gdb“监视指针”导致了过多的h/w监视点错误

Question

class Message{
    double *val
};

Message** val_msgs;
val_msgs = new Message*[120];
for(int i=0; i<120; i++)
    val_msgs[i]=new Message();

我使用gdb监视消息数据结构中的一个变量。

watch val_msgs[0]->val

但是，我得到了这个错误

(gdb) watch val_msgs[0]->val
Hardware watchpoint 2: this->val_msgs[0]->val
(gdb) c
Continuing.
pingCharmrun (ignored=0x7ffff73751c1) at machine.c:1151
1151    {
Current language:  auto; currently c
(gdb) c
Continuing.
Warning:
Could not insert hardware watchpoint 2.
Could not insert hardware breakpoints:
You may have requested too many hardware breakpoints/watchpoints.

如你所见，我只设置了两个观察点。救命求你了？

Answer 1

对前一个问题的回答可能会有所帮助：gdb problem setting hardware watchpoint/how to set software watchpoint