当我试图使用.xml框架解析一个简单的RapidXML文件时,它会抛出一个parse_error,其原因是:“预期的<”。这实际上是我第一次编写XML代码,所以这可能是一个愚蠢的语法错误,在这种情况下,请原谅我:)这是我的xmlParser.h
#ifndef __XML_PARSER_H__
#define __XML_PARSER_H__
#include "rapidxml.hpp"
#include "windowUtil.h"
class XmlParser
{
public:
bool parse(char *xml)
{
try
{
doc.parse<0>(xml);
}
catch(rapidxml::parse_error &e)
{
msg_box(NULL, e.what(), "RapidXML exception!", MB_OK | MB_ICONERROR | MB_TASKMODAL);
return false;
}
return true;
}
char* get_first_node_name()
{
return doc.first_node()->name();
}
private:
rapidxml::xml_document<> doc;
};
#endif这就是它的名称和用法:
int WINAPI WinMain(HINSTANCE hinstance, HINSTANCE hprevinstance, LPSTR lpcmdline, int ncmdshow)
{
XmlParser xmlParser;
WindowFramework *window = create_window(&framework, NULL, NULL, "GAME");
if(!init_window(window, true, true))
return kill(1);
if(!xmlParser.parse("./layouts/login_gui.xml"))
return kill(1);
framework.main_loop();
return kill(0);
}login_gui.xml
<?xml version="1.0"?>
<button>
<text>EXIT</text>
<buttonready>button.png</buttonready>
<buttonrollover>button_active.png</buttonrollover>
<buttonpressed>button_pressed.png</buttonpressed>
<buttoninactive>button_inactive.png</buttoninactive>
</button>发布于 2011-06-13 16:45:04
parse方法接受一个包含XML的字符串,您将它传递给它一个文件名。您的文件名被视为XML数据,显然这是不对的。您必须先读取文件,然后用结果字符串调用parse。
来自RapidXML文档
函数xml_document::parse 提要
void parse(Ch *text); 描述 根据给定的标志解析以零结尾的XML字符串。
你修改过的结构可能是
bool parse(char *xmlFile)
{
try
{
std::string xml(getXmlDataFromFile(xmlFile));
doc.parse<0>(xml.c_str());
} 发布于 2011-06-13 16:46:43
我经常提到的是关于使用RapidXML的详细文档。,这是必读的!
下面是我试图读取文档(demo.xml)的第一个节点的尝试。
string input_xml;
string line;
ifstream in("demo.xml");
// read file into input_xml
while(getline(in,line))
input_xml += line;
// make a safe-to-modify copy of input_xml
// (you should never modify the contents of an std::string directly)
vector<char> xml_copy(input_xml.begin(), input_xml.end());
xml_copy.push_back('\0');
// only use xml_copy from here on!
xml_document<> doc;
// we are choosing to parse the XML declaration
// parse_no_data_nodes prevents RapidXML from using the somewhat surprising
// behavior of having both values and data nodes, and having data nodes take
// precedence over values when printing
// >>> note that this will skip parsing of CDATA nodes <<<
doc.parse<parse_declaration_node | parse_no_data_nodes>(&xml_copy[0]);
// we didn't keep track of our previous traversal, so let's start again
// we can match nodes by name, skipping the xml declaration entirely
xml_node<>* cur_node = doc.first_node("button");
// go straight to the first text node
cur_node = cur_node->first_node("text");
string text = cur_node->value(); // if the node doesn't exist, this line will crash
cout << text << endl;
// and then to the next node
cur_node = cur_node->next_sibling("buttonready");
string b_ready = cur_node->value();
cout << b_ready << endl;
// and then to the next node
// ...输出:
EXIT
button.png如果您的XML将来变得更加复杂,您可以看看这个答案:
它显示了同时从节点读取属性的源代码。
https://stackoverflow.com/questions/6333319
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