所以我在玩没有堆栈的python,编写一个非常简单的very服务器来教自己用微线程/tasklet编程。但是现在我的问题是,当我在apache上运行类似ab -n 100000 -c 50 http://192.168.0.192/ (100 k请求,50并发)的东西时,我得到了6k req/s这样的东西,第二次运行它时,我得到了5.5k,第三次,第四次,4.5k等等,直到100 req/s或其他东西。
不过,当我重新启动python脚本时,问题就消失了。
现在我的问题是为什么?我忘了删除任务了吗?我已经检查了stackless.getruncount() (由于某种原因,它似乎总是返回1 ),所以似乎不会出现任何挂起的线程吗?我尝试过在所有已完成的任务上调用.kill(),但都没有帮助。我就是搞不懂这件事。
import socket
import select
import stackless
import time
class socket_wrapper(object):
def __init__(self, sock, sockets):
super(socket_wrapper, self).__init__()
self.sock = sock
self.fileno = sock.fileno
self.sockets_list = sockets
self.channel = stackless.channel()
self.writable = False
self.error = False
def remove(self):
self.sock.close()
self.sockets_list.remove(self)
def send(self, data):
self.sock.send(data)
def push(self, bytes):
self.channel.send(self.sock.recv(bytes))
def stackless_accept(accept, handler, recv_size=1024, timeout=0):
sockets = [accept]
while True:
read, write, error = select.select(sockets, sockets, sockets, timeout)
for sock in read:
if sock is accept:
# Accept socket and create wrapper
sock = socket_wrapper(sock.accept()[0], sockets)
# Create tasklett for this connection
tasklet = stackless.tasklet(handler)
tasklet.setup(sock)
# Store socket
sockets.append(sock)
else:
# Send data to handler
sock.push(recv_size)
# Tag all writable sockets
for sock in write:
if sock is not accept:
sock.writable = True
# Tag all faulty sockets
for sock in error:
if sock is not accept:
sock.error = True
else:
pass # should do something here if the main socket is faulty
timeout = 0 if socket else 1
stackless.schedule()
def simple_handler(tsock):
data = ""
while data[-4:] != "\r\n\r\n":
data += tsock.channel.receive()
while not tsock.writable and not tsock.error:
stackless.schedule()
if not tsock.error:
tsock.send("HTTP/1.1 200 OK\r\nContent-length: 8\r\n\r\nHi there")
tsock.remove()
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
sock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
sock.bind(("192.168.0.192", 8000))
sock.listen(5)
stackless.tasklet(stackless_accept)(sock, simple_handler)
stackless.run()发布于 2009-02-16 22:52:41
两件事。
首先,请以大写字母开头的类名。它更传统,更容易阅读。
更重要的是,在stackless_accept函数中,您积累了一个名为sockets的Sock对象的list。这个列表似乎在无止境地增长。是的,您有一个remove,但是它并不总是被调用。如果套接字得到一个错误,那么它似乎将永远留在集合中。
https://stackoverflow.com/questions/554805
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