我使用TF2 (2.3.0) NN逼近函数y,它解决了ODE: y'+3y=0
我定义了剪刀损失类和函数,在这些函数中,我试图将单个输出与单个输入区分开来,因此方程成立,条件是y_true为零:
from tensorflow.keras.losses import Loss
import tensorflow as tf
class CustomLossOde(Loss):
def __init__(self, x, model, name='ode_loss'):
super().__init__(name=name)
self.x = x
self.model = model
def call(self, y_true, y_pred):
with tf.GradientTape() as tape:
tape.watch(self.x)
y_p = self.model(self.x)
dy_dx = tape.gradient(y_p, self.x)
loss = tf.math.reduce_mean(tf.square(dy_dx + 3 * y_pred - y_true))
return loss但是运行以下NN:
import tensorflow as tf
from tensorflow.keras.optimizers import Adam
from tensorflow.keras.models import Model
from tensorflow.keras.layers import Dense
from tensorflow.keras import Input
from custom_loss_ode import CustomLossOde
num_samples = 1024
x_train = 4 * (tf.random.uniform((num_samples, )) - 0.5)
y_train = tf.zeros((num_samples, ))
inputs = Input(shape=(1,))
x = Dense(16, 'tanh')(inputs)
x = Dense(8, 'tanh')(x)
x = Dense(4)(x)
y = Dense(1)(x)
model = Model(inputs=inputs, outputs=y)
loss = CustomLossOde(model.input, model)
model.compile(optimizer=Adam(learning_rate=0.01, beta_1=0.9, beta_2=0.99),loss=loss)
model.run_eagerly = True
model.fit(x_train, y_train, batch_size=16, epochs=30)现在我从财政时代得到0的损失,这是没有任何意义的。
我在函数中同时打印了y_true和y_test,它们看起来还好,所以我怀疑问题是在渐变中,我没有成功地打印。提供任何帮助
发布于 2020-11-25 14:07:23
在这种情况下,用高级Keras定义自定义丢失有点困难。相反,我将从scracth编写培训循环,因为它允许对您可以做的事情进行更细粒度的控制。
我从这两个向导那里得到了灵感:
基本上,我使用的事实是,多个磁带可以无缝交互。我用一种计算损失函数,另一种用来计算要由优化器传播的梯度。
import tensorflow as tf
from tensorflow.keras.optimizers import Adam
from tensorflow.keras.models import Model
from tensorflow.keras.layers import Dense
from tensorflow.keras import Input
num_samples = 1024
x_train = 4 * (tf.random.uniform((num_samples, )) - 0.5)
y_train = tf.zeros((num_samples, ))
inputs = Input(shape=(1,))
x = Dense(16, 'tanh')(inputs)
x = Dense(8, 'tanh')(x)
x = Dense(4)(x)
y = Dense(1)(x)
model = Model(inputs=inputs, outputs=y)
# using the high level tf.data API for data handling
x_train = tf.reshape(x_train,(-1,1))
dataset = tf.data.Dataset.from_tensor_slices((x_train,y_train)).batch(1)
opt = Adam(learning_rate=0.01, beta_1=0.9, beta_2=0.99)
for step, (x,y_true) in enumerate(dataset):
# we need to convert x to a variable if we want the tape to be
# able to compute the gradient according to x
x_variable = tf.Variable(x)
with tf.GradientTape() as model_tape:
with tf.GradientTape() as loss_tape:
loss_tape.watch(x_variable)
y_pred = model(x_variable)
dy_dx = loss_tape.gradient(y_pred, x_variable)
loss = tf.math.reduce_mean(tf.square(dy_dx + 3 * y_pred - y_true))
grad = model_tape.gradient(loss, model.trainable_variables)
opt.apply_gradients(zip(grad, model.trainable_variables))
if step%20==0:
print(f"Step {step}: loss={loss.numpy()}")https://stackoverflow.com/questions/64995683
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