首页
学习
活动
专区
圈层
工具
发布
社区首页 >问答首页 >非常简单的RogueLike在F#中,使它更“功能”

非常简单的RogueLike在F#中,使它更“功能”
EN

Stack Overflow用户
提问于 2010-12-21 03:22:37
回答 4查看 1.7K关注 0票数 7

对于一个非常非常简单的C#引擎,我有一些现有的RogueLike代码。这是故意天真的,因为我试图尽可能简单地做到最低限度。它所做的就是使用箭头键和System.Console在硬编码地图周围移动@符号:

代码语言:javascript
复制
//define the map
var map = new List<string>{
  "                                        ",
  "                                        ",
  "                                        ",
  "                                        ",
  "    ###############################     ",
  "    #                             #     ",
  "    #         ######              #     ",
  "    #         #    #              #     ",
  "    #### #### #    #              #     ",
  "       # #  # #    #              #     ",
  "       # #  # #    #              #     ",
  "    #### #### ######              #     ",
  "    #              =              #     ",
  "    #              =              #     ",
  "    ###############################     ",
  "                                        ",
  "                                        ",
  "                                        ",
  "                                        ",
  "                                        "
};

//set initial player position on the map
var playerX = 8;
var playerY = 6;

//clear the console
Console.Clear();

//send each row of the map to the Console
map.ForEach( Console.WriteLine );

//create an empty ConsoleKeyInfo for storing the last key pressed
var keyInfo = new ConsoleKeyInfo( );

//keep processing key presses until the player wants to quit
while ( keyInfo.Key != ConsoleKey.Q ) {
  //store the player's current location
  var oldX = playerX;
  var oldY = playerY;

  //change the player's location if they pressed an arrow key
  switch ( keyInfo.Key ) {
    case ConsoleKey.UpArrow:
      playerY--;
      break;
    case ConsoleKey.DownArrow:
      playerY++;
      break;
    case ConsoleKey.LeftArrow:
      playerX--;
      break;
    case ConsoleKey.RightArrow:
      playerX++;
      break;
  }

  //check if the square that the player is trying to move to is empty
  if( map[ playerY ][ playerX ] == ' ' ) {
    //ok it was empty, clear the square they were standing on before
    Console.SetCursorPosition( oldX, oldY );
    Console.Write( ' ' );
    //now draw them at the new square
    Console.SetCursorPosition( playerX, playerY );
    Console.Write( '@' );
  } else {
    //they can't move there, change their location back to the old location
    playerX = oldX;
    playerY = oldY;
  }

  //wait for them to press a key and store it in keyInfo
  keyInfo = Console.ReadKey( true );
}

我在F#中玩这个游戏,最初我试图用函数概念来编写它,但结果发现我有点过头了,所以我做了一个很直接的端口--它实际上不是一个F#程序(尽管它编译和运行)--它是一个用F#语法编写的过程程序:

代码语言:javascript
复制
open System

//define the map
let map = [ "                                        ";
            "                                        ";
            "                                        ";
            "                                        ";
            "    ###############################     ";
            "    #                             #     ";
            "    #         ######              #     ";
            "    #         #    #              #     ";
            "    #### #### #    #              #     ";
            "       # #  # #    #              #     ";
            "       # #  # #    #              #     ";
            "    #### #### ######              #     ";
            "    #              =              #     ";
            "    #              =              #     ";
            "    ###############################     ";
            "                                        ";
            "                                        ";
            "                                        ";
            "                                        ";
            "                                        " ]

//set initial player position on the map
let mutable playerX = 8
let mutable playerY = 6

//clear the console
Console.Clear()

//send each row of the map to the Console
map |> Seq.iter (printfn "%s")

//create an empty ConsoleKeyInfo for storing the last key pressed
let mutable keyInfo = ConsoleKeyInfo()

//keep processing key presses until the player wants to quit
while not ( keyInfo.Key = ConsoleKey.Q ) do
    //store the player's current location
    let mutable oldX = playerX
    let mutable oldY = playerY

    //change the player's location if they pressed an arrow key
    if keyInfo.Key = ConsoleKey.UpArrow then
        playerY <- playerY - 1
    else if keyInfo.Key = ConsoleKey.DownArrow then
        playerY <- playerY + 1
    else if keyInfo.Key = ConsoleKey.LeftArrow then
        playerX <- playerX - 1
    else if keyInfo.Key = ConsoleKey.RightArrow then
        playerX <- playerX + 1

    //check if the square that the player is trying to move to is empty
    if map.Item( playerY ).Chars( playerX ) = ' ' then
        //ok it was empty, clear the square they were standing on
        Console.SetCursorPosition( oldX, oldY )
        Console.Write( ' ' )
        //now draw them at the new square 
        Console.SetCursorPosition( playerX, playerY )
        Console.Write( '@' )
    else
        //they can't move there, change their location back to the old location
        playerX <- oldX
        playerY <- oldY

    //wait for them to press a key and store it in keyInfo
    keyInfo <- Console.ReadKey( true )

所以我的问题是,我需要学些什么才能更有功能地重写它,你能给我一些提示,一个模糊的概述,诸如此类的事情吗?

我宁愿往正确的方向推进,而不只是看到一些代码,但是如果这是你向我解释的最简单的方法,那么就好了,但在这种情况下,你能解释一下“为什么”,而不是“如何”吗?

EN

回答 4

Stack Overflow用户

回答已采纳

发布于 2010-12-21 17:38:41

游戏编程一般会测试你管理复杂性的能力。我发现函数式编程鼓励您将解决的问题分解成更小的部分。

您要做的第一件事是通过分离所有不同的关注点,将脚本转换为一组函数。我知道这听起来很傻,但是这样做会使代码更有功能(双关意)。你主要关心的是国家管理。我使用一个记录来管理位置状态,使用一个元组来管理运行状态。随着代码变得更高级,您将需要对象来干净地管理状态。

尝试加入更多的这个游戏,并继续打破功能,因为他们的成长。最终,您将需要对象来管理所有函数。

在游戏编程注意事项中,不要将状态更改为其他状态,如果测试失败,则将其更改回。你想要最小的状态变化。因此,例如,在下面,我计算newPosition,然后只在这个未来的位置通过时更改playerPosition

代码语言:javascript
复制
open System

// use a third party vector class for 2D and 3D positions
// or write your own for pratice
type Pos = {x: int; y: int} 
    with
    static member (+) (a, b) =
        {x = a.x + b.x; y = a.y + b.y}

let drawBoard map =
    //clear the console
    Console.Clear()
    //send each row of the map to the Console
    map |> List.iter (printfn "%s")

let movePlayer (keyInfo : ConsoleKeyInfo) =
    match keyInfo.Key with
    | ConsoleKey.UpArrow -> {x = 0; y = -1}
    | ConsoleKey.DownArrow -> {x = 0; y = 1}
    | ConsoleKey.LeftArrow -> {x = -1; y = 0}
    | ConsoleKey.RightArrow  -> {x = 1; y = 0}
    | _ -> {x = 0; y = 0}

let validPosition (map:string list) position =
    map.Item(position.y).Chars(position.x) = ' '

//clear the square player was standing on
let clearPlayer position =
    Console.SetCursorPosition(position.x, position.y)
    Console.Write( ' ' )

//draw the square player is standing on
let drawPlayer position =
    Console.SetCursorPosition(position.x, position.y)
    Console.Write( '@' )

let takeTurn map playerPosition =
    let keyInfo = Console.ReadKey true
    // check to see if player wants to keep playing
    let keepPlaying = keyInfo.Key <> ConsoleKey.Q
    // get player movement from user input
    let movement = movePlayer keyInfo
    // calculate the players new position
    let newPosition = playerPosition + movement
    // check for valid move
    let validMove = newPosition |> validPosition map
    // update drawing if move was valid
    if validMove then
        clearPlayer playerPosition
        drawPlayer newPosition
    // return state
    if validMove then
        keepPlaying, newPosition
    else
        keepPlaying, playerPosition

// main game loop
let rec gameRun map playerPosition =
    let keepPlaying, newPosition = playerPosition |> takeTurn map 
    if keepPlaying then
        gameRun map newPosition

// setup game
let startGame map playerPosition =
    drawBoard map
    drawPlayer playerPosition
    gameRun map playerPosition


//define the map
let map = [ "                                        ";
            "                                        ";
            "                                        ";
            "                                        ";
            "    ###############################     ";
            "    #                             #     ";
            "    #         ######              #     ";
            "    #         #    #              #     ";
            "    #### #### #    #              #     ";
            "       # #  # #    #              #     ";
            "       # #  # #    #              #     ";
            "    #### #### ######              #     ";
            "    #              =              #     ";
            "    #              =              #     ";
            "    ###############################     ";
            "                                        ";
            "                                        ";
            "                                        ";
            "                                        ";
            "                                        " ]

//initial player position on the map
let playerPosition = {x = 8; y = 6}

startGame map playerPosition
票数 9
EN

Stack Overflow用户

发布于 2010-12-21 12:55:37

这是一个不错的小游戏:-)。在函数式编程中,您可能希望避免使用可变状态(正如其他人所指出的那样),您还希望将游戏的核心编写为没有任何副作用的函数(例如从控制台读取和写入)。

游戏的关键部分是控制位置的功能。您可以重构代码,使其具有类型签名的函数:

代码语言:javascript
复制
val getNextPosition : (int * int) -> ConsoleKey -> option<int * int>

如果游戏退出,该函数将返回None。否则,它将返回Some(posX, posY),其中posXposY@符号的新位置。通过进行更改,您可以得到一个很好的函数核心,并且函数getNextPosition也很容易测试(因为它总是对相同的输入返回相同的结果)。

要使用该函数,最好的选择是使用递归编写循环。主要功能的结构如下所示:

代码语言:javascript
复制
let rec playing pos =
  match getNextPosition pos (Console.ReadKey()) with
  | None -> () // Quit the game
  | Some(newPos) ->
     // This function redraws the screen (this is a side-effect,
     // but it is localized to a single function)
     redrawScreen pos newPos
     playing newPos
票数 4
EN

Stack Overflow用户

发布于 2010-12-21 03:32:22

作为一个游戏,使用控制台,这里有状态和副作用,这是固有的。但你要做的关键是消除那些变项。使用递归循环而不是while循环将有助于您这样做,因为这样您就可以将状态作为参数传递给每个递归调用。除此之外,我在这里看到的利用F#特性的主要方法是使用模式匹配,而不是if/ see语句和开关,尽管这主要是一种美学上的改进。

票数 2
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/4495993

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档