ExpectJ专家需要的帮助

Question

假设我有下面的say脚本details.sh

echo "name"
read name
if [ "$name" == "abcd" ]; then
echo "hi"
echo "hello"
echo "bye"
fi

=============================================

这是我的Java代码

ExpectJ exp = new ExpectJ();
String cmd = "sh details.sh"; //Command for execution of **details.sh**
Spawn s = exp.spawn(cmd); //Spawns the process **details.sh**
s.expect("name");  //Expecting "name" from the script
s.send("abcd");  //When successful, it sends **abcd** as the input to the script

//Now the script will compare the input(given by java code) with the pre-fed one (the one in the script)

s.expect("hi");  //according to me only **hi** must be displayed,but the java console is taking and displaying all the consecutive echo statements from the script.

你知道为什么会发生这种事吗?还是应该这样做？

Answer 1

好的，它会显示相同的字符串，即使你只显示其中之一。它显示所有连续的字符串。我知道这是expectj.Spawn.expect().的自然行为这就是它的工作原理。

在这种情况下，即使我把-

S.expect(“嗨”)；

我会得到的输出是-

你好，再见

所以没什么好担心的。

Answer 2

查看您的脚本输出，我将输入以下预期

s.expect("hi\nhello\nbye");