嗨,我用伏地魔来存储我的数据。我的关键是一个单词,值是单词和URL出现的次数。例如:
key :question
value: 10, www.stackoverflow.com我使用Json对象来把我的值。我的代码如下所示
import org.json.JSONObject;
import com.metaparadigm.jsonrpc.JSONSerializer;
import voldemort.client.ClientConfig;
import voldemort.client.SocketStoreClientFactory;
import voldemort.client.StoreClient;
import voldemort.client.StoreClientFactory;
public class ClientExample {
public static void main (String [] args) {
String bootstrapUrl = "tcp://localhost:6666";
ClientConfig cc = new ClientConfig ();
cc.setBootstrapUrls (bootstrapUrl);
String[] valuePair = new String[2];
int val = 1;
StoreClientFactory factory = new SocketStoreClientFactory (cc);
StoreClient client = factory.getStoreClient("test");
JSONObject json = new JSONObject();
json.put("occurence",val);
json.put("url", "www.cnn.com");
client.put("foo", json);
}
} 我的store.xml看起来像这样
<stores>
<store>
<name>test</name>
<persistence>bdb</persistence>
<routing>client</routing>
<replication-factor>1</replication-factor>
<required-reads>1</required-reads>
<required-writes>1</required-writes>
<key-serializer>
<type>string</type>
</key-serializer>
<value-serializer>
<type>java-serialization</type>
<schema-info>"Compount Types"</schema-info>
</value-serializer>
</store>
</stores> 当我试图运行代码时,我得到以下异常:**
线程"main“voldemort.serialization.SerializationException: java.io.NotSerializableException: org.json.JSONObject at voldemort.serialization.ObjectSerializer.toBytes(ObjectSerializer.java:47) at voldemort.store.serialized.SerializingStore.put(SerializingStore.java:109) at voldemort.store.DelegatingStore.put(DelegatingStore.java:68) at voldemort.client.DefaultStoreClient.put(DefaultStoreClient.java:208) at voldemort.client.DefaultStoreClient.put(DefaultStoreClient.java:193) at ClientExample.main(ClientExample.java:27)中的
异常by: java.io.ObjectOutputStream.writeObject0(Unknown Source中的java.io.NotSerializableException: org.json.JSONObject )在voldemort.serialization.ObjectSerializer.toBytes(ObjectSerializer.java:44)上)
**
您能告诉我如何提前序列化JSON object.Thanks吗?
发布于 2011-05-12 06:34:28
请看一下Gson库。它为对象映射和序列化做了很好的JSON。
发布于 2014-08-15 12:14:16
迟答,但我自己正在寻找,我已经找到了解决办法。澄清一下,我的问题是我的类包含一个org.json.JSONobject,不能序列化,这是在Android对象中传递对象的必要步骤。
来修饰。
如下所示:
private void writeObject(ObjectOutputStream oos) throws IOException{
oos.defaultWriteObject();
oos.writeChars(_jsonObject.toString());
}
private void readObject(ObjectInputStream ois) throws ClassNotFoundException, IOException {
ois.defaultReadObject();
loadJSON(ois.readUTF());
}我发现这比更换图书馆容易得多。
发布于 2010-11-24 00:22:40
使用.toString()方法JSONObject来获取文本。
https://stackoverflow.com/questions/4262390
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