有段时间我被困在这个问题上。我试图通过一个表单传递3个Id,以便将数据保存到我的数据库中。
def new
@person = Person.find(params[:person])
@honored = Person.find(params[:honored])
@group = Group.find(params[:group_id])
@honor = Honor.new
end
def create
@person = Person.find(current_person)
@honor = Honor.create(:group => Group.find(params[:group_id]),
:person => Person.find(params[:person]),
:honored => Person.find(params[:honored]))
if @honor.valid?
flash[:success] = "Honor created."
redirect_to (:back)
else
redirect_to (:back)
end
end在我看来,我在其中调用new方法:
<% @asked_groupmembership.each do |agm| %>
<%= link_to "Create Honor", new_honor_path(:group_id => @group.id, :person => current_person.id,
:honored => agm.member.id) %> 我的表格:
<% form_for @honor do |f| %>
<%= f.hidden_field :group_id, :value => @group.id %>
<%= f.hidden_field :person, :value => current_person.id %>
<%= f.hidden_field :honored, :value => @honored.id %>
<div class="field">
<%= f.label :texto %><br />
<%= f.text_field :texto %>
</div>当我单击submit按钮时,会得到以下错误:
Couldn't find Group without an ID
app/controllers/honors_controller.rb:22:in `create'
{"utf8"=>"✓",
"authenticity_token"=>"C7wofMY4VcyfdS10oc3iglex8nZVBMQ0Nh22nMiaOqs=",
"honor"=>{"group_id"=>"39",
"person"=>"2",
"honored"=>"44",
...
},
"commit"=>"Insert"}我怎么才能解决这个问题?谢谢。
##EDITED##
class Honor < ActiveRecord::Base
belongs_to :person, :class_name => 'Person', :foreign_key => "person_id"
belongs_to :honored, :class_name => 'Person', :foreign_key => "honored_id"
belongs_to :group, :class_name => 'Group', :foreign_key => "group_id"发布于 2011-05-26 12:16:02
您需要使用以下内容更新create方法:
def create
@person = Person.find(current_person)
@honor = Honor.create(:group_id => params[:honor][:group],
:person_id => params[:honor][:person],
:honored_id => params[:honor][:honored])
if @honor.save
...
end因为在你提交表格后,你得到了你的数据在对角线:荣誉。您可以在问题中的代码中看到传递给控制器的哈希:
"honor"=>{"group"=>"39",
"person"=>"2",
"honored"=>"44",发布于 2011-05-26 12:50:10
为了让它更易读,让我们这样做
表格:
<% form_for @honor do |f| %>
<%= f.hidden_field :group_id, :value => @group.id %>
<%= f.hidden_field :person_id, :value => current_person.id %>
<%= f.hidden_field :honored_id, :value => @honored.id %>
...
<% end %>主计长:
def new
@person = Person.find(params[:person])
@honored = Person.find(params[:honored])
@group = Group.find(params[:group_id])
@honor = Honor.new
end
def create
@person = Person.find(current_person)
@honor = Honor.create(
:group => Group.find(params[:honor][:group_id]),
:person => Person.find(params[:honor][:person_id]),
:honored => Person.find(params[:honor][:honored_id])
)
if @honor.save
...
end
end表单中的每个隐藏字段都将作为params[:honor]中的param到达控制器。
现在,看看控制器,有些东西看上去不太对。如果没有错误,create方法将创建一个新实例并保存该对象。调用create,然后调用save,但您可以调用new (而不是create),然后调用save,或者继续使用create,然后再调用valid?。就我个人而言,我认为new然后save过程更干净。
示例:
def create
@person = Person.find(current_person)
@honor = Honor.new(
:group => Group.find(params[:honor][:group_id]),
:person => Person.find(params[:honor][:person_id]),
:honored => Person.find(params[:honor][:honored_id])
)
if @honor.save
...
end
end https://stackoverflow.com/questions/6138153
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