我试着在歌曲和专辑之间建立一个联系。每首歌可以出现在一个或多个专辑上,每个专辑可以包含一首或多首歌曲。我决定使用GRDB作为我的数据库解决方案,但在这个问题上我陷入了困境。
我尝试过的是:正如文档所示,我创建了一个passport结构,如下所示:
public struct AlbumPassport: TableRecord {
static let track = belongsTo(SPTTrack.self)
static let album = belongsTo(SPTAlbum.self)
}然后在SPTTrack类中:
public static let passports = hasMany(AlbumPassport.self)
public static let albums = hasMany(SPTAlbum.self, through: passports, using: AlbumPassport.album)在SPTAlbum课程中:
public static let passports = hasMany(AlbumPassport.self)
public static let tracks = hasMany(SPTTrack.self, through: passports, using: AlbumPassport.track)我在文档中找不到一个很好的例子,说明如何使用这些关联构建请求。在SPTAlbum类中,我添加了linkedTracks属性
public var linkedTracks: QueryInterfaceRequest<SPTTrack> {
request(for: Self.tracks)
}然后在我的数据库管理器中:
func fetchTracks(for album: SPTAlbum) -> [SPTTrack] {
do {
return try dbQueue.read { db in
try album.linkedTracks.fetchAll(db)
}
} catch {
print(error)
}
return []
}我搞错了:
SQLite错误1:没有这样的表: albumPassport
这是非常不言自明的,但我不知道应该如何在何处为AlbumPassport结构创建表,以及是否需要采取任何其他步骤来实际填充此表中的相册/曲目连接。
两个SPTTrack/SPTAlbum都有一个名为id的字段,该字段在第一次迁移期间被设置为primaryKey。
发布于 2021-09-29 04:15:17
你的协会没有问题。所有hasMany()和belongsTo()都是正确的。您所得到的错误告诉我,您的数据库设置有问题(您的问题中没有包含)。
以下是我将如何实现它:

import GRDB
struct Album: Codable, Hashable, FetchableRecord, MutablePersistableRecord {
mutating func didInsert(with rowID: Int64, for column: String?) { id = rowID }
var id: Int64?
var name: String
static let passports = hasMany(AlbumPassport.self)
static let tracks = hasMany(Track.self, through: passports, using: AlbumPassport.track)
}
struct Track: Codable, Hashable, FetchableRecord, MutablePersistableRecord {
mutating func didInsert(with rowID: Int64, for column: String?) { id = rowID }
var id: Int64?
var name: String
static let passports = hasMany(AlbumPassport.self)
static let albums = hasMany(Album.self, through: passports, using: AlbumPassport.album)
}
struct AlbumPassport: Codable, Hashable, FetchableRecord, PersistableRecord {
let track: Int64
let album: Int64
static let track = belongsTo(Track.self)
static let album = belongsTo(Album.self)
}
let queue = DatabaseQueue()
try queue.write { db in
try db.create(table: "album") { t in
t.autoIncrementedPrimaryKey("id")
t.column("name", .text).notNull()
}
try db.create(table: "track") { t in
t.autoIncrementedPrimaryKey("id")
t.column("name", .text).notNull()
}
try db.create(table: "albumPassport") { t in
t.column("track", .integer).notNull().indexed().references("track")
t.column("album", .integer).notNull().indexed().references("album")
t.primaryKey(["track", "album"])
}
// Testing real data from https://music.apple.com/de/artist/yiruma/73406786
var solo = Album(name: "SOLO")
try solo.insert(db)
var sometimes = Track(name: "Sometimes Someone")
try sometimes.insert(db)
try AlbumPassport(track: sometimes.id!, album: solo.id!).insert(db)
var destiny = Track(name: "Destiny Of Love")
try destiny.insert(db)
try AlbumPassport(track: destiny.id!, album: solo.id!).insert(db)
var bestOf = Album(name: "Best of Yiroma")
try bestOf.insert(db)
var poem = Track(name: "Poem")
try poem.insert(db)
try AlbumPassport(track: poem.id!, album: bestOf.id!).insert(db)
var river = Track(name: "River Flows In You")
try river.insert(db)
try AlbumPassport(track: river.id!, album: bestOf.id!).insert(db)
}
// Fetch all albums and their tracks
try queue.read { db in
struct AlbumInfo: FetchableRecord, Decodable, CustomStringConvertible {
var album: Album
var tracks: Set<Track>
var description: String { "\(album.name) → \(tracks.map(\.name))" }
}
let request = Album.including(all: Album.tracks)
let result = try AlbumInfo.fetchAll(db, request)
print(result)
// > [SOLO → ["Sometimes Someone", "Destiny Of Love"], Best of Yiroma → ["River Flows In You", "Poem"]]
}有关另一个代码示例,请参见我的回答 of 多对多关系,其中一个实体具有相同类型的多个属性。。
https://stackoverflow.com/questions/69296355
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