (Serializer.Deserialize)读取它。
但是,protobuf不是xml;它是一种与xml完全无关的二进制格式。如果您打算深入克隆数据,还应该使用protobuf (Serializer.Serialize)进行序列化。
通常可以在两种格式之间转换模型,但是流本身是不可交换的。
https://stackoverflow.com/questions/6467758
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