ORA-00907:缺少右括号
我正在尝试运行代码,并且一直得到正确的括号错误,我检查了整个代码。有人能明白我为什么失败吗?
select * from CUSTOMER_ORDER_JOIN
where
CASE WHEN CF$_ZCOORDINATORID is not null THEN
((TRIM(upper('&Coordinator_ID&')) LIKE upper((select CUSTOMER_ORDER_API.GET_AUTHORIZE_CODE(ORDER_NO) from dual) ))
and (OBJSTATE = (select CUSTOMER_ORDER_LINE_API.FINITE_STATE_ENCODE__('Partially Delivered') from dual)
or OBJSTATE = (select CUSTOMER_ORDER_LINE_API.FINITE_STATE_ENCODE__('Picked') from dual)
or OBJSTATE = (select CUSTOMER_ORDER_LINE_API.FINITE_STATE_ENCODE__('Released') from dual)
or OBJSTATE = (select CUSTOMER_ORDER_LINE_API.FINITE_STATE_ENCODE__('Reserved') from dual)))
ELSE ((TRIM(upper('&Coordinator_ID&')) LIKE upper((select CUSTOMER_ORDER_API.GET_AUTHORIZE_CODE(ORDER_NO) from dual) ) or
TRIM(upper('&Coordinator_ID&')) is not null)
and (OBJSTATE = (select CUSTOMER_ORDER_LINE_API.FINITE_STATE_ENCODE__('Partially Delivered') from dual)
or OBJSTATE = (select CUSTOMER_ORDER_LINE_API.FINITE_STATE_ENCODE__('Picked') from dual)
or OBJSTATE = (select CUSTOMER_ORDER_LINE_API.FINITE_STATE_ENCODE__('Released') from dual)
or OBJSTATE = (select CUSTOMER_ORDER_LINE_API.FINITE_STATE_ENCODE__('Reserved') from dual)))
END发布于 2021-04-15 16:24:23
正如注释中提到的那样,案例表达式的计算结果是一个值,然后您可以使用该值或将其与其他值进行比较。在where子句中,只使用布尔逻辑通常更简单,因此可以删除case表达式;还可以删除大量针对dual的重复和不必要的子查询,以获得以下内容:
select * from CUSTOMER_ORDER_JOIN
where
(
TRIM(upper('&Coordinator_ID&')) LIKE upper(CUSTOMER_ORDER_API.GET_AUTHORIZE_CODE(ORDER_NO))
or (CF$_ZCOORDINATORID is null and TRIM(upper('&Coordinator_ID&')) is not null)
)
and
(
OBJSTATE = CUSTOMER_ORDER_LINE_API.FINITE_STATE_ENCODE__('Partially Delivered')
or OBJSTATE = CUSTOMER_ORDER_LINE_API.FINITE_STATE_ENCODE__('Picked')
or OBJSTATE = CUSTOMER_ORDER_LINE_API.FINITE_STATE_ENCODE__('Released')
or OBJSTATE = CUSTOMER_ORDER_LINE_API.FINITE_STATE_ENCODE__('Reserved')
) 尽管LIKE可能应该是=,而not null检查中的upper()并没有真正做任何事情--但是不能判断其他的是否必要;您可以使用in()来进行OBJSTATE检查。
我相信这与你问题中的说法是一样的。
https://stackoverflow.com/questions/67111274
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