在var $soap_response中有这样的SOAP响应:
<SOAP-ENV:Envelope SOAP-ENV:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/" xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:clr="http://schemas.microsoft.com/soap/encoding/clr/1.0">
<SOAP-ENV:Header>
<h3:__MethodSignature xsi:type="SOAP-ENC:methodSignature" SOAP-ENC:root="1" xmlns:h3="http://schemas.microsoft.com/clr/soap/messageProperties" xmlns:a2="http://schemas.microsoft.com/clr/ns/System.Collections">xsd:string a2:Hashtable</h3:__MethodSignature>
</SOAP-ENV:Header>
<SOAP-ENV:Body>
<i4:ReturnDataSetResponse id="ref-1" xmlns:i4="http://schemas.microsoft.com/clr/nsassem/TOIServerAppl.clsRSchedule/TOIServerAppl">
<return href="#ref-6"/>
</i4:ReturnDataSetResponse>
<a3:DataSet id="ref-6" xmlns:a3="http://schemas.microsoft.com/clr/nsassem/System.Data/System.Data%2C%20Version%3D1.0.5000.0%2C%20Culture%3Dneutral%2C%20PublicKeyToken%3Db77a5c561934e089">
<XmlSchema id="ref-7"><![CDATA[<?xml version="1.0" encoding="utf-16"?>
<xs:schema id="NewDataSet" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
<xs:element name="NewDataSet" msdata:IsDataSet="true">
<xs:complexType>
<xs:choice maxOccurs="unbounded">
<xs:element name="Table">
<xs:complexType>
<xs:sequence>
<xs:element name="id" type="xs:long" msdata:targetNamespace="" minOccurs="0" />
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:choice>
</xs:complexType>
</xs:element>
</xs:schema>]]>
</XmlSchema>
<XmlDiffGram id="ref-8">
<id>4437031</id>
</XmlDiffGram>
</a3:DataSet>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>如何从<id>4437031</id>?中提取id值
simplexml_load_string($soap_response);返回空对象数组。
我已经看到了一些地方,我可能不得不替换所有这些名称空间,使其工作?
发布于 2010-05-28 16:25:12
我能够用SoapClient和__doRequest()函数来完成它。Zend_Soap_client还使用SoapClient。所以我选择了SoapClient。
发布于 2010-05-28 13:18:48
让我为您节省大量的麻烦,并帮助您处理数据集(我假设这是您的web服务,如果不是,我很抱歉)。
不要序列化整个数据集,而是先运行这个函数,然后以字符串的形式返回它。
Public Function FormatDataSet(ByVal ds As DataSet)
Try
Dim xmlstream As New StringBuilder
Dim write As XmlWriter = XmlWriter.Create(xmlstream)
write.WriteProcessingInstruction("xml", "version='1.0' encoding='utf-8'")
ds.WriteXml(write)
Return xmlstream.ToString()
Catch ex As Exception
Return ex.Message
End Try
End Function这将去掉.NET的模式,并为您提供轻松解析的XML (即使是SimpleXML也能够解析它)。你需要System.Text和System.Xml
https://stackoverflow.com/questions/2927849
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