Php使用来自json数据结构的move_uploaded_file()

Question

我通过json角请求来增强数据，但是我没有($_FILES‘’name‘)格式，所以我不能使用move_uploaded_file()

WEB数据

avatar  {
contentType "application/pdf"
data    "data:application/pdf;base64,JVBERi0xLjcNCiW1tbW1DQoxIDAgb2JqDQo8PC9UeXBlL0NhdGFsb2cvUGFnZXMgMiAwIFIvTGFuZyhlcy1DTykgL1N0cnVjdFRyZWVSb290IDMxIDAgUi9NYXJrSW5mbzw8L01hcmtlZCB0cnVlPj4vTWV0YWRhdGEgMjMyIDAgUi9WaWV3ZXJQcmVmZXJlbmNlcyAyMzMgMCBSPj4NCmVuZG9iag0KMiAwIG9iag0KPDwvVHlwZS9QYWdlcy9Db3VudCA0L0tpZHNbIDMgMCBSIDE3IDAgUiAyMiAwIFIgMjYgMCBSXSA+Pg0KZW5kb2JqDQozIDAgb2JqDQo8PC9UeXBlL1BhZ2UvUGFyZW50IDIgMCBSL1Jlc291cmNlczw8L1hPYmplY3Q8PC9JbWFnZTUgNSAwIFIvSW1hZ2U3IDcgMCBSPj4vRXh0R1N0YXRlPDwvR1M2IDYgMCBSL0dTMTAgMTAgMCB…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"
filename    "manualversion1.pdf"
size    363915
}
descripPretensiones "gsdfgfgdfdgf"
fecFin  "2021-06-17T05:00:00.000Z"

在这部分，我没有任何的响应尝试捕捉，没有错误o问题，但我的文件从来没有上传到我的文件夹。

    $data = json_decode(file_get_contents('php://input'), true);
    $fileName= $data["avatar"]["filename"];
    
    try {
        if(move_uploaded_file(base64_decode($data['avatar']['data']), $finalRute)){
                echo 'file update';
        }
    } catch (Exception $e) {
        echo 'Excepción capturada: ',  $e->getMessage(), "\n";
    } 

Answer 1

内存中的数据编码为base64。您必须做一些事情来将数据写入磁盘，而不是使用move_uploaded_file，后者旨在将磁盘上的临时文件移动到不同的位置。最直截了当的是目录。

类似于：

file_put_contents($finalRute, base64_decode(explode(',', $data['avatar']['data'])[1]));

根据阿布拉卡德弗关于省略data:application/pdf;base64,的评论编辑的代码