jQuery .append (函数(索引，html){.})问题

Question

假设我们有这个不明身份的DIV

  <div class="class-occurs-many-times-on-page">foo</div>

我们想在它后面放置另一个不明的DIV，它包含几十个或数百个跨元素：

<div class="a-class-that-occurs-many-times-on-page">foo</div>
<div class="another-class-that-occurs-many-times-on-page">
        <span class="latin">lorem</span><span class="latin">ipse</span>
        <span class="swedish-chef">føø</span><span class="swedish-chef">bår</span>
        .
        .
        .
        <span>...</span>
</div>

我们已经添加了第一个未识别的DIV，并希望以这样的方式添加跨区容器DIV：

 values = [{word: "lorem", cls: "latin"}, {word: "ipse", cls: "latin"},
 {word:"føø",cls:"swedish-chef"}, {word:"bår",cls:"swedish-chef"}];

 $("#" +  someParentElement).append(
     $("<div></div>").addClass("a-class-that-occurs-many-times-on-page").text("foo").after(

            $("<div></div>").addClass("another-class-that-occurs-many-times-on-page").append(
                 function(index, html){                    
                     // how to wrap each value in the values array in a span
                     // and inject each of those spans into this DIV?

                 }
            )

      )


 );

这种方法可行吗?如果是这样，那么.append()方法调用中的函数在值数组的每一次迭代中都需要做什么，如果目标是将数组中的每个值封装在一个SPAN中并将其注入容器中？

谢谢

Answer 1

values = [{word: "lorem", cls: "latin"}, {word: "ipse", cls: "latin"}, {word:"føø",cls:"swedish-chef"}, {word:"bår",cls:"swedish-chef"}],
len    = values.length,
$ctn   = $('<div/>', {
     class:   'another-class-that-occurs-many-times-on-page'
}),
buildarr = [];

while(len--){
    buildarr.push('<span>');
    buildarr.push(values[len].word);
    buildarr.push(values[len].cls);
    buildarr.push('</span>');
}

$ctn.append(buildarr.join('')).appendTo(document.body);

这只是一个建议，好像你可以完成这样的任务。它假设我们必须填充数组的顺序是无关的(用最快的方式循环，reversed while)。如果订单很重要，请使用standard for loop。