我刚开始使用"@reduxjs/toolkit“(版本"^1.5.1")。
我正在尝试从状态数组(roundScore)中删除一个对象。这通常是使用filter()非常简单的事情。因为某种原因,这不管用,我也搞不懂原因。这是我的密码:
减速器片:
import { createSlice } from "@reduxjs/toolkit";
export const roundScoreSlice = createSlice({
name: "roundScore",
initialState: {
roundScore: [],
},
reducers: {
deleteArrow: (state, action) => {
console.log(`action.payload = ${action.payload}`); // returns correct id
state.roundScore.filter((arrow) => arrow.id !== action.payload);
},
},
});
export const { deleteArrow } = roundScoreSlice.actions;
export default roundScoreSlice.reducer;反应成分:
import React from "react";
import styled from "styled-components";
import { motion } from "framer-motion";
import { useDispatch } from "react-redux";
import { deleteArrow } from "../../redux-reducers/trackSession/roundScoreSlice";
export default function InputtedScore({
arrowScore,
id,
initial,
animate,
variants,
}) {
const dispatch = useDispatch();
const applyStyling = () => {
switch (arrowScore) {
case 0:
return "miss";
case 1:
return "white";
case 2:
return "white";
case 3:
return "black";
case 4:
return "black";
case 5:
return "blue";
case 6:
return "blue";
case 7:
return "red";
case 8:
return "red";
case 9:
return "gold";
case 10:
return "gold";
default:
return null;
}
};
return (
<ParentStyled
id={id}
initial={initial}
animate={animate}
variants={variants}
onClick={() => dispatch(deleteArrow(id))}
>
<Circle className={applyStyling()}>
{arrowScore}
<IconStyled>
<IoIosClose />
</IconStyled>
<IoIosClose className="redCross" />
</Circle>
</ParentStyled>
);
}添加2个箭头后的状态如下所示:
roundScore: [
{
id:"e0f225ba-19c2-4fd4-b2bf-1e0aef6ab4e0"
arrowScore:7
},
{
id:"2218385f-b37a-4f2c-a8db-4e7e65846171"
arrowScore:5
}
]我尝试过多种方法。
在dispatch
(state, action) => { /* code */ }中使用带大括号或不带大括号的还原器函数
我错过了什么?我知道这将是一个简单的解决办法,但出于某种原因,它正在逃避我。
任何帮助都是非常感谢的。
发布于 2021-05-07 16:29:38
好的,看起来问题在于filter方法是如何工作的,它返回一个新的数组,并且一个初始的数组不会发生变异(这就是为什么我们以前一直使用过滤器来操作redux状态),在代码中,您也显示了筛选操作的值,而不是分配给状态的任何属性,所以下面的代码应该适合您。
state.roundScore = state.roundScore.filter((arrow) => arrow.id !== action.payload);改变现有数组:
state.roundScore.splice(state.roundScore.findIndex((arrow) => arrow.id === action.payload), 1);发布于 2021-12-22 02:26:43
我们可以跳出框框,从另一个角度来看待它。上面的React组件实际上只是某个父组件的子组件。就我的回答而言,我假设在您的父组件中有某种形式的array.map。
因此,从该代码中,每个数组项都将有一个数组索引。您可以将该索引作为支柱传递给上面的react组件,如下所示:
const InputtedScore = ({ ...all your props, id, inputIndex }) => {
const dispatch = useDispatch();
// Having access to your index from the props, you can even
// find the item corresponding to that index
const inputAtIndex_ = useSelector(state => state.input[inputIndex])
const applyStyling = () => {
switch (arrowScore) {
...your style logic
}
};
return (
// you can send that index as a payload to the reducer function
<ParentStyled id={id} onClick={() => dispatch(deleteArrow(inputIndex))}
...the rest of your properties >
<Circle className={applyStyling()}>
{arrowScore}
<IconStyled>
<IoIosClose />
</IconStyled>
<IoIosClose className="redCross" />
</Circle>
</ParentStyled>
);
}在通过发送项目的索引作为有效载荷删除删除操作后,您不再需要在还原器中找到该项了:
deleteMeal: (state, action) => {
// you receive you inputIndex from the payload
let { inputIndex } = action.payload;
// and you use it to splice the desired item off the array
state.meals.splice(inputIndex, 1);
...your other logic if any
},发布于 2022-11-23 07:06:14
您需要改变现有的数组。
state.roundScore.splice(state.roundScore.findIndex((arrow) => arrow.id === action.payload), 1);https://stackoverflow.com/questions/67436949
复制相似问题