如何从正则表达式中排除括号中的内容

Question

我有一个函数，它把一个表达式或方程分解成个别的术语。

这就是我所拥有的：

​

const terms = equation => {
  equation = equation.replace(/\s/g, '').replace(/(\+\-)/g, '-').split(/(?=[\+\-\=])/g);
  for (var i = 0; i < equation.length; i++) {
    if (equation[i].indexOf('=') != -1) {
      equation[i] = equation[i].replace('=', '');
      equation.splice(i, 0, '=');
    }
  }
  return equation;
}

console.log(terms('2(a+6-2)+3-7 = 5a'));

​

这将记录"2(a", "+6", "-2)", "+3", "-7", "=", "5a"

我要它记录"2(a+6-2)", "+3", "-7", "=", "5a"

如果它在圆括号中，我如何使它在'+'或'-'上不分裂？

Answer 1

感谢谁的评论

最后我用了这个：

​

const terms = equation => equation.replace(/\s/g, '').replace(/(\+\-)/g, '-').match(/\w*\([^)(]+\)|=|[+-]?\s*\w+/g);

console.log(terms("2(a+6-2)+3-7 = 5a"));

​