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社区首页 >问答首页 >以内存高效的方式进行内容分析，但有一些异常

问以内存高效的方式进行内容分析，但有一些异常
EN

Stack Overflow用户
提问于 2021-07-05 15:09:17
回答 1查看 57关注 0票数 0

下面是我的示例数据，以及我尝试使用xpath的内容。这里，我的目标是通过排除script, style标记和少数类noparse, generic来修改html中的所有文本。

下面是指向我的示例输入和php脚本的链接：

https://3v4l.org/urIBl#v7.4.21

有人能向正确的道路展示一些光明吗？

My输入：

代码语言：javascript
复制
$html=<<<doc
<html>
<head>
<title>My page</title>
<script>
//<![CDATA[
$(function(){
   $('.ajax').trigger('change');
})
//]]></script>
<style>ul li ol li{color;red;}</style>
</head>
<body>
<div>
<ul>
    <li>Languages
        <ol>
        <li>PHP</li>
        <li class='noparse'>C++</li>
        </ol>
    </li>
</ul>
<span>inline text</span>
<p class="generic">some long text data</p>
<a href="https://stackoverflow.com" title="resource hub">Stack Overflow</a>
<a href="https://google.nl" title="Google" class="inline-a noparse otherclass">Google</a>
<img class="img-responsive parse round red" src="" alt="round image" />
<img class="img-responsive noparse round red" src="" alt="square image" />
</div>
</body>
</html>
doc;

，这就是我尝试过的，

代码语言：javascript
复制
<?php


libxml_use_internal_errors(true);
$dom = new DOMDocument();
$dom->preserveWhiteSpace = false;
$dom->loadHTML($html, LIBXML_SCHEMA_CREATE);
$xpath = new DOMXPath($dom);

$exclude='.generic,.noparse';

foreach ($xpath->query("//*/text()[not(@class='$exclude')]|//a/@title[not(@class='$exclude')]|//img/@alt[not(@class='$exclude')]")  as $node)
{ 
  $node->textContent=$node->textContent.' powered by sometext';
} 

echo $dom->saveHTML();

?>

预期结果：

代码语言：javascript
复制
<html>
<head>
<title>My page powered by sometext</title>
<script>
//<![CDATA[
$(function(){
   $('.ajax').trigger('change');
})
//]]></script>
<style>ul li ol li{color;red;}</style>
</head>
<body>
<div>
<ul>
    <li>Languages  powered by sometext
        <ol>
        <li>PHP  powered by sometext</li>
        <li class='noparse'>C++</li>
        </ol>
    </li>
</ul>
<span>inline text  powered by sometext</span>
<p class="generic">some long text data</p>
<a href="https://stackoverflow.com" title="resource hub  powered by sometext">Stack Overflow  powered by sometext</a>
<a href="https://google.nl" title="Google" class="inline-a noparse otherclass">Google</a>
<img class="img-responsive parse round red" src="" alt="round image  powered by sometext" />
<img class="img-responsive noparse round red" src="" alt="square image" />
</div>
</body>
</html>

--这是我从脚本中得到的(这不是期望的输出)

代码语言：javascript
复制
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html>
 powered by sometext<head>
 powered by sometext<title>My page powered by sometext</title>
 powered by sometext<script>
//<![CDATA[

$(function(){
   $('.ajax').trigger('change');
})
//]]> powered by sometext</script>
 powered by sometext<style>ul li ol li{color;red;} powered by sometext</style>
 powered by sometext</head>
 powered by sometext<body>
 powered by sometext<div>
 powered by sometext<ul>
     powered by sometext<li>Languages
         powered by sometext<ol>
         powered by sometext<li>PHP powered by sometext</li>
         powered by sometext<li class="noparse">C++ powered by sometext</li>
         powered by sometext</ol>
     powered by sometext</li>
 powered by sometext</ul>
 powered by sometext<span>inline text powered by sometext</span>
 powered by sometext<p class="generic">some long text data powered by sometext</p>
 powered by sometext<a href="https://stackoverflow.com" title>Stack Overflow powered by sometext</a>
 powered by sometext<a href="https://google.nl" title class="inline-a noparse otherclass">Google powered by sometext</a>
 powered by sometext<img class="img-responsive parse round red" src="" alt>
 powered by sometext<img class="img-responsive noparse round red" src="" alt>
 powered by sometext</div>
 powered by sometext</body>
 powered by sometext</html>
domxpath
php-7.4
php
domdocument
simple-html-dom
EN

回答 1

Stack Overflow用户

发布于 2021-07-05 17:19:57

编辑的

下面是编辑的脚本：

备注：

  1. 您有以下代码。我不知道这是什么。我试图在网上搜索，但没有得到任何信息。因为语法：

，所以解析和输出出错了。

代码语言：javascript
复制
  //<![CDATA[
  <script>

如果您知道它是什么，但不知道如何修复解析，请回答。

  1. 我不确定您是否也想要更改属性。我看到您的预期输出有一些不一致之处，所以我没有花更多时间修复属性方面的问题:首先，a href没有排除类，但是它的类属性预计会改变。而对于img，则不是。

代码语言：javascript
复制
<a href="https://google.nl" title="Google" class="inline-a noparse otherclass">Google</a>
<img class="img-responsive parse round red" src="" alt="round image  powered by sometext" />
代码语言：javascript
复制
<?php

  $html=<<<doc
  <html>
  <head>
  <title>My page</title>
  //<![CDATA[
  <script>
  $(function(){
     $('.ajax').trigger('change');
  })
  //]]></script>
  <style>ul li ol li{color;red;}</style>
  </head>
  <body>
  <div>
  <ul>
      <li>Languages
          <ol>
          <li>PHP</li>
          <li class='noparse'>C++</li>
          </ol>
      </li>
  </ul>
  <span>inline text</span>
  <p class="generic">some long text data</p>
  <a href="https://stackoverflow.com" title="resource hub">Stack Overflow</a>
  <a href="https://google.nl" title="Google" class="inline-a noparse otherclass">Google</a>
  <img class="img-responsive parse round red" src="" alt="round image" />
  <img class="img-responsive noparse round red" src="" alt="square image" />
  </div>
  </body>
  </html>
  doc;

  libxml_use_internal_errors(true);
  $dom = new DOMDocument();
  $dom->preserveWhiteSpace = false;
  $dom->loadHTML($html, LIBXML_SCHEMA_CREATE);
  $xpath = new DOMXPath($dom);

  $excluded_tags = array("script", "style");
  $excluded_classes=array('generic', 'noparse');

  $nodes = $xpath->query("//*");
  foreach ($nodes as $node)
  {
  
     if ($node && $node->nodeName) {
        if (!in_array($node->nodeName, $excluded_tags)) {
           if (0 < $node->childNodes->count() && "#text" === $node->childNodes[0]->nodeName) {
             if (!$node->hasAttribute('class') || !in_array($node->getAttribute('class'), $excluded_classes)) {
                $nodeValue = preg_replace('/\s+$/', '', $node->childNodes[0]->nodeValue);
                if (0 != strlen($nodeValue)) {
                  $node->childNodes[0]->nodeValue = $node->childNodes[0]->nodeValue.' powered by sometext';
                  //echo "Node Name: ", $node->nodeName, " Node Child Count: ", $node->childNodes->count(), " Node Child Name: ", $node->childNodes[0]->nodeName, " Node Child Value: ", preg_replace('/\s+$/', '', $node->childNodes[0]->nodeValue), PHP_EOL;
                  
                   if ($node->attributes) {
                      foreach ($node->attributes as $attribute) {
                        if ('href' != $attribute->nodeName) {
                           $attribute->nodeValue = $attribute->nodeValue.' powered by sometext';
                        }
                      }
                   }
                }
             }
           }
        }
     }
  } 

  echo $dom->saveHTML();

输出

代码语言：javascript
复制
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html>
<head>
<title>My page powered by sometext</title></head><body><p>
//
$(function(){
   $('.ajax').trigger('change');
})
//]]&gt;
 powered by sometext<style>ul li ol li{color;red;}</style>

</p>
<div>
<ul>
    <li>Languages
         powered by sometext<ol>
        <li>PHP powered by sometext</li>
        <li class="noparse">C++</li>
        </ol>
    </li>
</ul>
<span>inline text powered by sometext</span>
<p class="generic">some long text data</p>
<a href="https://stackoverflow.com" title="resource hub powered by sometext">Stack Overflow powered by sometext</a>
<a href="https://google.nl" title="Google powered by sometext" class="inline-a noparse otherclass powered by sometext">Google powered by sometext</a>
<img class="img-responsive parse round red" src="" alt="round image">
<img class="img-responsive noparse round red" src="" alt="square image">
</div>

</body></html>

图像

​

​

票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：

https://stackoverflow.com/questions/68258380

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