我有一个Angular Service,我尝试发送一个HTTP Post请求并将Content-Type标头设置为application/x-www-form-urlencoded
代码如下:
import { HttpClient, HttpHeaders } from '@angular/common/http';
export class UserService {
constructor(private http:HttpClient, private bodyParser:BodyParserService{}
public login(username:String, password:String){
let body = this.bodyParser.parseBody({username: username, password: password})
const options = {
headers: new HttpHeaders({'Content-Type': 'application/x-www-form-urlencoded'})
};
this.http.post(`${environment.apiUrl}/login`, body, options)
.subscribe((response:any) => {
console.log("Response", response);
})
}
}我正在使用Angular7。我使用Chrome浏览器,但问题在FireFox上仍然存在
我得到以下错误:
ERROR TypeError: url__WEBPACK_IMPORTED_MODULE_2__.URLSearchParams is not a constructor
at BodyParserService.push../src/app/services/body-parser.service.ts.BodyParserService.parseBody (body-parser.service.ts:12)
at UserService.push../src/app/services/user-service.service.ts.UserService.login (user-service.service.ts:21)
at LoginModalComponent.push../src/app/nav-bar/nav-bar.component.ts.LoginModalComponent.login (nav-bar.component.ts:50)
at Object.eval [as handleEvent] (LoginModalComponent.html:19)
at handleEvent (core.js:19545)
at callWithDebugContext (core.js:20639)
at Object.debugHandleEvent [as handleEvent] (core.js:20342)
at dispatchEvent (core.js:16994)
at core.js:17441
at HTMLButtonElement.<anonymous> (platform-browser.js:993)我已经确认,我已经导入了HttpClientModule
bodyParser服务:
import { Injectable } from '@angular/core';
import { URLSearchParams } from 'url';
@Injectable({
providedIn: 'root'
})
export class BodyParserService {
constructor() { }
public parseBody(bodyObject: Object): string {
const body = new URLSearchParams();
Object.keys(bodyObject).forEach(key => {
body.set(key.toString(), bodyObject[key]);
});
return body.toString();
}
}好吧,我发现了我的错误: URLSearchParams似乎被弃用了。我现在使用的是HttpParams:
const body = new HttpParams();发布于 2019-06-10 09:39:59
URLSearchParams已弃用,您必须使用HttpParams。例如
let params = new HttpParams()
.set('grant_type', 'password')
.set('username', username)
.set('password', password);
params.toString();发布于 2019-02-10 05:33:06
我已经在答案中添加了正确的解决方案。URLSearchParams似乎已被弃用。所以我换成了HttpParams,它似乎工作得无懈可击
https://stackoverflow.com/questions/54610734
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