作为乳胶的输出线性模型回归总结

Question

如何打印拟合的线性模型对象的汇总表作为胶乳？

例如，如何打印res作为乳胶码？

# Libraries
import pandas as pd
from linearmodels.panel import PanelOLS
from linearmodels.datasets import wage_panel

# Load silly data
df = wage_panel.load()

# Set indexes
df = df.set_index(['nr','year'])

# Fit silly model
mod = PanelOLS(dependent=df['lwage'], exog=df[['hours','married','educ']], time_effects=True)
res = mod.fit()

# Print results
print(res)
                          PanelOLS Estimation Summary                           
================================================================================
Dep. Variable:                  lwage   R-squared:                        0.0933
Estimator:                   PanelOLS   R-squared (Between):              0.7056
No. Observations:                4360   R-squared (Within):               0.0373
Date:                Thu, Nov 04 2021   R-squared (Overall):              0.6764
Time:                        23:48:11   Log-likelihood                   -3055.6
Cov. Estimator:            Unadjusted                                           
                                        F-statistic:                      149.14
Entities:                         545   P-value                           0.0000
Avg Obs:                       8.0000   Distribution:                  F(3,4349)
Min Obs:                       8.0000                                           
Max Obs:                       8.0000   F-statistic (robust):             149.14
                                        P-value                           0.0000
Time periods:                       8   Distribution:                  F(3,4349)
Avg Obs:                       545.00                                           
Min Obs:                       545.00                                           
Max Obs:                       545.00                                           
                                                                                
                             Parameter Estimates                              
==============================================================================
            Parameter  Std. Err.     T-stat    P-value    Lower CI    Upper CI
------------------------------------------------------------------------------
hours      -7.571e-05  1.357e-05    -5.5805     0.0000     -0.0001  -4.911e-05
married        0.1573     0.0157     10.017     0.0000      0.1265      0.1881
educ           0.0765     0.0042     18.048     0.0000      0.0682      0.0848
==============================================================================

F-test for Poolability: 41.795
P-value: 0.0000
Distribution: F(7,4349)

Included effects: Time

Answer 1

您可以使用summary属性来完成这一任务。请注意，您必须在Latex中使用booktabs包。

print(res.summary.as_latex())

其中的指纹：

\begin{center} \begin{tabular}{lclc} \toprule \textbf{Dep。变量：}& \textbf{ R-平方：}& 0.0933 \ \textbf{估计：}& PanelOLS &\textbf{R-平方(介于)：}& 0.7056 \textbf{No.观察：}& 4360 & \textbf{ R-平方(在)：}

& 0.0373 \ \textbf{日期：}和清华，11月04 2021和\textbf{ R-平方(总体)：}和0.6764 \textbf{时间：}& 23:50:24和\textbf{Log-可能}& -3055.6 \ \textbf{Cov。估计量：}&未调整& \textbf{ }&

\ \textbf{}和& \textbf{ F-统计量：}& 149.14 \\textbf{实体：}

& 545 & \textbf{ P}和0.0000 \ \textbf{Avg：}和8.0000 & \textbf{分发：}& F(3,4349) \textbf{Min Obs:}

& 8.0000 & \textbf{ }&

\ \textbf{Max Obs:} & 8.0000 & \textbf{ F-统计量(稳健)：}& 149.14 \ \textbf{}

& \textbf{ P-值}& 0.0000 \ \textbf{时间段：}&8&\textbf{分发：}& F(3,4349) \ \textbf{Avg Obs:}

& 545.00 & \textbf{ }&

\ \textbf{Min Obs:} & 545.00 & \textbf{

}&\ \textbf{Max Obs:} & 545.00

& \textbf{}和\ \textbf{ }

&& \textbf{ }&

\\底规则\结束{tabular} \begin{tabular}{lcccccc} &\textbf{textbf}和\textbf{Std。Err.}和textbf{textbf}和\textbf{P-值}和\textbf{低CI}和\textbf{上CI} \ \midrule \textbf{小时}& -7.571e-05和1.357e-05 & -5.5805和0.0000 &0.0001&

-4.911e-05 \\textbf{已往}& 0.1573 & 0.0157和10.017 & 0.0000 & 0.1265 &

0.1881 \ \textbf{educ} & 0.0765 & 0.0042和18.048 & 0.0000 & 0.0682 &

0.0848 \\底规则\结束{表格}%\标题{PanelOLS估计摘要}\\end{中心}

Poolability测试: 41.795 \newline P-值: 0.0000 \newline分布: F(7,4349) \newline \newline包含的效果: Time