解决约束问题需要帮助(二)

Question

我已经解决了以下约束处理任务。你能确认一下是否正确吗？

One of the prisoners of a high-level security prison sees a way to escape. Almost
free, he reaches a corridor of 20 meters long, guarded by 5 cameras, behind
which is the exit. In Figure 3, we provide a schematic overview of the corridor.

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The prisoner has only 10 seconds to reach the end of the corridor and may 
not be noticed by the cameras in doing so. After 10 seconds, or when seen by a
camera, the prison is put under total lock-down, which will prevent his escape.
We will consider the following constraints:

• A camera can only see 3 meters and cannot see its own position. E.g., the
camera at position 9 is able to see the positions 6, 7 and 8, or 10, 11 and
12, depending on the orientation of the camera.

• At time point 0, all cameras are oriented towards the end of the corridor.
Thus, the camera at position 9 sees positions 10, 11 and 12.

• Every two seconds the cameras change their orientation. Thus, at time
point 2 the camera at position 9 will see the positions 6, 7 and 8.

• Every second, the prisoner can move 0, 1, 2 or 3 meters forward. He
cannot move backward. Thus, if the prisoner is standing at position 2 at
time point 2, then, at time point 3, he can be on position 2, 3, 4 or 5.

Formulate the problem above as a constraint problem. Come up with a useful
representation of the problem in terms of the constraint processing tool. Provide
an explanation of indices, variables and domains. Furthermore, provide for every
introduced constraint, the meaning of the constraint in natural language.

这是我的解决方案，希望你们能帮我检查一下我做错了什么：

***MY VARIABLES***

Name: T, domain: 0..10                 // T = the time from 0 to 10 seconds  

Name: P, domain: 0..3                   // P = Prisoner can move 0, 1, 2, 3 meters

Name: C1, domain: 2                     // C1 = camera 1

Name: C2, domain: 4                     // C2 = camera 2

Name: C3, domain: 9                       // C3 = camera 3

Name: C4, domain: 12                      // C4 = camera 14

Name: C5, domain: 17                      // C5 = camera 5

Name: View1, domain: -1..5                // camera1 view

Name: View2, domain: 1..7                   // camera2 view

Name: View3, domain: 6..12                 // camera3 view

Name: View4, domain: 9..15                 // camera4 view

Name: View5, domain: 14..20                // camera5 view

我的约束

我以这样的方式宣布了限制条件:每次相机的视角都是交替的，当时间是偶数时，当时间是偶数时，只有囚犯才能移动。

 Constraint: (T=0/\View1=(C1+3)/\View2=(C2+3)/\View3=(C3+3)/\View4=(C4+3)/\View5=(C5+3)/\P(i)), range: i>-1
    Constraint: (T=1/\P(i)), range: i>0
    Constraint: (T=2/\View1=(C1-3)/\View2=(C2-3)/\View3=(C3-3)/\View4=(C4-3)/\View5=(C5-3)/\P(i)), range: i>-1
    Constraint: (T=3/\P(i)), range: i>0
    Constraint: (T=4/\View1=(C1+3)/\View2=(C2+3)/\View3=(C3+3)/\View4=(C4+3)/\View5=(C5+3)/\P(i)), range: i>-1
    Constraint: (T=5/\P(i)), range: i>0
    Constraint: (T=6/\View1=(C1-3)/\View2=(C2-3)/\View3=(C3-3)/\View4=(C4-3)/\View5=(C5-3)/\P(i)), range: i>-1
    Constraint: (T=7/\P(i)), range: i>0
    Constraint: (T=8/\View1=(C1+3)/\View2=(C2+3)/\View3=(C3+3)/\View4=(C4+3)/\View5=(C5+3)/\P(i)), range: i>-1
    Constraint: (T=9/\P(i)), range: i>0
    Constraint: (T=10/\View1=(C1-3)/\View2=(C2-3)/\View3=(C3-3)/\View4=(C4-3)/\View5=(C5-3)/\P(i)), range: i>-1

伙计们，我知道我做错了什么，所以帮我纠正一下。

谢谢你的帮助。昨天我发布了一个类似的问题，所以如果您想知道变量和约束的语法，那么下面是链接：Variable and Constraint syntax in this post

谢谢你的帮忙

Answer 1

你已经忘记了相机无法看到自己：“相机只能看到3米，看不到自己的位置”.Thus，View1，View2.应修改View5。

Als，您需要一个变量来表示囚犯的位置(您只有一个变量用于囚犯的移动)

我在找其他的错误。