搜索ABAddressbook iOS SDK

Question

我想在iPhone地址簿中搜索一个特定的电话号码，然后检索联系人名。目前，我正在循环遍历所有联系人，提取多值属性并与值进行比较。这需要花费太多的时间。我读过苹果地址簿指南，他们说：

“完成其他类型的搜索，使用ABAddressBookCopyArrayOfAllPeople函数，然后使用NSArray方法filteredArrayUsingPredicate：”筛选结果。

有人能给我举个例子来说明如何做到这一点吗？

谢谢。

Answer 1

如果你想在有电话号码的联系人中搜索一下，我会告诉你一个建议。

1.取得所有联系人

NSArray *thePeoples = (NSArray*)ABAddressBookCopyArrayOfAllPeople(addressBook);

2.从联系人数组(ThePeoples)创建另一个数组(记录)，

记录: record1，record2，....recordN

记录：{myContactName: phoneNumber:"1234567890"}

3.使用谓词搜索mutableArray(记录)。

NSPredicate * myPredicate = [NSPredicate predicateWithFormat:@"record.phoneNumber contains %@",string];

NSArray * filteredArray = [records filteredArrayUsingPredicate:myPredicate];

这只是解决方案的一个简单示例，请记住phoneNumber是一个multiValue字段。因此，我们将在模型类变量中包含一个作为电话号码的数组。

Answer 2

下面的方法将返回一个数组，该数组包含具有给定电话号码的所有联系人。这个方法花了0.02秒在运行iPhone 5的iOS7上搜索250个联系人。

#import <AddressBook/AddressBook.h>


-(NSArray *)contactsContainingPhoneNumber:(NSString *)phoneNumber {
    /*

     Returns an array of contacts that contain the phone number

     */

    // Remove non numeric characters from the phone number
    phoneNumber = [[phoneNumber componentsSeparatedByCharactersInSet:[[NSCharacterSet alphanumericCharacterSet] invertedSet]] componentsJoinedByString:@""];

    // Create a new address book object with data from the Address Book database
    CFErrorRef error = nil;
    ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, &error);
    if (!addressBook) {
        return [NSArray array];
    } else if (error) {
        CFRelease(addressBook);
        return [NSArray array];
    }

    // Requests access to address book data from the user
    ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {});

    // Build a predicate that searches for contacts that contain the phone number
    NSPredicate *predicate = [NSPredicate predicateWithBlock: ^(id record, NSDictionary *bindings) {
        ABMultiValueRef phoneNumbers = ABRecordCopyValue( (__bridge ABRecordRef)record, kABPersonPhoneProperty);
        BOOL result = NO;
        for (CFIndex i = 0; i < ABMultiValueGetCount(phoneNumbers); i++) {
            NSString *contactPhoneNumber = (__bridge_transfer NSString *) ABMultiValueCopyValueAtIndex(phoneNumbers, i);
            contactPhoneNumber = [[contactPhoneNumber componentsSeparatedByCharactersInSet:[[NSCharacterSet alphanumericCharacterSet] invertedSet]] componentsJoinedByString:@""];
            if ([contactPhoneNumber rangeOfString:phoneNumber].location != NSNotFound) {
                result = YES;
                break;
            }
        }
        CFRelease(phoneNumbers);
        return result;
    }];

    // Search the users contacts for contacts that contain the phone number
    NSArray *allPeople = (NSArray *)CFBridgingRelease(ABAddressBookCopyArrayOfAllPeople(addressBook));
    NSArray *filteredContacts = [allPeople filteredArrayUsingPredicate:predicate];
    CFRelease(addressBook);

    return filteredContacts;
}

Answer 3

用这个。这是我的密码。制作搜索阵列。

        NSLog(@"=====Make People Array with Numbers. Start.");
        peopleWithNumber = [[NSMutableDictionary alloc] init];
        for (int i=0; i < [people count]; i++) {
            NSInteger phoneCount = [self phoneCountAtIndex:i];
            if (phoneCount != 0) {
                NSMutableArray *phoneNumbers = [[NSMutableArray alloc] init];
                for (int j=0 ; j < phoneCount ; j++) {
                    [phoneNumbers addObject:[self phoneNumberAtIndex:i phoneIndex:j]];
                }
                [peopleWithNumber addEntriesFromDictionary:
                 [NSDictionary dictionaryWithObjectsAndKeys:
                  [NSArray arrayWithArray:phoneNumbers],    [self fullNameAtIndex:i], nil]];
            }
        }
        NSLog(@"=====Make People Array with Numbers. End.\n");

搜索方法它(PeopleWithNumber)将比使用数组(人员)更快

“ABAddressBookCopyArrayOfAllPeople(addressBook);”NSArray *people = (NSArray *)

- (NSArray *)searchNamesByNumber:(NSString *)number {

    NSString *predicateString = [NSString stringWithFormat:@"%@[SELF] contains '%@'",@"%@",number];
    NSPredicate *searchPredicate = [NSPredicate predicateWithFormat:predicateString,peopleWithNumber,number];
    NSArray *names = [[peopleWithNumber allKeys] filteredArrayUsingPredicate:searchPredicate];

    return names;
}