Java HTMLUnit MalformedURLException

Question

我正在尝试从HTMLUnit教程执行这段代码

final WebClient webClient = new WebClient();
final HtmlPage page = webClient.getPage("http://htmlunit.sourceforge.net");

但是在Eclipse中保存它时，我会在第二行中获得MalformedURLException (如果我编译并运行代码，我也会得到它)。有什么问题吗？提亚

PS:我是Java新手

Up:

下面是堆栈跟踪：

Exception in thread "main" java.lang.NoClassDefFoundError: org/apache/commons/httpclient/auth/CredentialsProvider
    at Tester.main(Tester.java:12)
Caused by: java.lang.ClassNotFoundException: org.apache.commons.httpclient.auth.CredentialsProvider
    at java.net.URLClassLoader$1.run(Unknown Source)
    at java.security.AccessController.doPrivileged(Native Method)
    at java.net.URLClassLoader.findClass(Unknown Source)
    at java.lang.ClassLoader.loadClass(Unknown Source)
    at sun.misc.Launcher$AppClassLoader.loadClass(Unknown Source)
    at java.lang.ClassLoader.loadClass(Unknown Source)
    at java.lang.ClassLoader.loadClassInternal(Unknown Source)
    ... 1 more

Answer 1

我在Eclipse3.5中尝试了这一点，它工作正常，并且测试正在通过。我假设您已经在项目中包含了必要的HTMLUnit JAR？我将HTMLUnit lib目录中的所有JAR添加到项目的构建路径中。

另外，您能捕获异常并在这里发布堆栈跟踪吗？

try {
  final WebClient webClient = new WebClient();
  final HtmlPage page = webClient.getPage("http://htmlunit.sourceforge.net");
  assertEquals("HtmlUnit - Welcome to HtmlUnit", page.getTitleText());
}
catch (Exception e) {
  e.printStackTrace();
}

Answer 2

package com.project.test;

import java.io.IOException;
import java.net.MalformedURLException;

import com.gargoylesoftware.htmlunit.FailingHttpStatusCodeException;
import com.gargoylesoftware.htmlunit.WebClient;
import com.gargoylesoftware.htmlunit.html.HtmlPage;



public class Practice1 {

    public static void main(String[] args) {

         final WebClient webClient = new WebClient();
            HtmlPage page;
            try {
                page =  (HtmlPage) webClient.getPage("http://htmlunit.sourceforge.net");
                 System.out.println("Title="+ page.getTitleText());
            } catch (FailingHttpStatusCodeException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (MalformedURLException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }




    }
}

Answer 3

因为在你的堆叠痕迹里

Caused by: java.lang.ClassNotFoundException: org.apache.commons.httpclient.auth.CredentialsProvider

这不是格式错误的URL异常。

作为org.apache.commons.httpclient.auth.CredentialsProvider，经JARFinder证实类应该来自commons 3.*..jar。因此，问题的原因必须是您的类路径中没有通用的HTTPClient 3.x JAR。