在Hibernate中使用列表时放置列表索引

Question

我使用的是一个集合，但现在由于小部件的限制，我需要使用list.一个使用A集的映射文件示例和一个列表如下所示。谁能帮我把列表索引。我有点困惑。

**Attribute Mapping File using Set**
?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated Dec 16, 2010 5:25:09 AM by Hibernate Tools 3.4.0.Beta1 -->
<hibernate-mapping>
    <class name="h.Attribute" table="ATTRIBUTE">
        <id name="AttributeId" type="long">
            <column name="ATTRIBUTEID" />
            <generator class="native" />
        </id>
        <property name="AttributeName" type="java.lang.String">
            <column name="ATTRIBUTENAME" />
        </property>
        <set name="Options" table="ATTRIBUTEOPTION" inverse="false"  cascade="all" lazy="true">
            <key>
                <column name="ATTRIBUTEID" />
            </key>
            <one-to-many class="h.AttributeOption" />
        </set>
    </class>
</hibernate-mapping>



 **Category Mapping File using Set**
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated Dec 16, 2010 8:37:02 AM by Hibernate Tools 3.4.0.Beta1 -->
<hibernate-mapping>
    <class name="h.Category" table="CATEGORY">
        <id name="CategoryId" type="long">
            <column name="CATEGORYID" />
            <generator class="native" />
        </id>
        <property name="CategoryName" type="java.lang.String">
            <column name="CATEGORYNAME" />
        </property>

        <many-to-one name="ParentCategory" class="h.Category">
            <column name="PARENT_CATEGORY_ID" />
        </many-to-one>

        <set name="SubCategory" lazy="true" cascade="all-delete-orphan" inverse="true">
            <key>
                <column name="PARENT_CATEGORY_ID" />
            </key>
            <one-to-many class="h.Category" />
        </set>

        <set name="AllAttributes" table="ATTRIBUTE" inverse="false" lazy="true"  cascade="all">
            <key>
                <column name="CATEGORYID" />
            </key>
            <one-to-many class="h.Attribute" />
        </set>

    </class>
</hibernate-mapping>

类别映射文件使用没有列表索引的列表

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated Dec 17, 2010 2:10:50 AM by Hibernate Tools 3.4.0.Beta1 -->
<hibernate-mapping>
    <class name="h.Category" table="CATEGORY">
        <id name="CategoryId" type="long">
            <column name="CATEGORYID" />
            <generator class="assigned" />
        </id>
        <property name="CategoryName" type="java.lang.String">
            <column name="CATEGORYNAME" />
        </property>
        <many-to-one name="ParentCategory" class="h.Category" fetch="join">
            <column name="PARENTCATEGORY" />
        </many-to-one>
        <list name="SubCategory" inverse="false" table="CATEGORY" lazy="true">
            <key>
                <column name="CATEGORYID" />
            </key>
            <list-index></list-index>
            <one-to-many class="h.Category" />
        </list>
        <list name="AllAttributes" inverse="false" table="ATTRIBUTE" lazy="true"  cascade="all">
            <key>
                <column name="CATEGORYID" />
            </key>
            <list-index></list-index>
            <one-to-many class="h.Attribute" />
        </list>
    </class>
</hibernate-mapping>

使用非列表索引的属性映射文件

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated Dec 17, 2010 2:10:50 AM by Hibernate Tools 3.4.0.Beta1 -->
<hibernate-mapping>
    <class name="h.Attribute" table="ATTRIBUTE">
        <id name="AttributeId" type="long">
            <column name="ATTRIBUTEID" />
            <generator class="assigned" />
        </id>
        <property name="AttributeName" type="java.lang.String">
            <column name="ATTRIBUTENAME" />
        </property>
        <list name="Options" inverse="false" table="ATTRIBUTEOPTION" lazy="true" cascade="all">
            <key>
                <column name="ATTRIBUTEID" />
            </key>
            <list-index></list-index>
            <one-to-many class="h.AttributeOption" />
        </list>
    </class>
</hibernate-mapping>

Answer 1

读取Hibernate参考: 6.2.3。索引集合

例如：

    <list name="whatEver">
        <key column="whatEver_fk"/>
        <index column="idx"/>
        <one-to-many class="WhatEver"/>
    </list>

Answer 2

Hibernate 3.3参考表示“数组或列表的索引始终是整型.”，并且“如果您的表没有索引列，并且仍然希望使用 list 作为属性类型，则可以将该属性映射为Hibernate <bag>”。

一个袋子的例子：

<bag name="options" table="ATTRIBUTEOPTION" order-by="column_name asc|desc" inverse="true" lazy="true" fetch="select">
    <key column="ATTRIBUTEID" />
    <one-to-many class="h.AttributeOption" />
</bag>

Answer 3

我认为您应该在POJO中提供"index“属性，以便为其创建一对多的关系。

<list name="whatEver">
        <key column="whatEver_fk"/>
        <index column="idx"/>
        <one-to-many class="WhatEver_Class"/>
    </list>

在上面的例子中，"WhatEver_Class“POJO应该有一个索引属性，它的hbm文件应该有下面的属性标记。

<property name="index" type="long" insert="false" update="false">
            <column name="idx" />
        </property>