我在hibernate中使用postgresql,我想将数据从模板表大容量插入到另一个模板表中。如何在本地查询中这样做对我来说是很清楚的,但在HQL中,我并不真正知道如何达到我的预期结果。我使用http://docs.jboss.org/hibernate/core/3.3/reference/en/html/batch.html#batch-direct的语法来创建我的查询。
@NamedQuery(name="Tile.bulkLoadLevel", query="INSERT INTO Tile (x, y, game, tileOverlay, startTile, blockWalkable, sightBlocking)" +
" SELECT t.x, t.y, :game as game, t.tileOverlay, t.startTile, t.blockWalkable, t.sightBlocking from TemplateQuestTile t")我的Shema:
CREATE TABLE tile
(
x integer NOT NULL,
y integer NOT NULL,
blockwalkable boolean NOT NULL,
sightblocking boolean NOT NULL,
starttile boolean NOT NULL,
imagepath character varying(255) NOT NULL,
gameid bigint NOT NULL,
CONSTRAINT tile_pkey PRIMARY KEY (gameid, x, y)
);简化我的模板:
CREATE TABLE templatequesttile
(
x integer NOT NULL,
y integer NOT NULL,
blockwalkable boolean NOT NULL,
sightblocking boolean NOT NULL,
starttile boolean NOT NULL,
imagepath character varying(255) NOT NULL,
questname character varying(255) NOT NULL,
CONSTRAINT templatequesttile_pkey PRIMARY KEY (questname, questseries, x, y)
)我得到以下错误:
ERROR (SessionFactoryImpl.java:435) - Error in named query: Tile.bulkLoad
org.hibernate.QueryException: number of select types did not match those for insert [INSERT INTO Tile (x, y, game, tileOverlay, startTile, blockWalkable, sightBlocking) SELECT t.x, t.y, :game, t.tileOverlay, t.startTile, t.blockWalkable, t.sightBlocking from net.hq.model.TemplateQuestTile t]
at org.hibernate.hql.ast.tree.IntoClause.validateTypes(IntoClause.java:115)
at org.hibernate.hql.ast.tree.InsertStatement.validate(InsertStatement.java:57)
at org.hibernate.hql.ast.HqlSqlWalker.postProcessInsert(HqlSqlWalker.java:715)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.insertStatement(HqlSqlBaseWalker.java:519)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:261)游戏是一个由序列生成的长标识符的实体。
如您所见,游戏不在我的模板表中,所以我需要强制将游戏id输入到我的查询中。有人知道该怎么做吗?
提前谢谢你的时间,向我问好
PS:如何调用查询:
Query query = em.createNamedQuery("Tile.bulkLoadLevel");
query.setParameter("game", game.getGameid());
int copyiedEntities = query.executeUpdate();实体:
public class Tile implements Serializable{
@Id
private int x;
@Id
private int y;
@Id
@ManyToOne
@JoinColumn(name="gameid")
private Game game;PS:演员也不起作用。
net.hq.process.db.PersistenceTest.setUp(PersistenceTest.java:58) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native
java.lang.ExceptionInInitializerError ) sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java44)在org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15) at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41) at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:27) at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31) at org.junit.runners.ParentRunner.run(ParentRunner.java:236) atorg.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:49) at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run( org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197) )由: java.lang.NullPointerException at java.lang.Class.forName0(原生方法) at java.lang.Class.forName(Class.java:169) at org.hibernate.util.ReflectHelper.classForName(ReflectHelper.java:192) at org.hibernate.type.TypeFactory.heuristicType(TypeFactory.java:279) at org.hibernate.type.TypeFactory.heuristicType(TypeFactory.java:264) at org.hibernate.hql.ast.util.SessionFactoryHelper.findFunctionReturnType(SessionFactoryHelper.java:400) at org.hibernate.hql.ast.util.SessionFactoryHelper.findFunctionReturnType(SessionFactoryHelper.java:392) at org.hibernate.hql.ast.tree.MethodNode.dialectFunction(MethodNode.java:103) at org.hibernate.hql.ast.tree.MethodNode.resolve(MethodNode.java:78) at org.hibernate.hql.ast.HqlSqlWalker.processFunction(HqlSqlWalker.java:979) at org.hibernate.hql.antlr.HqlSqlBaseWalker.functionCall(HqlSqlBaseWalker.java:2529) at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectExpr(HqlSqlBaseWalker.java:2129) at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectExprList(HqlSqlBaseWalker.java:1983) at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectClause(HqlSqlBaseWalker.java:1515) at org.hibernate.hql.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:586)在org.hibernate.hql.antlr.HqlSqlBaseWalker.insertStatement(HqlSqlBaseWalker.java:510) at org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:261) at org.hibernate.hql.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:254) at org.hibernate.hql.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:185) at org.hibernate.hql.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:136) at org.hibernate.engine.query.HQLQueryPlan.(HQLQueryPlan.java:101) at org.hibernate.engine.query.HQLQueryPlan.(HQLQueryPlan.java:80) at org.hibernate.engine.query.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:98) at org.hibernate.impl.SessionFactoryImpl.checkNamedQueries(SessionFactoryImpl.java:562) at org.hibernate.impl.SessionFactoryImpl.(SessionFactoryImpl.java:424) at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1385) atorg.hibernate.cfg.AnnotationConfiguration.buildSessionFactory(AnnotationConfiguration.java:954) at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:891) at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:57) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:48) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:32) at net.hq.util.Db.(Db.java:7) . 17
发布于 2011-01-20 19:37:39
我认为你不能用HQL来表达这个查询。Hibernate文档描述了INSERT ... SELECT ...查询的几个限制,特别是
select_statement可以是任何有效的HQL查询,但必须说明返回类型必须与insert所期望的类型匹配。目前,这是在查询编译期间检查的,而不是允许将检查降到数据库。
由于您不能在查询中表示:game有一种类型的Game,所以该查询的编译永远不会成功。
尝试使用本机SQL查询。
发布于 2011-03-09 19:59:59
试着:
插入Tile (x,y,startTile,blockWalkable,sightBlocking)选择t.x,t.y,cast(游戏作为游戏),t.tileOverlay,t.startTile,t.blockWalkable,t.sightBlocking来自TemplateQuestTile t")
和
query.setEntity(游戏,游戏);
我假设你还有一个名为Tile和x,y,tileOverlay的类.是那个类的属性。在hibernate参考文档中:“INSERT语句的伪语法是: INSERT INSERT EntityName properties_list select_statement”。
关于cast函数,“cast(. as .),其中第二个参数是Hibernate类型的名称”,所以它应该可以工作。
我没有在实体中尝试它,但是它在简单类型(字节、整数.)中工作得很好。
发布于 2013-04-23 18:30:10
我从jorgegm上面的评论中想出了如何做到这一点,我希望这是他的实际答案,因为他最初的回答给出了NPE。
您希望像这样创建查询:
INSERT INTO Tile (x, y, game, tileOverlay, startTile, blockWalkable, sightBlocking)
SELECT t.x, t.y, g, t.tileOverlay, t.startTile, t.blockWalkable, t.sightBlocking
FROM TemplateQuestTile t,
Game g
WHERE g.id = :gameId然后,打电话
query.setParameter("gameId", game.getId());我使用Hibernate 3.6做了这件事,它的工作就像一种魅力。
https://stackoverflow.com/questions/4751135
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