我正在执行一项任务,在该任务中,我必须使用测试数据评估基于RMSE (均方误差)的预测模型。我已经建立了一个线性回归模型来预测葡萄酒质量(数字),使用所有可用的预测变量,基于列车数据。下面是我的当前代码。完全错误是“”错误:列i* regression1 = predict(regression1, newdata = my_type_test)**. x不适用于类"c('double',‘数值’)“**对象的”预测“方法的问题
install.packages("rsample")
library(rsample)
my_type_split <- initial_split(my_type, prop = 0.7)
my_type_train <- training(my_type_split)
my_type_test <- testing(my_type_split)
my_type_train
regression1 <- lm(formula = quality ~ fixed.acidity + volatile.acidity + citric.acid + chlorides + free.sulfur.dioxide + total.sulfur.dioxide +
density + pH + sulphates + alcohol, data = my_type_train)
summary(regression1)
regression1
install.packages("caret")
library(caret)
install.packages("yardstick")
library(yardstick)
library(tidyverse)
my_type_test <- my_type_test %>%
mutate(regression1 = predict(regression1, newdata = my_type_test)) %>%
rmse(my_type_test, price, regression1)发布于 2021-11-13 03:36:30
您所采取的许多步骤可能是不必要的。
--实现相同目标的最小示例:
# Set seed for reproducibility
set.seed(42)
# Take the internal 'mtcars' dataset
data <- mtcars
# Get a random 80/20 split for the number of rows in data
split <- sample(
size = nrow(data),
x = c(TRUE, FALSE),
replace = TRUE,
prob = c(0.2, 0.8)
)
# Split the data into train and test sets
train <- data[split, ]
test <- data[!split, ]
# Train a linear model
fit <- lm(mpg ~ disp + hp + wt + qsec + am + gear, data = train)
# Predict mpg in test set
prediction <- predict(fit, test)结果:
> caret::RMSE(prediction, test$mpg)
[1] 4.116142https://stackoverflow.com/questions/69950840
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