如何将javascript中的[some_text](some_text)替换为[[some_text]](some_text)

Question

注意，我只需要对符合这个模式的单词进行替换，@[some_text](some_text)。

以下是一些输入和预期输出的示例：

输入：thanks @[said](said_Id) for helping me with [PCM]

输出：thanks @[[said]](said_Id) for helping me with [PCM]

输入：thanks @[said](said_Id) @[john](jhon_doe_id)

输出：thanks @[[said]](said_Id) @[[jhon]](jhon_does_id)

输入：thanks @[said](said_Id) some text @[john](jhon_doe_id) some text @[alex](alex-id)

输出：thanks @[[said]](said_Id) @[[jhon]](jhon_does_id) some text @[[alex]](alex-id)

Answer 1

input.replace(/@\[(.*?)\](\(.*?\))/g, '@[[$1]]$2')

霸王龙爆发了：

@\[(.*?)\]  <-- match the pattern @[anything]  
(\(.*?\))  <--- match (anything)
/@\[(.*?)\](\(.*?\))/g  <--- globally match all @[anything](anything)

替换部分从搜索中获取括号中的主题，并按外观顺序替换它们($1，$2) --在本例中，它正在重建它在搜索@[[$1]]$2中找到的字符串

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const fix = input => input.replace(/@\[(.*?)\](\(.*?\))/g, '@[[$1]]$2');
console.log(fix(`thanks @[said](said_Id) for helping me with [PCM]`))
console.log(fix(`thanks @[said](said_Id) some text @[john](jhon_doe_id) some text @[alex](alex-id)`))

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