有一个包含以下数据的文件:
样本:
id|mdl_name|mdl_tagid|mdl_brnchcd|mdls_mktvl
NoData|\N|6ypXQwLw8H9svA|04271|NoData
NoData|\N|7MFzlQriUjohVg|60475|NoData
NoData|\N|8AtEVeaU3fiK5w|91305|NULL
NoData|\N|AA3B5BNqNTokWw|87818|NoData
NoData|\N|CG79LhAgIeBkPw|80199|NULL使用sed替换NoData、NULL和\N
sed -i "s/\\\\\N//g" samplefile
sed -i "s/\x0//g" samplefile
sed -i "s/NoData//g" samplefile实际结果:
id|mdl_name|mdl_tagid|mdl_brnchcd|mdls_mktvl
NoData|\N|6ypXQwLw8H9svA|04271|NoData
NoData|\N|7MFzlQriUjohVg|60475|NoData
NoData|\N|8AtEVeaU3fiK5w|91305|NULL
NoData|\N|AA3B5BNqNTokWw|87818|NoData
NoData|\N|CG79LhAgIeBkPw|80199|NULL预期结果:
id|mdl_name|mdl_tagid|mdl_brnchcd|mdls_mktvl
||6ypXQwLw8H9svA|04271|
||7MFzlQriUjohVg|60475|
||8AtEVeaU3fiK5w|91305|
||AA3B5BNqNTokWw|87818|
||CG79LhAgIeBkPw|80199|在sed命令中没有得到它没有产生预期结果的错误或缺失的内容。
执行建议后,根据测试结果进行更新:
sed -Ei 's/\\N|NULL|NoData//g' samplefile
CG79LhAgIeBkPw|80199 6ypXqwLw8H9svA=04271 7 7MFzlQriUjohVg=60475 8 AtEVeaU3fiK5w/91305 AA3B5BNqNTokWw-87818 id|mdl_name|mdl_tagid|mdl_brnchcd|mdls_mktvl
awk 'BEGIN{FS=OFS="|"} NR>1{$1=$2=$5=""} 1' samplefile
CG79LhAgIeBkPw|80199 6ypXqwLw8H9svA=04271 7 7MFzlQriUjohVg=60475 8 AtEVeaU3fiK5w/91305 AA3B5BNqNTokWw-87818 id|mdl_name|mdl_tagid|mdl_brnchcd|mdls_mktvl
不过,这并不符合预期的结果。是否有办法保留分隔符并用一个空格替换值?
发布于 2021-10-24 08:41:19
从@EdMorton注释中测试代码Suggestion_2,在GNU awk中获取expected result
awk 'BEGIN{FS=OFS="|"} NR>1{$1=$2=$5=""} 1' file id|mdl_name|mdl_tagid|mdl_brnchcd|mdls_mktvl
||6ypXQwLw8H9svA|04271|
||7MFzlQriUjohVg|60475|
||8AtEVeaU3fiK5w|91305|
||AA3B5BNqNTokWw|87818|
||CG79LhAgIeBkPw|80199|GNU awk版本:
awk --version
GNU Awk 5.1.0, API: 3.0 (GNU MPFR 4.1.0, GNU MP 6.2.1)
....与@jthill注释中的sed的结果相同:
sed -E 's/(\\N|NULL|NoData)//g' file id|mdl_name|mdl_tagid|mdl_brnchcd|mdls_mktvl
||6ypXQwLw8H9svA|04271|
||7MFzlQriUjohVg|60475|
||8AtEVeaU3fiK5w|91305|
||AA3B5BNqNTokWw|87818|
||CG79LhAgIeBkPw|80199|https://stackoverflow.com/questions/69691605
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