首页
学习
活动
专区
圈层
工具
发布
社区首页 >问答首页 >多边形轮廓线上的边并不总是正确的

多边形轮廓线上的边并不总是正确的
EN

Stack Overflow用户
提问于 2010-06-14 16:36:30
回答 5查看 2.2K关注 0票数 6

我使用下面的算法生成四边形,然后呈现成这样的轮廓

http://img810.imageshack.us/img810/8530/uhohz.png

在图像上看到的问题是,有时线条太薄,而它们应该总是相同的宽度。我的算法找到了第一个顶点的4顶点,然后下一个顶点的上2顶点是前一个顶点的下2。这创造了连接的线路,但它似乎并不总是有效的。我怎么才能解决这个问题?

这是我的算法:

代码语言:javascript
复制
 void OGLENGINEFUNCTIONS::GenerateLinePoly(const std::vector<std::vector<GLdouble>> &input,
                          std::vector<GLfloat> &output, int width)
 {
     output.clear();

     if(input.size() < 2)
     {
         return;
     }

     int temp;
     float dirlen;
     float perplen;
     POINTFLOAT start;
     POINTFLOAT end;
     POINTFLOAT dir;
     POINTFLOAT ndir;
     POINTFLOAT perp;
     POINTFLOAT nperp;

     POINTFLOAT perpoffset;
     POINTFLOAT diroffset;

     POINTFLOAT p0, p1, p2, p3;

     for(unsigned int i = 0; i < input.size() - 1; ++i)
     {

         start.x = static_cast<float>(input[i][0]);
         start.y = static_cast<float>(input[i][1]);

         end.x = static_cast<float>(input[i + 1][0]);
         end.y = static_cast<float>(input[i + 1][1]);

         dir.x = end.x - start.x;
         dir.y = end.y - start.y;

         dirlen = sqrt((dir.x * dir.x) + (dir.y * dir.y));

         ndir.x = static_cast<float>(dir.x * 1.0 / dirlen);
         ndir.y = static_cast<float>(dir.y * 1.0 / dirlen);

         perp.x = dir.y;
         perp.y = -dir.x;

         perplen = sqrt((perp.x * perp.x) + (perp.y * perp.y));

         nperp.x = static_cast<float>(perp.x * 1.0 / perplen);
         nperp.y = static_cast<float>(perp.y * 1.0 / perplen);

         perpoffset.x = static_cast<float>(nperp.x * width * 0.5);
         perpoffset.y = static_cast<float>(nperp.y * width * 0.5);

         diroffset.x = static_cast<float>(ndir.x * 0 * 0.5);
         diroffset.y = static_cast<float>(ndir.y * 0 * 0.5);

            // p0 = start + perpoffset - diroffset
            // p1 = start - perpoffset - diroffset
            // p2 = end + perpoffset + diroffset
            // p3 = end - perpoffset + diroffset 

         p0.x = start.x + perpoffset.x - diroffset.x;
         p0.y = start.y + perpoffset.y - diroffset.y;

         p1.x = start.x - perpoffset.x - diroffset.x;
         p1.y = start.y - perpoffset.y - diroffset.y;

         if(i > 0)
         {
             temp = (8 * (i - 1));
             p2.x = output[temp + 2];
             p2.y = output[temp + 3];
             p3.x = output[temp + 4];
             p3.y = output[temp + 5];

         }
         else
         {
             p2.x = end.x + perpoffset.x + diroffset.x;
             p2.y = end.y + perpoffset.y + diroffset.y;

             p3.x = end.x - perpoffset.x + diroffset.x;
             p3.y = end.y - perpoffset.y + diroffset.y;
         }



         output.push_back(p2.x);
         output.push_back(p2.y);
         output.push_back(p0.x);
         output.push_back(p0.y);
         output.push_back(p1.x);
         output.push_back(p1.y);
         output.push_back(p3.x);
         output.push_back(p3.y);

     }
 }

编辑:

代码语言:javascript
复制
 POINTFLOAT multiply(const POINTFLOAT &a, float b)
 {
     POINTFLOAT result;
     result.x = a.x * b;
     result.y = a.y * b;
     return result;
 }

 POINTFLOAT normalize(const POINTFLOAT &a)
 {
     return multiply(a, 1.0f / sqrt(a.x * a.x + a.y * a.y));
 }


 POINTFLOAT slerp2d( const POINTFLOAT v0, 
                     const POINTFLOAT v1, float t )
 {
     float dot = (v0.x * v1.x + v1.y * v1.y);
     if( dot < -1.0f ) dot = -1.0f;
     if( dot > 1.0f ) dot = 1.0f;

     float theta_0 = acos( dot );
     float theta = theta_0 * t;

     POINTFLOAT v2;
     v2.x = -v0.y;
     v2.y = v0.x;

     POINTFLOAT result;
     result.x = v0.x * cos(theta) + v2.x * sin(theta);
     result.y = v0.y * cos(theta) + v2.y * sin(theta);

     return result;
 }

 void OGLENGINEFUNCTIONS::GenerateLinePoly(const std::vector<std::vector<GLdouble> > &input,
                          std::vector<GLfloat> &output, int width)
 {
     output.clear();

     if(input.size() < 2)
     {
         return;
     }

     float w = width / 2.0f;

     //glBegin(GL_TRIANGLES);
     for( size_t i = 0; i < input.size()-1; ++i )
     {
         POINTFLOAT cur;
         cur.x = input[i][0];
         cur.y = input[i][1];


         POINTFLOAT nxt;
         nxt.x = input[i+1][0];
         nxt.y = input[i+1][1];

         POINTFLOAT b;
         b.x = nxt.x - cur.x;
         b.y = nxt.y - cur.y;

         b = normalize(b);



         POINTFLOAT b_perp;
         b_perp.x = -b.y;
         b_perp.y = b.x;


         POINTFLOAT p0;
         POINTFLOAT p1;
         POINTFLOAT p2;
         POINTFLOAT p3;

         p0.x = cur.x + b_perp.x * w;
         p0.y = cur.y + b_perp.y * w;

         p1.x = cur.x - b_perp.x * w;
         p1.y = cur.y - b_perp.y * w;

         p2.x = nxt.x + b_perp.x * w;
         p2.y = nxt.y + b_perp.y * w;

         p3.x = nxt.x - b_perp.x * w;
         p3.y = nxt.y - b_perp.y * w;

         output.push_back(p0.x);
         output.push_back(p0.y);
         output.push_back(p1.x);
         output.push_back(p1.y);
         output.push_back(p2.x);
         output.push_back(p2.y);

         output.push_back(p2.x);
         output.push_back(p2.y);
         output.push_back(p1.x);
         output.push_back(p1.y);
         output.push_back(p3.x);
         output.push_back(p3.y);



         // only do joins when we have a prv
         if( i == 0 ) continue;

         POINTFLOAT prv;
         prv.x = input[i-1][0];
         prv.y = input[i-1][1];

         POINTFLOAT a;
         a.x = prv.x - cur.x;
         a.y = prv.y - cur.y;

         a = normalize(a);

         POINTFLOAT a_perp;
         a_perp.x = a.y;
         a_perp.y = -a.x;

         float det = a.x * b.y - b.x * a.y;
         if( det > 0 )
         {
             a_perp.x = -a_perp.x;
             a_perp.y = -a_perp.y;

             b_perp.x = -b_perp.x;
             b_perp.y = -b_perp.y;
         }

         // TODO: do inner miter calculation

         // flip around normals and calculate round join points
         a_perp.x = -a_perp.x;
         a_perp.y = -a_perp.y;

         b_perp.x = -b_perp.x;
         b_perp.y = -b_perp.y;

         size_t num_pts = 4;

         std::vector< POINTFLOAT> round( 1 + num_pts + 1 );
         POINTFLOAT nc;
         nc.x = cur.x + (a_perp.x * w);
         nc.y = cur.y + (a_perp.y * w);

         round.front() = nc;

         nc.x = cur.x + (b_perp.x * w);
         nc.y = cur.y + (b_perp.y * w);

         round.back() = nc;

         for( size_t j = 1; j < num_pts+1; ++j )
         {
             float t = (float)j / (float)(num_pts + 1);
             if( det > 0 )
             {
                 POINTFLOAT nin;
                 nin = slerp2d( b_perp, a_perp, 1.0f-t );
                 nin.x *= w;
                 nin.y *= w;

                 nin.x += cur.x;
                 nin.y += cur.y;

                 round[j] = nin;
             }
             else
             {
                 POINTFLOAT nin;
                 nin = slerp2d( a_perp, b_perp, t );
                 nin.x *= w;
                 nin.y *= w;

                 nin.x += cur.x;
                 nin.y += cur.y;

                 round[j] = nin;
             }
         }

         for( size_t j = 0; j < round.size()-1; ++j )
         {

             output.push_back(cur.x);
             output.push_back(cur.y);

             if( det > 0 )
             {
                 output.push_back(round[j + 1].x);
                 output.push_back(round[j + 1].y);
                 output.push_back(round[j].x);
                 output.push_back(round[j].y);
             }
             else
             {

                 output.push_back(round[j].x);
                 output.push_back(round[j].y);

                 output.push_back(round[j + 1].x);
                 output.push_back(round[j + 1].y);
             }
         }
     }
 }
EN

回答 5

Stack Overflow用户

回答已采纳

发布于 2010-06-17 04:58:43

需要编写本征,但是核心操作应该很容易映射到您使用的任何向量类。

代码语言:javascript
复制
// v0 and v1 are normalized
// t can vary between 0 and 1
// http://number-none.com/product/Understanding%20Slerp,%20Then%20Not%20Using%20It/
Vector2f slerp2d( const Vector2f& v0, const Vector2f& v1, float t )
{
    float dot = v0.dot(v1);
    if( dot < -1.0f ) dot = -1.0f;
    if( dot > 1.0f ) dot = 1.0f;

    float theta_0 = acos( dot );
    float theta = theta_0 * t;

    Vector2f v2( -v0.y(), v0.x() );

    return ( v0*cos(theta) + v2*sin(theta) );
}


void glPolyline( const vector<Vector2f>& polyline, float width )
{
    if( polyline.size() < 2 ) return;
    float w = width / 2.0f;

    glBegin(GL_TRIANGLES);
    for( size_t i = 0; i < polyline.size()-1; ++i )
    {
        const Vector2f& cur = polyline[ i ];
        const Vector2f& nxt = polyline[i+1];

        Vector2f b = (nxt - cur).normalized();
        Vector2f b_perp( -b.y(), b.x() );

        Vector2f p0( cur + b_perp*w );
        Vector2f p1( cur - b_perp*w );
        Vector2f p2( nxt + b_perp*w );
        Vector2f p3( nxt - b_perp*w );

        // first triangle
        glVertex2fv( p0.data() );
        glVertex2fv( p1.data() );
        glVertex2fv( p2.data() );
        // second triangle
        glVertex2fv( p2.data() );
        glVertex2fv( p1.data() );
        glVertex2fv( p3.data() );

        // only do joins when we have a prv
        if( i == 0 ) continue;

        const Vector2f& prv = polyline[i-1];
        Vector2f a = (prv - cur).normalized();
        Vector2f a_perp( a.y(), -a.x() );

        float det = a.x()*b.y() - b.x()*a.y();
        if( det > 0 )
        {
            a_perp = -a_perp;
            b_perp = -b_perp;
        }

        // TODO: do inner miter calculation

        // flip around normals and calculate round join points
        a_perp = -a_perp;
        b_perp = -b_perp;

        size_t num_pts = 4;
        vector< Vector2f > round( 1 + num_pts + 1 );
        for( size_t j = 0; j <= num_pts+1; ++j )
        {
            float t = (float)j/(float)(num_pts+1);
            if( det > 0 )
                round[j] = cur + (slerp2d( b_perp, a_perp, 1.0f-t ) * w);
            else
                round[j] = cur + (slerp2d( a_perp, b_perp, t ) * w);
        }

        for( size_t j = 0; j < round.size()-1; ++j )
        {
            glVertex2fv( cur.data() );
            if( det > 0 )
            {
                glVertex2fv( round[j+1].data() );
                glVertex2fv( round[j+0].data() );
            }
            else
            {
                glVertex2fv( round[j+0].data() );
                glVertex2fv( round[j+1].data() );
            }
        }
    }
    glEnd();
}

编辑:截图:

票数 9
EN

Stack Overflow用户

发布于 2010-06-14 22:33:09

那麽:

  1. 把每一条线画到拐角处
  2. 在与角垂直的每个角处画一条额外的线。

如下所示:

alt文本http://www.geekops.co.uk/photos/0000-00-02%20%28Forum%20images%29/CorrectAngleDrawing.png

蓝色/红色代表你想连接的两条线。虚线绿色是你为使拐角处光滑而加的额外的一个。上面的图片显示,内容将被剪裁非常轻微的锐角。如果这是个问题,你可以把这两条连接线进一步向外延伸,然后把额外的线画得更远。

编辑我发现了我的建议中的一个缺陷。你在那里有一些凹的部分,它们根本不能正常工作。在这种情况下,你会想做一些事情,比如画一个倒角的边缘,而不是:

alt文本http://www.geekops.co.uk/photos/0000-00-02%20%28Forum%20images%29/CorrectAngleDrawing2.png

Edit2我已经对我之前发布的代码做了一些调试。下列各点应更有用处:

代码语言:javascript
复制
    // PolygonOutlineGen.cpp : A small program to calculate 4-point polygons 
// to surround an input polygon.

#include <vector>
#include <math.h>
#include <iostream>
#include <iomanip>

using namespace std;

// Describe some structures etc. so the code will compile without 
// requiring the GL libraries.
typedef double GLdouble;
typedef float GLfloat;
typedef struct POINTFLOAT
{
    float x;
    float y;
} POINTFLOAT;

// A function to generate two coordinates representing the start and end
// of a line perpendicular to start/end, offset by 'width' units.
void GenerateOffsetLineCoords(
    POINTFLOAT start, 
    POINTFLOAT end, 
    int width,
    POINTFLOAT& perpStart,
    POINTFLOAT& perpEnd)
{
    float dirlen;
    POINTFLOAT dir;
    POINTFLOAT ndir;
    POINTFLOAT nperp;
    POINTFLOAT perpoffset;

    // Work out the offset for a parallel line which is space outwards by 'width' units
    dir.x = end.x - start.x;
    dir.y = end.y - start.y;
    dirlen = sqrt((dir.x * dir.x) + (dir.y * dir.y));
    ndir.x = static_cast<float>(dir.x * 1.0 / dirlen);
    ndir.y = static_cast<float>(dir.y * 1.0 / dirlen);
    nperp.x = -ndir.y;
    nperp.y = ndir.x;
    perpoffset.x = static_cast<float>(nperp.x * width);
    perpoffset.y = static_cast<float>(nperp.y * width);

    // Calculate the offset coordinates for the new line
    perpStart.x = start.x + perpoffset.x;
    perpStart.y = start.y + perpoffset.y;
    perpEnd.x = end.x + perpoffset.x;
    perpEnd.y = end.y + perpoffset.y;
}

// Function to generate quads of coordinate pairs to surround the 'input'
// polygon.
void GenerateLinePoly(const std::vector<std::vector<GLdouble>> &input,
    std::vector<GLfloat> &output, int width)
{
    // Make sure we have something to produce an outline for and that it's not contaminated with previous results
    output.clear();
    if(input.size() < 2)
    {
        return;
    }

    // Storage for the pairs of lines which form sections of the outline
    POINTFLOAT line1_start;
    POINTFLOAT line1_end;
    POINTFLOAT line2_start;
    POINTFLOAT line2_end;

    // Storage for the outer edges of the quads we'll be generating
    POINTFLOAT line1offset_start;
    POINTFLOAT line1offset_end;
    POINTFLOAT line2offset_start;
    POINTFLOAT line2offset_end;

    // Storage for the line we'll use to make smooth joints between polygon sections.
    POINTFLOAT joininglineoffset_start;
    POINTFLOAT joininglineoffset_end;

    for(unsigned int i = 0; i < input.size() - 2; ++i)
    {
        // Grab the raw line input for the first line or if we've already done one, just re-use the last results
        if( i == 0 )
        {
            line1_start.x = static_cast<float>(input[i][0]);
            line1_start.y = static_cast<float>(input[i][1]);
            line1_end.x = static_cast<float>(input[i + 1][0]);
            line1_end.y = static_cast<float>(input[i + 1][1]);

            GenerateOffsetLineCoords(line1_start, line1_end, width, line1offset_start, line1offset_end);
        }
        else
        {
            line1_start = line2_start;
            line1offset_start = line2offset_start;
            line1_end = line2_end;
            line1offset_end = line2offset_end;
        }

        // Grab the second line and work out the coords of it's offset 
        line2_start.x = static_cast<float>(input[i+1][0]);
        line2_start.y = static_cast<float>(input[i+1][1]);
        line2_end.x = static_cast<float>(input[i+2][0]);
        line2_end.y = static_cast<float>(input[i+2][1]);
        GenerateOffsetLineCoords(line2_start, line2_end, width, line2offset_start, line2offset_end);

        // Grab the offset for the line which joins the open end
        GenerateOffsetLineCoords(line2offset_start, line1offset_end, width, joininglineoffset_start, joininglineoffset_end);

        // Push line 1 onto the output
        output.push_back(line1_start.x);
        output.push_back(line1_start.y);
        output.push_back(line1_end.x);
        output.push_back(line1_end.y);
        output.push_back(line1offset_end.x);
        output.push_back(line1offset_end.y);
        output.push_back(line1offset_start.x);
        output.push_back(line1offset_start.y);

        // Push the new section onto the output
        output.push_back(line1offset_end.x);
        output.push_back(line1offset_end.y);
        output.push_back(line2offset_start.x);
        output.push_back(line2offset_start.y);
        output.push_back(joininglineoffset_start.x);
        output.push_back(joininglineoffset_start.y);
        output.push_back(joininglineoffset_end.x);
        output.push_back(joininglineoffset_end.y);
    }

    // TODO: Push the remaining line 2 on.

    // TODO: Add one last joining piece between the end and the beginning.
}

int main(int argc, char* argv[])
{
    // Describe some input data
    std::vector<std::vector<GLdouble>> input;
    std::vector<GLdouble> val1; val1.push_back(010.0); val1.push_back(010.0); input.push_back(val1);
    std::vector<GLdouble> val2; val2.push_back(050.0); val2.push_back(100.0); input.push_back(val2);
    std::vector<GLdouble> val3; val3.push_back(100.0); val3.push_back(100.0); input.push_back(val3);
    std::vector<GLdouble> val4; val4.push_back(010.0); val4.push_back(010.0); input.push_back(val4);

    // Generate the quads required to outline the shape
    std::vector<GLfloat> output;
    GenerateLinePoly(input, output, 5);

    // Dump the output as pairs of coordinates, grouped into the quads they describe
    cout << setiosflags(ios::fixed) << setprecision(1);
    for(unsigned int i=0; i < output.size(); i++)
    {
       if( (i > 0) && ((i)%2==0) ) { cout << endl; }
       if( (i > 0) && ((i)%8==0) ) { cout << endl; }
       cout << setw(7) << output[i];
    }
    cout << endl;
    return 0;
}

据我所知,..which看起来适用于凸多边形:-)

票数 3
EN

Stack Overflow用户

发布于 2010-06-14 17:28:29

啊,我现在明白了。这是因为你重复使用你的旧顶点,这些顶点不一定与你的新顶点平行。

只需用一个简单的例子来看你的代码,在这里你的输入点会有一个90度的急转弯。旧的顶点将与dir平行,而新的顶点将垂直。如果你在线上有足够近的点,那么你就会得到像你在照片中看到的奇怪的行为。

获得均匀宽度线没有“简单”的解决方案,但如果您一次将线条呈现成一对(即去掉i > 0大小写),情况会更好。这会给你一些丑陋的锐角,但你不会得到任何细线。

票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/3039026

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档