发布于 2011-03-25 12:45:46
下面的代码会给你答案。
#include <stdio.h>
int main() {
long x = 0x44434241;
char *y = (char *) &x;
if(strncmp(y,"ABCD",4)){
printf("Big Endian\n");
}else{
printf("little Endian\n");
}
}解释
在little endian中,4个字节被存储为[4th, 3rd , 2nd, 1st]。0x41是A,0x42是B等等。这个字节串被解释为字符串,我们使用strncpy确定字节在机器中的实际排列方式,并确定它的little or big endian。
发布于 2011-03-25 12:54:51
int main()
{
unsigned int i = 0x12345678; // assuming int is 4 bytes.
unsigned char* pc = (unsigned char*) &i;
if (*pc == 0x12)
printf("Big Endian. i = 0x%x, *pc = 0x%x\n", i, *pc);
else if (*pc == 0x78)
printf("Little Endian. i = 0x%x, *pc = 0x%x\n", i, *pc);
return 0;
}https://stackoverflow.com/questions/5432515
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