从HttpRequestMessage异常访问GetAsync

Question

如何从HttpRequestMessage异常获取GetAsync：

try {
  using var responseMsg = await httpClient.GetAsync(requestUri);
  var requestMessage = responseMsg.RequestMessage;

} catch (Exception ex) {
  var requestMessage = ????
  Log(requestMessage.Headers);
}

Answer 1

您可以在尝试之前手动创建HttpRequestMessage，然后使用HttpClient发送它：

HttpRequestMessage httpRequest = new HttpRequestMessage
{
    Method = HttpMethod.Get,
    RequestUri = uri
};

try
{
    HttpClient client = new HttpClient();
    var response = await client.SendAsync(httpRequest);
}
catch(Exception ex)
{
    var x = httpRequest.Headers;
}

在try<->catch之外创建的对象可以在每个部分中使用。