使用tr1::regex时链接器错误

Question

我有一个使用tr1::regex的程序，它在编译时会给我提供非常冗长的链接器错误。

以下是我的头文件MapObject.hpp：

#include <iostream>
#include <string>
#include <tr1/regex>
#include "phBaseObject.hpp"
using std::string;

namespace phObject
{
    class MapObject: public phBaseObject
    {
        private:
            string color;  // must be a hex string represented as "#XXXXXX"
            static const std::tr1::regex colorRX;  // enforces the rule above
        public:
            void setColor(const string&);
        (...)
    };
}

以下是我的实现：

#include <iostream>
#include <string>
#include <tr1/regex>
#include "MapObject.hpp"
using namespace std;


namespace phObject
{
    const tr1::regex MapObject::colorRX("#[a-fA-F0-9]{6}");

    void MapObject::setColor(const string& c)
    {
        if(tr1::regex_match(c.begin(), c.end(), colorRX))
        {
            color = c;
        }
        else cerr << "Invalid color assignment (" << c << ")" << endl;
     }

     (...)
}

现在说的是错误：

max@max-desktop:~/Desktop/Development/CppPartyHack/PartyHack/lib$ g++ -Wall -std=c++0x MapObject.cpp /tmp/cce5gojG.o:在函数std::tr1::basic_regex<char, std::tr1::regex_traits<char> >::basic_regex(char const*, unsigned int)': MapObject.cpp:(.text._ZNSt3tr111basic_regexIcNS_12regex_traitsIcEEEC1EPKcj[std::tr1::basic_regex<char, std::tr1::regex_traits<char> >::basic_regex(char const*, unsigned int)]+0x61): undefined reference tostd::tr1::basic_regex >：：_M_compile()中 /tmp/cce5gojG.o:函数bool std::tr1::regex_match<__gnu_cxx::__normal_iterator<char const*, std::basic_string<char, std::char_traits<char>, std::allocator<char> > >, char, std::tr1::regex_traits<char> >(__gnu_cxx::__normal_iterator<char const*, std::basic_string<char, std::char_traits<char>, std::allocator<char> > >, __gnu_cxx::__normal_iterator<char const*, std::basic_string<char, std::char_traits<char>, std::allocator<char> > >, std::tr1::basic_regex<char, std::tr1::regex_traits<char> > const&, std::bitset<11u>)': > >，std::tr1::regex_match<__gnu_cxx::__normal_iterator，：：MapObject.cpp:(.text._ZNSt3tr111regex_matchIN9__gnu_cxx17__normal_iteratorIPKcSsEEcNS_12regex_traitsIcEEEEbT_S8_RKNS_11basic_regexIT0_T1_EESt6bitsetILj11EE[bool std::tr1::regex_match<__gnu_cxx::__normal_iterator<char const*, std::basic_string<char, std::char_traits<char>, std::allocator<char> > >, char, std::tr1::regex_traits<char> >(__gnu_cxx::__normal_iterator<char const*, std::basic_string<char, std::char_traits<char>, std::allocator<char> > >, __gnu_cxx::__normal_iterator<char const*, std::basic_string<char, std::char_traits<char>, std::allocator<char> > >, std::tr1::basic_regex<char, std::tr1::regex_traits<char> > const&, std::bitset<11u>)]+0x53): undefined reference to> >(__gnu_cxx::__normal_iterator，std：：MapObject.cpp:(.text._ZNSt3tr111regex_matchIN9__gnu_cxx17__normal_iteratorIPKcSsEEcNS_12regex_traitsIcEEEEbT_S8_RKNS_11basic_regexIT0_T1_EESt6bitsetILj11EE[bool std::tr1::regex_match<__gnu_cxx::__normal_iterator<char const*, std::basic_string<char, std::char_traits<char>, std::allocator<char> > >, char, std::tr1::regex_traits<char> >(__gnu_cxx::__normal_iterator<char const*, std::basic_string<char, std::char_traits<char>, std::allocator<char> > >, __gnu_cxx::__normal_iterator<char const*, std::basic_string<char, std::char_traits<char>, std::allocator<char> > >, std::tr1::basic_regex<char, std::tr1::regex_traits<char> > const&, std::bitset<11u>)]+0x53): undefined reference to> >，__gnu_cxx：：__normal_iterator：：分配器>，__gnu_cxx：：__normal_iterator：：分配器> >，分配器，分配器>> >&，std::tr1::basic_regex > const&，std::bitset<11u>)‘ collect2: ld返回1个退出状态

除了刚开始的undefined reference to std::tr1::basic_regex之外，我真的不能对此做出正面或反面判断。有人知道怎么回事吗？

Answer 1

Regex对C++0x的支持是不完整的，TR1不支持Regex，参见C++0x/TR1的实现状态页。

Boost提供了一种替代的TR1实现以及它所基于的原始图书馆。

Answer 2

答案是，即使提供了标头，也没有提供一些方法。

人们可以从Georg的回答中推断出这一点，但在考虑并编码了大约100行之后，假设这个漂亮的库实际上是提供的，人们可能会觉得太累了，没有任何进一步的推论了。